Problem 4
Question
In the synthesis of ammonia, if \(-\Delta\left[\mathrm{H}_{2}\right] / \Delta t=4.5 \times 10^{-4}\) \(\mathrm{mol} / \mathrm{L} \cdot \mathrm{min},\) what is \(\Delta\left[\mathrm{NH}_{3}\right] / \Delta t ?\) \(\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{g})\)
Step-by-Step Solution
Verified Answer
The rate of change of ammonia concentration is \(3.0 \times 10^{-4}\) mol/L·min.
1Step 1: Understand the Given Information
We are given the rate of change of hydrogen concentration as \(-\frac{\Delta[\mathrm{H}_2]}{\Delta t} = 4.5 \times 10^{-4}\) mol/L·min. We need to find the rate of change of ammonia concentration, \(\frac{\Delta[\mathrm{NH}_3]}{\Delta t}\), for the reaction \(\mathrm{N}_2(\mathrm{g}) + 3 \mathrm{H}_2(\mathrm{g}) \longrightarrow 2 \mathrm{NH}_3(\mathrm{g})\).
2Step 2: Relate the Rates of Reaction
Using the stoichiometry of the balanced chemical equation, we see that for every 3 moles of \(\mathrm{H}_2\) consumed, 2 moles of \(\mathrm{NH}_3\) are produced. Thus, the rate of change of \(\mathrm{NH}_3\) is \(\frac{2}{3}\) times the rate of change of \(\mathrm{H}_2\).
3Step 3: Calculate the Rate of Change of NH3
Using the relationship from Step 2, calculate the rate of change of \(\mathrm{NH}_3\):\[\frac{\Delta[\mathrm{NH}_3]}{\Delta t} = \frac{2}{3} \times \left(4.5 \times 10^{-4}\right) = 3.0 \times 10^{-4}\, \text{mol/L·min}\]
4Step 4: Provide the Final Answer
The rate of change of ammonia concentration is \(3.0 \times 10^{-4}\) mol/L·min.
Key Concepts
StoichiometryChemical EquilibriumAmmonia Synthesis
Stoichiometry
Stoichiometry is the field of chemistry that deals with the relationships between the quantities of reactants and products in chemical reactions. It involves using balanced chemical equations to make predictions about the relative amounts of substances consumed and produced. In essence, stoichiometry allows chemists to quantify how much of each component is involved in a reaction.
An essential concept of stoichiometry is the mole ratio, derived from the coefficients in a chemical equation. For the synthesis of ammonia, as shown through the reaction model:
By understanding this concept, we can use stoichiometry to calculate unknown quantities in a reaction, like the rate of change of a product or reactant. This is achieved by forming equations based on the given relationships and solving for the desired variables. Stoichiometric calculations assure that chemical equations are accurately balanced and that the conservation of mass is adhered to.
An essential concept of stoichiometry is the mole ratio, derived from the coefficients in a chemical equation. For the synthesis of ammonia, as shown through the reaction model:
- \[\text{N}_2(g) + 3\, \text{H}_2(g) \rightarrow 2\, \text{NH}_3(g)\]
By understanding this concept, we can use stoichiometry to calculate unknown quantities in a reaction, like the rate of change of a product or reactant. This is achieved by forming equations based on the given relationships and solving for the desired variables. Stoichiometric calculations assure that chemical equations are accurately balanced and that the conservation of mass is adhered to.
Chemical Equilibrium
Chemical equilibrium occurs when a chemical reaction reaches a state where the concentrations of reactants and products remain constant over time. This does not mean that the reaction has stopped; rather, it has reached a balanced state where the rate of the forward reaction equals the rate of the reverse reaction.
In the context of ammonia synthesis, this balance is particularly important. At equilibrium, the synthesis of ammonia can be represented by the equation:
Understanding chemical equilibrium and its dynamic nature is crucial for industrial processes like the synthesis of ammonia, ensuring that production is efficient and sustainable. It provides insights into maximizing yield and optimizing reaction conditions.
In the context of ammonia synthesis, this balance is particularly important. At equilibrium, the synthesis of ammonia can be represented by the equation:
- \[\text{N}_2(g) + 3\, \text{H}_2(g) \rightleftharpoons 2\, \text{NH}_3(g)\]
Understanding chemical equilibrium and its dynamic nature is crucial for industrial processes like the synthesis of ammonia, ensuring that production is efficient and sustainable. It provides insights into maximizing yield and optimizing reaction conditions.
Ammonia Synthesis
Ammonia synthesis is an industrial process where nitrogen and hydrogen gases react to form ammonia. This process is commonly known as the Haber-Bosch process, named after the scientists who developed it. Ammonia plays a vital role in the production of fertilizers, making this method critical to global agriculture.
The Haber-Bosch process is carried out at high temperatures and pressures to maximize the yield of ammonia. The chemical equation for the reaction is:
Optimizing the conditions for ammonia synthesis involves balancing kinetic and thermodynamic considerations, ensuring that the process is not only efficient but also economically viable. Understanding the nuances of this synthesis is fundamental for chemists and engineers working to meet the growing global demand for agricultural inputs.
The Haber-Bosch process is carried out at high temperatures and pressures to maximize the yield of ammonia. The chemical equation for the reaction is:
- \[\text{N}_2(g) + 3\, \text{H}_2(g) \rightarrow 2\, \text{NH}_3(g)\]
Optimizing the conditions for ammonia synthesis involves balancing kinetic and thermodynamic considerations, ensuring that the process is not only efficient but also economically viable. Understanding the nuances of this synthesis is fundamental for chemists and engineers working to meet the growing global demand for agricultural inputs.
Other exercises in this chapter
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