Problem 4
Question
Find the volume of a right pyramid having a height of \(h\) units and a square base of side \(a\) units.
Step-by-Step Solution
Verified Answer
The volume is \( \frac{1}{3} \cdot a^2 \cdot h \).
1Step 1: Understand the Formula for Volume of a Right Pyramid
The volume of a pyramid is given by the formula: V = \frac{1}{3} \cdot B \cdot h where \( B \) is the area of the base and \( h \) is the height.
2Step 2: Calculate the Area of the Base
For a square base with side length \( a \), the area \( B \) of the base is given by: B = a^2. Since the base is a square, use the formula for the area of a square, which is side length squared.
3Step 3: Substitute the Area of the Base into the Volume Formula
Now, substitute \( a^2 \) for \( B \) in the volume formula: V = \frac{1}{3} \cdot a^2 \cdot h. This results in the formula: V = \frac{1}{3} \cdot a^2 \cdot h.
4Step 4: Conclude with the Final Volume
Hence, the volume of the right pyramid with a square base of side \( a \) units and height \( h \) units is given by: V = \frac{1}{3} \cdot a^2 \cdot h.
Key Concepts
pyramid volume formulasquare base areageometric shapes
pyramid volume formula
Understanding the volume of a pyramid is key to solving many problems involving geometric shapes. The volume formula for a pyramid is derived from its unique structure. For any pyramid, the volume is given by:
\( V = \frac{1}{3} \cdot B \cdot h \). Here, \( B \) represents the area of the base and \( h \) is the height.
The fraction \( \frac{1}{3} \) plays a crucial role as it accounts for the sloping sides of the pyramid. This is why the volume of a pyramid is always one-third of the product of its base area and its height. The wide base and tapering height combine to give it this one-third factor.
In essence, this formula is easy to use once you break it down. Always start by finding the area of the base, which can vary based on the shape of the base. Then, multiply it by the height of the pyramid, and finally, multiply by the fraction \( \frac{1}{3} \).
\( V = \frac{1}{3} \cdot B \cdot h \). Here, \( B \) represents the area of the base and \( h \) is the height.
The fraction \( \frac{1}{3} \) plays a crucial role as it accounts for the sloping sides of the pyramid. This is why the volume of a pyramid is always one-third of the product of its base area and its height. The wide base and tapering height combine to give it this one-third factor.
In essence, this formula is easy to use once you break it down. Always start by finding the area of the base, which can vary based on the shape of the base. Then, multiply it by the height of the pyramid, and finally, multiply by the fraction \( \frac{1}{3} \).
square base area
For a pyramid with a square base, calculating the base area is straightforward. A square base means all four sides are equal. If each side of the square base is \( a \) units long, the area of the base \( B \) is calculated using the formula:
\( B = a^2 \).
This formula comes from the general area formula for a square, which is side length times itself. In this case, since all sides are equal, the side length squared gives the total area. This step is crucial because:
\( B = a^2 \).
This formula comes from the general area formula for a square, which is side length times itself. In this case, since all sides are equal, the side length squared gives the total area. This step is crucial because:
- It gives you the exact measure of how much space the base of the pyramid covers.
- It provides the value needed to complete the pyramid volume formula.
geometric shapes
Geometric shapes are a fundamental aspect of mathematics and understanding them is essential for solving many problems. The right pyramid itself is a 3-dimensional geometric shape with a base and triangular faces that converge at a single point (the apex). Here are some key points about right pyramids and other shapes:
- A right pyramid has its apex directly above the center of its base.
- The base can be any polygon, but common examples include squares, triangles, and rectangles.
- The height of a right pyramid is the perpendicular distance from the apex to the center of the base.
Other exercises in this chapter
Problem 3
A spring has a natural length of 6 in. A \(12,000-\mathrm{lb}\) force compresses the spring to \(5 \frac{1}{2}\) in. Find the work done in compressing it from 6
View solution Problem 4
A plate in the shape of an isosceles right triangle is submerged vertically in a tank of water, with one leg lying in the surface. The legs are each \(6 \mathrm
View solution Problem 5
Find the volume of the tetrahedron having 3 mutually perpendicular faces and three mutually perpendicular edges whose lengths have measures \(a, b\), and \(c\).
View solution Problem 5
\(x^{3}=2 y^{2} ; x=0, y=-2\)
View solution