Problem 4
Question
Konvergieren die folgenden Reihen? Was ist ihre summe? a) \(\sum_{k=1}^{\infty} \frac{2}{3^{k-1}}\) b) \(\sum_{k=1}^{\infty} \frac{2^{k}+3^{k}}{6^{k}}\).
Step-by-Step Solution
Verified Answer
a) Converges, sum = 3. b) Converges, sum = \( \frac{3}{2} \).
1Step 1: Recognize the Series Type
For part a), the series is \( \sum_{k=1}^{\infty} \frac{2}{3^{k-1}} \). This suggests a geometric series, identifiable by the constant ratio between successive terms. For part b), \( \sum_{k=1}^{\infty} \frac{2^{k}+3^{k}}{6^{k}} \), notice it's a combination of two geometric series.
2Step 2: Calculate the Common Ratio (a)
In a geometric series \( \sum_{k=0}^{\infty} ar^k \), the form resembles \( \sum_{k=1}^{\infty} \frac{2}{3^{k-1}} = 2 \sum_{k=0}^{\infty} \left(\frac{1}{3}\right)^k \). Check the common ratio: \( r = \frac{1}{3} \), which is less than 1, signaling convergence.
3Step 3: Find the Sum of the Geometric Series (a)
The formula for the sum of a geometric series \( \sum_{k=0}^{\infty} ar^k \) is \( S = \frac{a}{1-r} \). Here, \( a = 2 \) and \( r = \frac{1}{3} \), so: \( S = \frac{2}{1-\frac{1}{3}} = \frac{2}{\frac{2}{3}} = 3 \).
4Step 4: Separate and Simplify the Series (b)
Express the series as \( \sum_{k=1}^{\infty} \left( \frac{2^k}{6^k} + \frac{3^k}{6^k} \right) \), which is \( \sum_{k=1}^{\infty} \left(\frac{1}{3}\right)^k + \sum_{k=1}^{\infty} \left(\frac{1}{2}\right)^k \). Both are geometric series.
5Step 5: Calculate Each Series in b)
For \( \sum_{k=1}^{\infty} \left(\frac{1}{3}\right)^k \), the sum is \( \frac{\frac{1}{3}}{1-\frac{1}{3}} = \frac{1}{2} \). For \( \sum_{k=1}^{\infty} \left(\frac{1}{2}\right)^k \), the sum is \( \frac{\frac{1}{2}}{1-\frac{1}{2}} = 1 \).
6Step 6: Conclusion for Part (b)
Add both sums from part (b): \( \frac{1}{2} + 1 = \frac{3}{2} \). This indicates that the series converges and the total sum is \( \frac{3}{2} \).
Key Concepts
Understanding Geometric SeriesCalculating the Sum of a SeriesConvergence Criteria for SeriesExploring Infinite Series
Understanding Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the "common ratio." This is why the series is termed geometric. For example, a series such as \( \sum_{k=0}^{\infty} ar^k \) is characterized by the first term \(a\) and the common ratio \(r\).
A geometric series can either converge or diverge, depending on the absolute value of the common ratio \(r\):
A geometric series can either converge or diverge, depending on the absolute value of the common ratio \(r\):
- If \(|r| < 1\), the series converges, meaning it approaches a finite sum as \(k\) approaches infinity.
- If \(|r| \geq 1\), the series diverges, implying it grows indefinitely or oscillates.
Calculating the Sum of a Series
To find the sum of an infinite geometric series, mathematicians use the formula \( S = \frac{a}{1-r} \), where \(S\) represents the sum, \(a\) represents the first term, and \(r\) represents the common ratio.
This formula is derived from the nature of a geometric series and is only valid when the series converges (i.e., when \(|r| < 1\)).
Calculating the sum requires identifying the first term and the common ratio. For instance, in the series \( \sum_{k=0}^{\infty} ar^k \), if \(a = 2\) and \(r = \frac{1}{3}\), the sum is:
\[S = \frac{2}{1-\frac{1}{3}} = \frac{2}{\frac{2}{3}} = 3.\]
This calculation tells us that the infinite series will sum up to 3, showing how vital the formula is for practical computations.
This formula is derived from the nature of a geometric series and is only valid when the series converges (i.e., when \(|r| < 1\)).
Calculating the sum requires identifying the first term and the common ratio. For instance, in the series \( \sum_{k=0}^{\infty} ar^k \), if \(a = 2\) and \(r = \frac{1}{3}\), the sum is:
\[S = \frac{2}{1-\frac{1}{3}} = \frac{2}{\frac{2}{3}} = 3.\]
This calculation tells us that the infinite series will sum up to 3, showing how vital the formula is for practical computations.
Convergence Criteria for Series
Convergence of a series determines whether the infinite sum of its terms results in a finite number. The key factor in convergence for a geometric series is the common ratio \(r\).
To decide if a given series converges, follow these guidelines:
To decide if a given series converges, follow these guidelines:
- If \(|r| < 1\), the series converges, indicating that the series approaches a finite limit.
- If \(|r| \geq 1\), the series diverges, meaning no finite sum can be ascertained.
Exploring Infinite Series
Infinite series extend indefinitely and are a fascinating area of study in mathematics. A series is a sum of terms, and an infinite series goes on without end.
Important concepts regarding infinite series include:
Important concepts regarding infinite series include:
- A convergent infinite series has a definite finite sum, determined by the series' structure and characteristics, like the common ratio in geometric series.
- A divergent infinite series does not settle down to a specific value, often growing infinitely large or failing to approach a stable sum.
Other exercises in this chapter
Problem 2
Finden Sie eine zahl \(x \in \mathbb{R}\) so, daB die Reihe \(\sum_{k=1}^{\infty} x^{k-1}\) konvergent ist. Finden sie eine zahl \(y \in \mathbb{R}\) so, \(\ope
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a) Finden Sie neben der harmonischen Reihe ein Beispiel einer divergenten Reihe \(\sum_{k=1}^{\infty} a_{k}\), für die \(\lim _{n \rightarrow \infty} a_{n}\) ex
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AUFGABE 8. - Untersuchen sie die folgenden Reihen mit dem Wurzelkriterium auf Konvergenz: a) \(\sum_{n=1}^{\infty} \frac{n^{2}}{2^{n}}\), b) \(\sum_{k=1}^{\inft
View solution Problem 9
Untersuchen Sie die folgenden Reihen mit dem Quotientenkriterium auf Konvergenz: a) \(\sum_{n=1}^{\infty} \frac{n t}{n}\) b) Für welche zahlen \(x>0\) konvergie
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