Problem 4
Question
For the functions \(f\) and \(g\), find a. \((f+g)(x)\), b. \((f-g)(x), c .(f \cdot g)(x)\), and d. \(\left(\frac{f}{g}\right)(x)\). $$ f(x)=x^{2}-2 ; g(x)=3 x $$
Step-by-Step Solution
Verified Answer
1. \((f+g)(x)=x^2+3x-2\)
2. \((f-g)(x)=x^2-3x-2\)
3. \((f \cdot g)(x)=3x^3-6x\)
4. \(\left(\frac{f}{g}\right)(x)=\frac{x}{3}-\frac{2}{3x}, x \neq 0\)
1Step 1: Adding Functions
To find \((f+g)(x)\), simply add the two functions: \(f(x) = x^2 - 2\) and \(g(x) = 3x\). This gives, \[(f+g)(x) = f(x) + g(x) = (x^2 - 2) + 3x = x^2 + 3x - 2.\]
2Step 2: Subtracting Functions
To find \((f-g)(x)\), subtract \(g(x)\) from \(f(x)\): \[(f-g)(x) = f(x) - g(x) = (x^2 - 2) - 3x = x^2 - 3x - 2.\]
3Step 3: Multiplying Functions
To find \((f\cdot g)(x)\), multiply the two functions: \[(f\cdot g)(x) = f(x) \cdot g(x) = (x^2 - 2)\cdot 3x.\]Distribute: \[(f\cdot g)(x) = 3x \cdot x^2 - 3x \cdot 2 = 3x^3 - 6x.\]
4Step 4: Dividing Functions
To find \(\left(\frac{f}{g}\right)(x)\), divide \(f(x)\) by \(g(x)\): \[\left(\frac{f}{g}\right)(x) = \frac{x^2 - 2}{3x}.\] This can be simplified as \[ \frac{x^2}{3x} - \frac{2}{3x} = \frac{x}{3} - \frac{2}{3x}.\] Ensure in your final answer that \(x eq 0\) to avoid division by zero.
Key Concepts
Adding FunctionsSubtracting FunctionsMultiplying FunctionsDividing Functions
Adding Functions
Adding functions involves combining two function expressions to form a new expression. Consider the functions \(f(x) = x^2 - 2\) and \(g(x) = 3x\). To add these functions, you calculate
Adding functions is particularly useful when you want to consider cumulative effects, like summing forces or costs modeled by separate functions.
- \((f+g)(x) = f(x) + g(x)\)
- Plug in the expressions: \((x^2 - 2) + 3x\)
- Simplify to get: \(x^2 + 3x - 2\)
Adding functions is particularly useful when you want to consider cumulative effects, like summing forces or costs modeled by separate functions.
Subtracting Functions
When subtracting functions, you focus on finding the difference between two function expressions. For \(f(x) = x^2 - 2\) and \(g(x) = 3x\), follow these steps:
- Calculate: \((f-g)(x) = f(x) - g(x)\)
- Insert the expressions: \((x^2 - 2) - 3x\)
- Simplify to obtain: \(x^2 - 3x - 2\)
Multiplying Functions
Multiplying functions means determining how one function scales another. For \(f(x) = x^2 - 2\) and \(g(x) = 3x\), the process is as follows:
Function multiplication is useful for modeling interactions between varying factors, like how changing weather might amplify seasonal effects on temperature, described by different functions.
- Compute: \((f\cdot g)(x) = f(x) \cdot g(x)\)
- Apply the expressions: \((x^2 - 2) \cdot 3x\)
- Distribute to get: \(3x^3 - 6x\)
Function multiplication is useful for modeling interactions between varying factors, like how changing weather might amplify seasonal effects on temperature, described by different functions.
Dividing Functions
Dividing functions involves determining how one function affects the scalings of another through division. Given \(f(x) = x^2 - 2\) and \(g(x) = 3x\), you handle this calculation by:
This operation is often seen in physics or economics, where one function might represent costs and the other quantities, enabling analysis of cost per unit or efficiency.
- Set up: \(\left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)}\)
- Input the expressions: \(\frac{x^2 - 2}{3x}\)
- Simplify: \(\frac{x}{3} - \frac{2}{3x}\)
This operation is often seen in physics or economics, where one function might represent costs and the other quantities, enabling analysis of cost per unit or efficiency.
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