Problem 4
Question
Find the partial fraction decomposition. \(\frac{5 x-12}{x^{2}-4 x}\)
Step-by-Step Solution
Verified Answer
The partial fraction decomposition is \(\frac{3}{x} + \frac{2}{x-4}\).
1Step 1: Factor the Denominator
First, we need to factor the denominator. The given denominator is \(x^2 - 4x\). This can be factored as \(x(x - 4)\).
2Step 2: Set Up Partial Fractions
The goal is to express the fraction \(\frac{5x - 12}{x(x - 4)}\) as a sum of two simpler fractions. Since the degree of \(x(x - 4)\) is 2, we need two fractions: \(\frac{A}{x} + \frac{B}{x-4}\).
3Step 3: Combine into a Single Fraction
Combine \(\frac{A}{x} + \frac{B}{x-4}\) into a single fraction using a common denominator: \(\frac{A(x-4) + Bx}{x(x-4)}\).
4Step 4: Equate Numerators
Set the numerator of the original fraction equal to the new numerator: \(A(x-4) + Bx = 5x - 12\).
5Step 5: Simplify and Collect Like Terms
Expand and collect like terms: \(Ax - 4A + Bx = 5x - 12\), which simplifies to \((A + B)x - 4A = 5x - 12\).
6Step 6: Solve for Coefficients
From the equation \((A + B)x - 4A = 5x - 12\), we equate coefficients: - For \(x\) terms: \(A + B = 5\) - For constant terms: \(-4A = -12\) which gives \(A = 3\).
7Step 7: Substitute and Solve for B
Substitute \(A = 3\) into \(A + B = 5\) to find \(B\): \(3 + B = 5\), which gives \(B = 2\).
8Step 8: Write the Final Decomposition
Substitute \(A = 3\) and \(B = 2\) into the partial fractions: \(\frac{5x - 12}{x(x - 4)} = \frac{3}{x} + \frac{2}{x-4}\).
Key Concepts
Rational ExpressionsFactoring PolynomialsAlgebraic FractionsNumerator and DenominatorEquation Solving
Rational Expressions
Rational expressions are fractions that have polynomials in both the numerator and denominator. The expressions can represent real-world situations where certain variables are unknown. Working with rational expressions often requires applying algebraic techniques to simplify or solve equations.
In the given exercise, we deal with the rational expression \( \frac{5x - 12}{x^2 - 4x} \). Understanding how to manipulate such expressions is crucial in algebra, and partial fraction decomposition is a method to break these complex fractions into simpler parts. This technique is especially valuable when dealing with calculus and integrations.
In the given exercise, we deal with the rational expression \( \frac{5x - 12}{x^2 - 4x} \). Understanding how to manipulate such expressions is crucial in algebra, and partial fraction decomposition is a method to break these complex fractions into simpler parts. This technique is especially valuable when dealing with calculus and integrations.
Factoring Polynomials
Factoring is a method used to express a polynomial as a product of its simplest polynomials. This process is vital because it simplifies rational expressions, making them easier to handle.
In our example, we start by factoring the denominator \( x^2 - 4x \). Factoring yields \( x(x - 4) \), where \( x \) and \( x - 4 \) are simpler polynomials.
In our example, we start by factoring the denominator \( x^2 - 4x \). Factoring yields \( x(x - 4) \), where \( x \) and \( x - 4 \) are simpler polynomials.
- Factoring reduces complex expressions into manageable pieces.
- For partial fraction decomposition, correct factoring is the first step toward simplifying the expression.
Algebraic Fractions
Algebraic fractions are similar to regular fractions, but they contain variables as part of their expressions. The primary goal when working with these is to simplify or solve them.
In this exercise, we express a more complex fraction \( \frac{5x - 12}{x(x - 4)} \) as a sum of simpler algebraic fractions, \( \frac{3}{x} + \frac{2}{x-4} \). This simplification through partial fraction decomposition allows us to harness fundamental algebraic principles to solve equations more effectively. Understanding algebraic fractions and their manipulation is key to mastering rational expressions and making further mathematical operations more straightforward.
In this exercise, we express a more complex fraction \( \frac{5x - 12}{x(x - 4)} \) as a sum of simpler algebraic fractions, \( \frac{3}{x} + \frac{2}{x-4} \). This simplification through partial fraction decomposition allows us to harness fundamental algebraic principles to solve equations more effectively. Understanding algebraic fractions and their manipulation is key to mastering rational expressions and making further mathematical operations more straightforward.
Numerator and Denominator
In any fraction, the numerator is the top part, and the denominator is the bottom part. When dealing with rational expressions, it's essential to manipulate both parts correctly to achieve the desired result.
For the given rational expression \( \frac{5x - 12}{x^2 - 4x} \), we focus on transforming the numerator \( 5x - 12 \) and the newly factored denominator \( x(x - 4) \). By rewriting the expression in the form \( \frac{3}{x} + \frac{2}{x-4} \), understanding how numerators and denominators interact becomes clearer.
Always remember:
For the given rational expression \( \frac{5x - 12}{x^2 - 4x} \), we focus on transforming the numerator \( 5x - 12 \) and the newly factored denominator \( x(x - 4) \). By rewriting the expression in the form \( \frac{3}{x} + \frac{2}{x-4} \), understanding how numerators and denominators interact becomes clearer.
Always remember:
- The degree of the numerator should be less than the degree of the denominator when decomposing fractions.
- Equating numerators is crucial for finding the coefficients needed for partial fraction decomposition.
Equation Solving
Equation solving is about finding values that satisfy a given equation. This process is often essential when working through partial fraction decomposition.
In this case, we equate the numerators from \( A(x-4) + Bx = 5x - 12 \). This step involves simplifying and comparing coefficients from both sides of the equation.
In our exercise, the solution involves:
In this case, we equate the numerators from \( A(x-4) + Bx = 5x - 12 \). This step involves simplifying and comparing coefficients from both sides of the equation.
In our exercise, the solution involves:
- Equating the coefficients of \( x \): \( A + B = 5 \)
- Equating constant terms: \( -4A = -12 \), which gives \( A = 3 \)
- Substituting \( A \) to find \( B \): \( 3 + B = 5 \rightarrow B = 2 \)
Other exercises in this chapter
Problem 3
Sketch the region \(R\) determined by the given constraints, and label its vertices. Find the maximum value of \(C\) on \(R\) $$\begin{array}{lll} C=3 x+y ; & x
View solution Problem 3
Use the method of substitution to solve the system. $$\left\\{\begin{aligned} y^{2} &=1-x \\ x+2 y &=1 \end{aligned}\right.$$
View solution Problem 4
Find, if possible, \(A+B, A-B, 2 A,\) and \(-3 B\). $$A=\left[\begin{array}{rrr} 0 & -2 & 7 \\ 5 & 4 & -3 \end{array}\right], \quad B=\left[\begin{array}{lll} 8
View solution Problem 4
Find all the minors and cofactors of the elements in the matrix. $$\left[\begin{array}{rrr} 5 & -2 & 1 \\ 4 & 7 & 0 \\ -3 & 4 & -1 \end{array}\right]$$
View solution