The name of the complex \(\left[\mathrm{Pt}\mathrm{Cl}_{2}\left(\mathrm{NH}_{3}\right)_{2}\right]\) is diamminedichloroplatinum(II). The tetrahedral geometry does not have geometric isomers and is diamagnetic, while the square-planar geometry has two geometric isomers (cis and trans) and is also diamagnetic. The presence of geometric isomers can help distinguish between the two geometries, but magnetic properties cannot.
1Step 1: (a) Name of the molecule
The complex under consideration is \(\left[\mathrm{Pt}\mathrm{Cl}_{2}\left(\mathrm{NH}_{3}\right)_{2}\right]\). To name this complex, we follow the IUPAC rules, where we list the ligands alphabetically, followed by the central metal atom. In this case, our ligands are two chlorides (Cl) and two ammonia molecules (NH3). Therefore, the name of the molecule is "diamminedichloroplatinum(II)."
2Step 2: (b) Geometric isomerism in tetrahedral geometry
Geometric isomers are molecules with the same chemical formula but different spatial arrangements of their atoms. In tetrahedral geometry, all four ligand positions are equivalent, so no geometric isomers are possible for this molecule.
3Step 3: (c) Magnetic properties in tetrahedral geometry
In the tetrahedral geometry, the molecule would be diamagnetic, as platinum (II) has a d8 configuration: 1s² 2s² 2p6 3s² 3p6 3d10 4s² 4p6 4d8. All the d-electrons are thus paired, and there are no unpaired electrons. Diamagnetic substances have no unpaired electrons and are not attracted to a magnetic field.
4Step 4: (d) Geometric isomerism in square-planar geometry
In square-planar geometry, different spatial arrangements of the ligands are possible. For the molecule \(\left[\mathrm{Pt}\mathrm{Cl}_{2}\left(\mathrm{NH}_{3}\right)_{2}\right]\), there are two possible geometric isomers: cis and trans. In the cis isomer, both ammonia ligands are adjacent to each other, while in the trans isomer, the ammonia ligands are opposite to each other. So, the square-planar molecule has geometric isomers.
5Step 5: (e) Magnetic properties in square-planar geometry
In the square-planar geometry, the molecule would also be diamagnetic. The reason is the same as for the tetrahedral geometry - platinum (II) has a d8 configuration with all its d-electrons paired, hence there are no unpaired electrons.
6Step 6: (f) Distinguishing between tetrahedral and square-planar geometries using geometric isomers
As we have discussed earlier, the tetrahedral molecule doesn't have geometric isomers, while the square-planar molecule does have geometric isomers (cis and trans). Therefore, the presence of geometric isomers can be used to distinguish between tetrahedral and square-planar geometries of the complex.
7Step 7: (g) Distinguishing between tetrahedral and square-planar geometries using magnetic properties
As previously discussed, both the tetrahedral and the square-planar molecules are diamagnetic because no unpaired electrons are present in the platinum (II) d8 configuration. Therefore, measuring the magnetic properties of the molecule would not help in distinguishing between these two geometries, as both of them would be diamagnetic.