Problem 4
Question
For each of the systems, determine whether the origin is stable, asymptotically stable, or unstable. \(\begin{array}{ll}\text { a. } \quad x^{\prime} & =2 x-5 y \\ & y^{\prime}=x-2 y \\ \text { c. } & x^{\prime}=-6 x-2 y \\ y^{\prime} & =2 x-1 y \\ \text { e. } & x^{\prime}=3 x-2 y \\ & y^{\prime}=2 x-1 y \\ \text { g. } & x^{\prime}=-x-5 y \\ \text { i. } & y^{\prime}=2 x-3 y \\ & x^{\prime}=-3 x+1 y \\ & y^{\prime}=2 x-2 y \\ \text { k. } & x^{\prime}=x-2 y \\ & y^{\prime}=2 x+1 y\end{array}\) \(x^{\prime}=2 x-5 y\) \(y^{\prime}=2 x-4 y\) \(x^{\prime}=-9 x+4 y\) d. \(y^{\prime}=-4 x-1 y\) \(x^{\prime}=\quad y / 2\) \(\begin{aligned} y^{\prime} &=-5 x-3 y \\ x^{\prime} &=\quad-5 y \end{aligned}\) h. \(y^{\prime}=2 x+2 y\) j. \(x^{\prime}=3 x+y\) \(\begin{aligned} y^{\prime} &=2 x+2 y \\ x^{\prime} &=6 x+4 y \end{aligned}\) l. \(y^{\prime}=2 x-y\)
Step-by-Step Solution
VerifiedKey Concepts
Matrix Representation
Consider a system:
- \(\begin{pmatrix} x' \ y' \end{pmatrix} = A \begin{pmatrix} x \ y \end{pmatrix} \)
Asymptotic Stability
The equilibrium point of interest is often the origin in the system of equations, noted as \((0,0)\). To determine asymptotic stability for linear systems, you typically check the eigenvalues of the system matrix \(A\):
- If all eigenvalues have strictly negative real parts, the system is considered asymptotically stable. Solutions will decay to zero as time progresses, indicating that perturbations diminish and the system naturally returns to equilibrium.
- If any eigenvalue has a positive real part, the system is unstable.
- If eigenvalues have zero real parts but no negative real components, the system might be stable or unstable based on further qualitative analysis.
System of Linear Equations
When dealing with such systems, you are primarily interested in:
- Consistency - Whether there exists at least one solution fulfilling all equations, typically representing an equilibrium point or a solution curve in the context of differential equations.
- Finding the Solution - Often involves techniques like substitution, elimination, or using matrix inverses and eigenvalues, especially when applying to larger systems.