Problem 4
Question
Graph some representative vectors in the given vector field. $$ \mathbf{F}(x, y)=x \mathbf{i}+2 y \mathbf{j} $$
Step-by-Step Solution
Verified Answer
Graph vectors such as \((0,0)\), \((1,1)\), \((-1,1)\), etc., following their components \(x\mathbf{i} + 2y\mathbf{j}\).
1Step 1: Understand the Vector Field
The given vector field \( \mathbf{F}(x, y) = x \mathbf{i} + 2y \mathbf{j} \) is a field of vectors where each vector depends on the position \( (x, y) \). The component \( x \mathbf{i} \) determines the magnitude and direction along the x-axis, while \( 2y \mathbf{j} \) determines the magnitude and direction along the y-axis.
2Step 2: Choose Representative Points
Select several points in the plane to calculate and graph vectors. For instance, choose points like \((0, 0), (1, 1), (-1, 1), (1, -1), (2, 0)\), and so on.
3Step 3: Calculate the Vector at Each Point
For each selected point, compute the vector \( \mathbf{F}(x, y) \).- At \((0,0)\), \( \mathbf{F}(0, 0) = 0 \mathbf{i} + 0 \mathbf{j} = \mathbf{0} \).- At \((1, 1)\), \( \mathbf{F}(1, 1) = 1 \mathbf{i} + 2 \mathbf{j} \).- At \((-1, 1)\), \( \mathbf{F}(-1, 1) = -1 \mathbf{i} + 2 \mathbf{j} \).- At \((1, -1)\), \( \mathbf{F}(1, -1) = 1 \mathbf{i} - 2 \mathbf{j} \).- At \((2, 0)\), \( \mathbf{F}(2, 0) = 2 \mathbf{i} + 0 \mathbf{j} \).
4Step 4: Graph Each Calculated Vector
Using graph paper or a digital graphing tool, plot each vector starting from its corresponding point. The direction and length of the vector are determined by its \( \mathbf{i} \) and \( \mathbf{j} \) components.
5Step 5: Analyze the Vector Field Pattern
Observe the vectors' direction and magnitude. Notice that the x-component depends linearly on \( x \), and the y-component depends linearly on \( y \), indicating a pattern where vectors tend to stretch out as \( x \) and \( y \) increase.
Key Concepts
Vector ComponentsGraphing VectorsVector Magnitude and Direction
Vector Components
To truly understand vector fields, you need to grasp the concept of vector components. Vectors are entities that have both a magnitude and a direction. In our given vector field, \( \mathbf{F}(x, y) = x \mathbf{i} + 2y \mathbf{j} \), each vector can be broken down into two main components:
- \( x \mathbf{i} \): This denotes the horizontal (or x-axis) component of the vector. It tells us how far right or left the vector will point on the graph, depending on the value of \( x \).
- \( 2y \mathbf{j} \): This denotes the vertical (or y-axis) component. It shows us how far up or down from the base point the vector will go based on twice the value of \( y \).
Graphing Vectors
Graphing vectors helps in visualizing how a vector field behaves at various points in a plane. To graph vectors from the vector field \( \mathbf{F}(x, y) \), follow these steps:
- Start by choosing some representative points in the plane. Typical points like \((0, 0), (1, 1), (-1, 1)\), etc. give a good spread across the graph.
- Calculate the specific vector for each point you picked. For instance, at \((1, 1)\), the vector is \( \mathbf{F}(1, 1) = 1 \mathbf{i} + 2 \mathbf{j} \).
- Plot each vector starting from the point you chose. This means placing the tail of the vector at the chosen point and using the calculated components \( x \mathbf{i} \) and \( 2y \mathbf{j} \) to find the head of the vector.
Vector Magnitude and Direction
Each vector within our vector field \( \mathbf{F}(x, y) = x \mathbf{i} + 2y \mathbf{j} \) possesses its own magnitude and direction. The magnitude of a vector is akin to its total length or size. This can be calculated using the formula:\[\text{Magnitude} = \sqrt{(x)^2 + (2y)^2}\]The direction of a vector shows the route or angle it takes from its starting point. This direction can be determined by considering the angle \( \theta \) it makes with the positive x-axis:\[\theta = \tan^{-1}\left(\frac{2y}{x}\right)\]Together, magnitude and direction form a complete picture of the vector's presence in the field:
- Magnitude gives you an idea of how forceful or weak a vector is. Larger magnitudes tell of stronger vectors.
- Direction indicates where the vector is headed. Using angle calculations, you can easily illustrate this on a graph.
Other exercises in this chapter
Problem 4
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Compute the gradient for the given function. $$ F(x, y, z)=x y \cos y z $$
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Graph the curve traced by the given vector function. $$ \mathbf{r}(t)=4 \mathbf{i}+2 \cos t \mathbf{j}+3 \sin t \mathbf{k} $$
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