Problem 4
Question
Find the moment of inertia (in \(\mathrm{g} \cdot \mathrm{cm}^{2}\) ) and the radius of gyration (in \(\mathrm{cm}\) ) with respect to the origin of each of the given arrays of masses located at the given points on the \(x\) -axis. $$3.4 \mathrm{g} \text { at }(-1.5,0), 6.0 \mathrm{g} \text { at }(2.1,0), 2.6 \mathrm{g} \text { at }(3.8,0)$$
Step-by-Step Solution
Verified Answer
Moment of inertia is 71.65 \( \text{g} \cdot \text{cm}^2\); radius of gyration is 2.442 \( \text{cm} \).
1Step 1: Define Moment of Inertia
The moment of inertia \(I\) for a point mass is calculated using the formula \(I = m imes r^2\), where \(m\) is the mass and \(r\) is the distance from the point to the axis of rotation (origin in this case). We will calculate the moment of inertia for each mass first.
2Step 2: Calculate Moment of Inertia for Each Mass
For the mass at \((-1.5, 0)\):\[I_1 = 3.4 imes (-1.5)^2 = 3.4 imes 2.25 = 7.65 \, \text{g} \cdot \text{cm}^2\]For the mass at \((2.1, 0)\):\[I_2 = 6.0 imes (2.1)^2 = 6.0 imes 4.41 = 26.46 \, \text{g} \cdot \text{cm}^2\]For the mass at \((3.8, 0)\):\[I_3 = 2.6 imes (3.8)^2 = 2.6 imes 14.44 = 37.54 \, \text{g} \cdot \text{cm}^2\]
3Step 3: Total Moment of Inertia
Add the individual moments of inertia to find the total moment of inertia:\[I_{total} = I_1 + I_2 + I_3 = 7.65 + 26.46 + 37.54 = 71.65 \, \text{g} \cdot \text{cm}^2\]
4Step 4: Define Radius of Gyration
The radius of gyration \(k\) is defined by the formula \(k = \sqrt{\frac{I_{total}}{m_{total}}}\), where \(I_{total}\) is the total moment of inertia and \(m_{total}\) is the total mass of all points.
5Step 5: Calculate Total Mass
The total mass \(m_{total}\) is the sum of all point masses:\[m_{total} = 3.4 + 6.0 + 2.6 = 12.0 \, \text{g}\]
6Step 6: Calculate Radius of Gyration
Substitute the values into the radius of gyration formula:\[k = \sqrt{\frac{71.65}{12.0}} = \sqrt{5.9708} \approx 2.442\, \text{cm}\]
Key Concepts
Understanding Radius of GyrationMass Distribution and its ImpactPhysics Education: Making Learning AccessibleCalculations in Mechanics
Understanding Radius of Gyration
The radius of gyration is a concept often used in physics and engineering when analyzing the distribution of mass around an axis. It provides insight into how a body's mass is distributed relative to a given axis. This can influence how the body will behave when it is rotating.
Most simply, the radius of gyration is defined as the square root of the ratio of the total moment of inertia and total mass. Mathematically, it's given by:
Understanding the radius of gyration is crucial in structural engineering and design, as it helps determine how structures bear loads and resist bending and twisting.
Most simply, the radius of gyration is defined as the square root of the ratio of the total moment of inertia and total mass. Mathematically, it's given by:
- \( k = \sqrt{\frac{I_{total}}{m_{total}}} \)
Understanding the radius of gyration is crucial in structural engineering and design, as it helps determine how structures bear loads and resist bending and twisting.
Mass Distribution and its Impact
In mechanics, the distribution of mass plays a central role in determining how an object will rotate about an axis. Masses located farther from the axis contribute more to the moment of inertia, which means they have a larger effect on the rotational properties of the system.
For the given exercise, consider three different masses placed along the x-axis. Each mass has a unique position, which affects its contribution to the total moment of inertia. The formula for moment of inertia for a point mass is:
By understanding and manipulating mass distribution, engineers and physicists can influence the rotational dynamics and stability of mechanical systems, which is vital in everything from designing bridges to creating athletic gear.
For the given exercise, consider three different masses placed along the x-axis. Each mass has a unique position, which affects its contribution to the total moment of inertia. The formula for moment of inertia for a point mass is:
- \( I = m \cdot r^2 \)
By understanding and manipulating mass distribution, engineers and physicists can influence the rotational dynamics and stability of mechanical systems, which is vital in everything from designing bridges to creating athletic gear.
Physics Education: Making Learning Accessible
Physics education focuses heavily on making abstract concepts tangible, especially ones involving complex calculations like moment of inertia and radius of gyration. By starting with basic principles and gradually building towards more complex problems, students develop a stronger understanding.
Educators often use step-by-step solutions like the one provided to break down challenging topics. This approach helps students follow the logic and mathematical operations required in physics, ensuring that they comprehend each part of the process before moving on to more advanced topics.
Educators often use step-by-step solutions like the one provided to break down challenging topics. This approach helps students follow the logic and mathematical operations required in physics, ensuring that they comprehend each part of the process before moving on to more advanced topics.
- Visual aids, such as diagrams and animations, can also help clarify these concepts.
- Active problem-solving and discussions promote engagement and deeper learning.
Calculations in Mechanics
Mechanics involves understanding and applying various mathematical principles to predict and analyze the motion of objects. Fundamental to this is the ability to perform accurate and logical calculations.
Calculations for concepts like moment of inertia and radius of gyration require careful consideration of the formulas involved, ensuring each variable and constant is applied correctly.
Calculations for concepts like moment of inertia and radius of gyration require careful consideration of the formulas involved, ensuring each variable and constant is applied correctly.
- Step-by-step breakdowns aid in comprehending the cumulative processes in calculations.
- Precision is key in yielding correct results, as small errors can lead to significant deviations.
Other exercises in this chapter
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