Problem 4
Question
In \(3-18,\) find all roots of each given function by factoring or by using the quadratic formula. $$ f(x)=2 x^{3}+2 x^{2}-4 x $$
Step-by-Step Solution
Verified Answer
The roots of the function are \( x = 0, -2, \) and \( 1 \).
1Step 1: Factor Out Common Factor
The function is given as \( f(x) = 2x^3 + 2x^2 - 4x \). First, we notice that each term in the function has a common factor of \( 2x \). Factoring \( 2x \) out, we get: \[ f(x) = 2x(x^2 + x - 2) \] This expression provides a simpler polynomial to solve for roots.
2Step 2: Factor the Quadratic Expression
Next, we need to factor the quadratic expression \( x^2 + x - 2 \). To factor this, we look for two numbers that multiply to \(-2\) (the constant term) and add to \(1\) (the linear coefficient). These numbers are \(2\) and \(-1\). Thus, we factor the quadratic as follows: \[ x^2 + x - 2 = (x + 2)(x - 1) \]
3Step 3: Set Each Factor Equal to Zero
Now that the function is factored completely as \( f(x) = 2x(x + 2)(x - 1) \), we set each factor equal to zero to find the roots of the function:1. \( 2x = 0 \) 2. \( x + 2 = 0 \) 3. \( x - 1 = 0 \)
4Step 4: Solve for Roots
Solve each equation from Step 3 for \( x \):1. \( 2x = 0 \) yields \( x = 0 \).2. \( x + 2 = 0 \) yields \( x = -2 \).3. \( x - 1 = 0 \) yields \( x = 1 \).Therefore, the roots of the function are \( x = 0, -2, \) and \( 1 \).
Key Concepts
Quadratic FormulaSolving Cubic EquationsAlgebraic Expressions
Quadratic Formula
The quadratic formula is an essential tool in algebra for finding the roots of a quadratic equation. A quadratic equation is any equation that can be written in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants.
When factoring is difficult or impossible, the quadratic formula becomes invaluable. The formula is:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]By using this formula, we can easily find the roots of the quadratic equation by substituting the values of \(a\), \(b\), and \(c\). Let's break it down:
When factoring is difficult or impossible, the quadratic formula becomes invaluable. The formula is:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]By using this formula, we can easily find the roots of the quadratic equation by substituting the values of \(a\), \(b\), and \(c\). Let's break it down:
- \(b^2 - 4ac\) is called the discriminant.
- The discriminant tells us the nature of the roots (real and distinct, real and same, or complex).
- The symbol \(\pm\) gives us the two roots of the equation.
- If the discriminant is positive, there are two distinct real roots.
- If it is zero, there is one real root (a repeated root).
- If it is negative, the roots are complex.
Solving Cubic Equations
Solving cubic equations can be more complex than solving quadratics, but there are still several methods to find their roots. A cubic equation is usually in the form \(ax^3 + bx^2 + cx + d = 0\).
For some cubic equations, like the one in the original exercise, factoring is often a good starting point. To factor a cubic equation step-by-step:
Be mindful of the possibility of multiple real roots or complex roots in cubic equations. It's always good to check your factorization by multiplying the factors to confirm that you end up with the original polynomial. This verification step ensures no mistakes were made during the factoring process.
For some cubic equations, like the one in the original exercise, factoring is often a good starting point. To factor a cubic equation step-by-step:
- Look for any common factors in all terms. This makes the equation simpler.
- Write the equation as a product of factors. This can reduce a complex equation into simpler, smaller degree polynomials.
- Apply the zero product property by setting each factor to zero, which solves for its roots.
Be mindful of the possibility of multiple real roots or complex roots in cubic equations. It's always good to check your factorization by multiplying the factors to confirm that you end up with the original polynomial. This verification step ensures no mistakes were made during the factoring process.
Algebraic Expressions
Algebraic expressions are essential building blocks in algebra. These expressions may consist of variables, constants, and operations. Here's what to look out for:
- Variables: Typically represented by letters (e.g., \(x, y\)), they are the unknowns we often solve for.
- Coefficients: Numbers that multiply variables. For instance, in \(3x\), 3 is the coefficient.
- Constant terms: Numbers on their own (e.g., \(5\) in \(2x + 5\)).
- Simplifying expressions by combining like terms.
- Using distributive property to expand or factor expressions.
- Rearranging expressions to make equations easier to solve.
Other exercises in this chapter
Problem 3
In \(3-8,\) complete the square of the quadratic expression. $$ x^{2}+6 x $$
View solution Problem 4
In \(3-14,\) use the quadratic formula to find the imaginary roots of each equation. $$ x^{2}+6 x+10=0 $$
View solution Problem 4
Without solving each equation, find the sum and product of the roots. \(x^{2}+4 x+5=0\)
View solution Problem 4
In \(3-17,\) find each sum or difference of the complex numbers in \(a+b i\) form. $$ (3-5 i)+(2+i) $$
View solution