Problem 4
Question
In the return stroke of a typical lightning bolt, a current of \(2.5 \times 10^{4}\) A exists for \(20 \mu\) s. How much charge is transferred in this event?
Step-by-Step Solution
Verified Answer
The charge transferred is 0.5 Coulombs.
1Step 1: Understand the Relationship
To find out the amount of charge transferred, we need to use the relationship between current, charge, and time: \[ Q = I imes t \]where \( Q \) is the charge, \( I \) is the current, and \( t \) is the time.
2Step 2: Identify the Variables
Here, we have:- Current \( I = 2.5 \times 10^{4} \) A,- Time \( t = 20 \mu s = 20 \times 10^{-6} \) s.
3Step 3: Apply the Formula
Substitute the known values into the equation:\[ Q = 2.5 \times 10^{4} \times 20 \times 10^{-6} \]
4Step 4: Calculate the Charge
Simplify and calculate the expression:\[ Q = 2.5 \times 20 \times 10^4 \times 10^{-6} \]\[ Q = 50 \times 10^{-2} \]\[ Q = 0.5 \, C \]
5Step 5: Review the Solution
The charge transferred during this lightning event is calculated as \(0.5 \) Coulombs.
Key Concepts
Understanding Electrical CurrentThe Power of LightningThe Role of Time Duration in Charge Transfer
Understanding Electrical Current
In electrical terms, current is the flow of electric charge through a conductor, such as a wire. Imagine it as water flowing through a pipe, where the amount of water (electric charge) flowing per second is the current.
The unit of current is the ampere, often shortened to "A." When we say that a lightning strike has a current of \(2.5 \times 10^{4}\) A, it means 25,000 units of charge are passing through a point in the lightning bolt per second.
To calculate the charge passing through, you multiply the current by the time the current is flowing. This relationship is given by the formula:
This basic principle helps us understand how much charge moves through a system over a given period.
The unit of current is the ampere, often shortened to "A." When we say that a lightning strike has a current of \(2.5 \times 10^{4}\) A, it means 25,000 units of charge are passing through a point in the lightning bolt per second.
To calculate the charge passing through, you multiply the current by the time the current is flowing. This relationship is given by the formula:
- The formula: \(Q = I \times t\) where \(Q\) is the charge in coulombs.
- \(I\) is the current in amperes, and
- \(t\) is the time in seconds.
This basic principle helps us understand how much charge moves through a system over a given period.
The Power of Lightning
Lightning is a powerful natural phenomenon involving the rapid movement of electric charges. It is a dramatic illustration of electric current in action.
A typical lightning bolt can carry a massive current, such as \(2.5 \times 10^{4}\) amperes as seen in the problem above. This huge flow of electric charge results from the clouds building up opposite charges, which eventually meet, causing an electric discharge.
The duration of this current flow is extremely short, often just a few microseconds (a microsecond is \(10^{-6}\) seconds). During that brief period, a tremendous amount of electrical energy is transferred, sometimes enough to start fires, split trees, or cause damage to structures. Understanding the behavior of lightning as a current gives us insight into both its power and its dangers.
A typical lightning bolt can carry a massive current, such as \(2.5 \times 10^{4}\) amperes as seen in the problem above. This huge flow of electric charge results from the clouds building up opposite charges, which eventually meet, causing an electric discharge.
The duration of this current flow is extremely short, often just a few microseconds (a microsecond is \(10^{-6}\) seconds). During that brief period, a tremendous amount of electrical energy is transferred, sometimes enough to start fires, split trees, or cause damage to structures. Understanding the behavior of lightning as a current gives us insight into both its power and its dangers.
The Role of Time Duration in Charge Transfer
Time duration indicates how long a current flows through a conductor. In our lighting example, the time duration is expressed in microseconds (\(\mu s\)), where \(1\,\mu s = 10^{-6}\,s\).
In the formula \(Q = I \times t\), time duration is a crucial factor because it determines how much charge is transferred over that specific period. Even massive currents, when only existing for brief moments, transfer limited charge due to short time durations.
For instance, with a current of \(2.5 \times 10^4\) A flowing for \(20\,\mu s\), the total charge transferred is simplified to \(0.5\) Coulombs as calculated earlier.
This shows that the relationship between current and time determines the magnitude of charge movement, underlining the significance of time duration in electrical events.
In the formula \(Q = I \times t\), time duration is a crucial factor because it determines how much charge is transferred over that specific period. Even massive currents, when only existing for brief moments, transfer limited charge due to short time durations.
For instance, with a current of \(2.5 \times 10^4\) A flowing for \(20\,\mu s\), the total charge transferred is simplified to \(0.5\) Coulombs as calculated earlier.
This shows that the relationship between current and time determines the magnitude of charge movement, underlining the significance of time duration in electrical events.
Other exercises in this chapter
Problem 2
Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with their diameters (Fig. \(21-22 a\) )
View solution Problem 3
What must be the distance between point charge \(q_{1}=26.0 \mu \mathrm{C}\) and point charge \(q_{2}=-47.0 \mu \mathrm{C}\) for the electrostatic force between
View solution Problem 5
A particle of charge \(+3.00 \times 10^{-6} \mathrm{C}\) is \(12.0 \mathrm{~cm}\) distant from a second particle of charge \(-1.50 \times 10^{-6} \mathrm{C}\).
View solution Problem 6
Two equally charged particles are held \(3.2 \times 10^{-3} \mathrm{~m}\) apart and then released from rest. The initial acceleration of the first particle is o
View solution