Problem 4
Question
\(\lim _{(x, y) \rightarrow(1,2)} \frac{x^{3}-3 x^{2} y+3 x y^{2}-y^{3}}{y-2 x^{2}}\)
Step-by-Step Solution
Verified Answer
The limit is undefined at (1, 2) as the denominator equals zero.
1Step 1: Analyze the Limit
First, we need to determine if the limit is of an indeterminate form. Substitute the point \(x=1, y=2\) into the expression to check if both the numerator and denominator approach zero as \(x
ightarrow 1\) and \(y
ightarrow 2\). We have \(1^3 - 3(1)^2(2) + 3(1)(2)^2 - 2^3 = 1 - 6 + 12 - 8 = -1\) and \(2 - 2(1)^2 = 0\). Although the numerator does not approach zero at \(x=1, y=2\), the denominator does. Thus, the expression does not result in a \(\frac{0}{0}\) indeterminate form. Hence, we proceed with direct evaluation of the limit.
2Step 2: Direct Substitution
Since the limit does not result in an indeterminate form \(\frac{0}{0}\), directly substitute \(x=1\) and \(y=2\) into the expression. Compute the numerator \(1^3 - 3(1)^2(2) + 3(1)(2)^2 - 2^3 = -1\), and the denominator \(2 - 2(1)^2 = 0\). The division of \(-1\) by \(0\) indicates an undefined result, suggesting that the function approaches negative infinity or positive infinity or does not have a limit at this point.
Key Concepts
Understanding Indeterminate FormsUsing Direct Substitution When PossibleExploring Limit Analysis for Comprehensive Understanding
Understanding Indeterminate Forms
In calculus, an indeterminate form is a mathematical expression that initially appears to fizzle out into forms like \(\frac{0}{0}\), \(\frac{\infty}{\infty}\), \(0 \times \infty\), among others, during limit evaluation. Such forms require deep inspection because they don't immediately reveal the limit's behavior as variables approach specific values.
- Indeterminate forms occur when both the numerator and denominator of a rational expression approach zero; this is called a \(\frac{0}{0}\) form.
- They can also arise in cases involving infinity, such as \(\frac{\infty}{\infty}\) or differences like \(\infty - \infty\).
Using Direct Substitution When Possible
Direct substitution is a straightforward method to evaluate limits. This technique involves plugging in the specified values for the variables, assuming they do not lead to indeterminate forms like \(\frac{0}{0}\).
- If direct substitution gives you a defined number, then that number is the limit of the function at the point of interest.
- However, if substitution leads to undefined values like \(\frac{a}{0}\) (with \(a eq 0\)), further analysis is needed to understand the behavior near that point.
Exploring Limit Analysis for Comprehensive Understanding
Limit analysis refers to examining a function's behavior as it approaches a specific point, using various techniques to discover whether a limit exists and, if so, to calculate it. This analysis often involves:
- Checking for continuity at the point of interest.
- Considering different paths in multivariable limits to determine if the limit changes based on the path taken.
- Using epsilon-delta definitions for rigorous proof in theoretical situations.
Other exercises in this chapter
Problem 4
Let \(g(x, y, z)=\sqrt{x \cos y}+z^{2}\). Find each value. (a) \(g(4,0,2)\) (b) \(g(-9, \pi, 3)\) (c) \(g(2, \pi / 3,-1)\) (d) \(g(3,6,1.2)\)
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$$ f(x, y)=x y^{2}-6 x^{2}-3 y^{2} $$
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In Problems 1-16, find all first partial derivatives of each function. \(f(x, y)=e^{x} \cos y\)
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$$ \text { In Problems 1-10, find the gradient } \nabla f \text {. } $$ $$ f(x, y)=x^{2} y \cos y $$
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