Problem 4
Question
Find the roots to the characteristic equation, \(r^{2}-p r+q=0\) and write the solutions for \(A_{t}\) in the following systems. a. \(\begin{array}{rlrl}A_{0} & =10 & A_{t+1} & =0.8 A_{t}+0.2 B_{t} \\ B_{0} & =0 & B_{t+1} & =0.1 A_{t}+0.7 B_{t}\end{array}\) b. \(\begin{array}{rlrl}A_{0} & =0 & A_{t+1} & =0.6 A_{t}+0.3 B_{t} \\ B_{0} & =5 & B_{t+1} & =0.2 A_{t}+0.7 B_{t}\end{array}\) c. \(\begin{array}{rlrl}A_{0} & =1 & A_{t+1} & =0.26 A_{t}+0.04 B_{t} \\ B_{0} & =1 & B_{t+1} & =0.06 A_{t}+0.24 B_{t}\end{array}\) d. \(\begin{aligned} A_{0} &=2 & & A_{t+1}=& 1.04 A_{t}+0.16 B_{t} \\ B_{0} &=3 & & B_{t+1} &=0.24 A_{t}+0.96 B_{t} \end{aligned}\) e. \(\begin{array}{rlrl}A_{0} & =20 & A_{t+1} & =0.86 A_{t}+0.04 B_{t} \\\ B_{0} & =10 & B_{t+1} & =0.06 A_{t}+0.84 B_{t}\end{array}\)
Step-by-Step Solution
VerifiedKey Concepts
Characteristic Equation
For a system matrix, the characteristic equation is derived from the equation \( \det(M - rI) = 0 \). Here, \( M \) is the system matrix, \( r \) represents potential eigenvalues, and \( I \) is the identity matrix of the same dimension as \( M \). Calculating the determinant of \( M - rI \) provides a polynomial, typically a quadratic in simpler systems.
- The roots of this polynomial are the eigenvalues of the matrix.
- The form \( r^2 - (a+d)r + (ad-bc) = 0 \) is common when dealing with 2x2 matrices.
Understanding the eigenvalues obtained from the characteristic equation can indicate whether a system will grow, shrink, or oscillate over time, based on their real or complex nature.
System Matrix
In the context of discrete dynamical systems, the system matrix \( M \) is defined as:
\[M = \begin{bmatrix} a & b \ c & d \end{bmatrix}\]
and is used in relation:\[\begin{bmatrix} A_{t+1} \ B_{t+1} \end{bmatrix} = M \begin{bmatrix} A_{t} \ B_{t} \end{bmatrix}\]
- The elements of the matrix \( a, b, c, \) and \( d \) usually come from coefficients in the given update equations for a system.
- By analyzing this matrix, particularly its eigenvalues and eigenvectors, we can understand the long-term behavior of the system.
Formulating such matrices from a system allows for convenient use of linear algebra techniques to solve and predict system behavior.
Quadratic Formula
This formula is given by:
\[r = \frac{-(a+d) \pm \sqrt{(a+d)^2 - 4(ad-bc)}}{2}\]
where \( a, b, c, \) and \( d \) are elements of the system matrix, and \( (a+d)^2 - 4(ad-bc) \) is called the discriminant.
- If the discriminant is positive, the equation has two distinct real roots. These may signify two different growth or decay rates in a dynamical system.
- A zero discriminant indicates a single repeated root, which could lead to a stable system if the eigenvalue is less than 1.
- A negative discriminant suggests complex roots, often leading to oscillatory systems.
This powerful formula offers an exact solution to quadratic equations and is invaluable in assessing system stability through eigenvalues.
Initial Conditions
When we have derived the general solution for \( A_t \) using the eigenvalues, we end up with:
\[A_t = C_1 r_1^t + C_2 r_2^t\]
where \( r_1 \) and \( r_2 \) are the eigenvalues, and \( C_1 \) and \( C_2 \) are constants dependent on the initial conditions.
- Initial conditions, like \( A_0 \) and \( B_0 \), are specific values given at \( t = 0 \) for the variables in the system.
- Substituting these initial values into the general solution allows determination of \( C_1 \) and \( C_2 \).
By knowing the initial state of a system, we can tailor the general solution to fit the particular dynamics and evolution expected upon its evolution.