Problem 4
Question
Sketch a graph of the parabola. $$ y^{2}=x $$
Step-by-Step Solution
Verified Answer
The parabola for \( y^2 = x \) opens to the right with the vertex at the origin.
1Step 1: Understand the Equation
The given equation is \( y^2 = x \). This is the equation of a parabola. Parabolas that have the form \( y^2 = 4px \) open sideways, either to the right or left, depending on the sign of \( x \). Here, since it is simply \( y^2 = x \), it resembles \( y^2 = 4px \) with \( 4p = 1 \), which indicates it opens to the right.
2Step 2: Identify Vertex and Orientation
For the given equation \( y^2 = x \), the vertex is at the origin \((0, 0)\). The parabola opens to the right because \( x \) is expressed as \( y^2 \), meaning \( x \) could take positive values when \( y \) is positive or negative.
3Step 3: Find Key Points
To accurately sketch the graph, find a few key points. Choose a few values for \( y \) to solve for \( x \). For \( y = 1 \), \( x = 1^2 = 1 \) gives the point \( (1, 1) \). For \( y = -1 \), \( x = (-1)^2 = 1 \) gives the point \( (1, -1) \). Similarly, for \( y = 2 \) and \( y = -2 \), \( x = 4 \) provides \((4, 2)\) and \((4, -2)\) respectively.
4Step 4: Plot the Points
Using the points \((0, 0), (1, 1), (1, -1), (4, 2), (4, -2)\), plot them on the coordinate plane. These points outline the shape of the parabola that opens to the right. This helps illustrate the curve of the parabola.
5Step 5: Sketch the Parabola
Draw a smooth curve through the plotted points to form the parabola. The parabola should be symmetrical with respect to the x-axis and open to the right, representing the graph of \( y^2 = x \).
Key Concepts
Graph SketchingQuadratic EquationCoordinate Geometry
Graph Sketching
Graph sketching is the process of drawing a graph to visually represent an equation. When working with a parabola, this involves a few steps to ensure accuracy. Start by identifying the vertex, which acts as a reference point for the curve. The vertex of a parabola in the equation form of \( y^2 = x \) is at the origin, \((0, 0)\). From there, choose values to one variable and solve for the other to find key points that lie on the parabola.
- Select values of \( y \) and solve for \( x \).
- Use these points to outline the parabola's trajectory.
- Ensure the curve is smooth and symmetrically drawn around the axis of symmetry.
Quadratic Equation
A quadratic equation is any equation that can be expressed in the form \( ax^2 + bx + c = 0 \). However, when dealing with parabolas like \( y^2 = x \), we notice a deviation from the standard form. In such cases, the equation is not in standard quadratic form but still retains key features of quadratic equations.The equation \( y^2 = x \) focuses on \( y \) as the dependent variable, where \( x \) is expressed in terms of \( y \). This reverses expectations from typical quadratic equations and influences how the graph is sketched.
- A square term allows the equation to form a curve (half of a quadratic).
- The lack of a linear \( y \)-term simplifies the interaction between variables.
- Understanding the sideways opening of such parabolas is crucial when sketching graphs.
Coordinate Geometry
Coordinate geometry, or analytic geometry, involves using algebraic principles to represent geometrical shapes within a coordinate system. Understanding this helps visualize equations like \( y^2 = x \) as geometric curves on a graph.The coordinate plane uses the x-axis and y-axis to create a framework where each point corresponds to an ordered pair \((x, y)\). Parabolas such as \( y^2 = x \) are plotted by identifying key points that satisfy the equation.
- The origin \((0,0)\) is a pivotal point where the parabola's vertex is located.
- Symmetry ensures that points such as \((1,1)\) and \((1,-1)\) maintain balance across the x-axis.
- Plotting helps reveal a clear visual of how the parabola appears on the grid.
Other exercises in this chapter
Problem 3
Sketch a graph of the parabola. $$ y^{2}=-x $$
View solution Problem 4
Graph the ellipse. Label the foci and the endpoints of each axis. $$ x^{2}+\frac{y^{2}}{4}=1 $$
View solution Problem 5
Graph the ellipse. Label the foci and the endpoints of each axis. $$ x^{2}+4 y^{2}=400 $$
View solution Problem 5
Sketch a graph of the parabola. $$ 4 x^{2}=-2 y $$
View solution