Problem 4
Question
Find the first and second derivatives. $$ w=3 z^{7}-7 z^{3}+21 z^{2} $$
Step-by-Step Solution
Verified Answer
First derivative: \( w' = 21z^6 - 21z^2 + 42z \), Second derivative: \( w'' = 126z^5 - 42z + 42 \).
1Step 1: Understand the Function
The given function is a polynomial: \[ w = 3z^7 - 7z^3 + 21z^2 \] We need to find its first and second derivatives with respect to \( z \).
2Step 2: Apply the Power Rule for the First Derivative
To find the first derivative, \( w' \), we apply the power rule: \( d/dz \> a z^n = a n z^{n-1} \).1. Differentiate \( 3z^7 \): \[ d/dz \>(3z^7) = 3 imes 7 z^{6} = 21z^6 \]2. Differentiate \( -7z^3 \): \[ d/dz \>(-7z^3) = -7 imes 3 z^{2} = -21z^2 \]3. Differentiate \( 21z^2 \): \[ d/dz \>(21z^2) = 21 imes 2 z^{1} = 42z \]Combine these results to get:\[ w' = 21z^6 - 21z^2 + 42z \]
3Step 3: Apply the Power Rule for the Second Derivative
Now, differentiate the first derivative to find the second derivative, \( w'' \).1. Differentiate \( 21z^6 \): \[ d/dz \>(21z^6) = 21 imes 6 z^{5} = 126z^5 \]2. Differentiate \( -21z^2 \): \[ d/dz \>(-21z^2) = -21 imes 2 z^{1} = -42z \]3. Differentiate \( 42z \): \[ d/dz \>(42z) = 42 \]Combine these results to get:\[ w'' = 126z^5 - 42z + 42 \]
Key Concepts
Polynomial FunctionsPower RuleFirst DerivativeSecond Derivative
Polynomial Functions
Polynomial functions are mathematical expressions that are built from variables and constants, using only addition, subtraction, multiplication, and positive integer exponents. A general polynomial function can be written in the form of
In our exercise, the polynomial function given is:
Understanding polynomial functions is crucial because they serve as the foundation for many concepts in calculus, including the differentiation process used in finding derivatives.
- \( f(x) = a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \)
In our exercise, the polynomial function given is:
- \( w = 3z^7 - 7z^3 + 21z^2 \)
Understanding polynomial functions is crucial because they serve as the foundation for many concepts in calculus, including the differentiation process used in finding derivatives.
Power Rule
The power rule is a basic and powerful tool for finding derivatives of polynomial functions. It simplifies the process of differentiation when dealing with terms where variables are raised to exponents. The rule states:
When applying the power rule, you multiply the original exponent by the coefficient of that term and then subtract one from the exponent.
In our exercise, we applied the power rule to each term:
- \( \frac{d}{dz} (a z^n) = a n z^{n-1} \)
When applying the power rule, you multiply the original exponent by the coefficient of that term and then subtract one from the exponent.
In our exercise, we applied the power rule to each term:
- To \( 3z^7 \) we get \( 21z^6 \).
- To \( -7z^3 \) we get \( -21z^2 \).
- To \( 21z^2 \) we get \( 42z \).
First Derivative
The first derivative of a function provides information about the rate of change of the function’s value with respect to a change in the variable. It is often denoted as \( w' \) or \( \frac{dw}{dz} \) for a function \( w \) of \( z \).
In physical terms, if a function describes position over time, its first derivative represents velocity.
In our exercise, the first derivative of the polynomial \( w = 3z^7 - 7z^3 + 21z^2 \) is calculated as follows:
The first derivative is used to find critical points, determine where a function is increasing or decreasing, and is a fundamental step towards understanding the overall shape of the function’s graph.
In physical terms, if a function describes position over time, its first derivative represents velocity.
In our exercise, the first derivative of the polynomial \( w = 3z^7 - 7z^3 + 21z^2 \) is calculated as follows:
- \( w' = 21z^6 - 21z^2 + 42z \)
The first derivative is used to find critical points, determine where a function is increasing or decreasing, and is a fundamental step towards understanding the overall shape of the function’s graph.
Second Derivative
The second derivative of a function is the derivative of its first derivative. It provides insight into the concavity of the function and how the rate of change of the rate of change occurs. For a function \( w \), the second derivative is denoted by \( w'' \) or even \( \frac{d^2w}{dz^2} \).
A positive second derivative indicates that the function is concave up (shaped like a cup), while a negative second derivative indicates concave down (shaped like a cap).
From the first derivative \( w' = 21z^6 - 21z^2 + 42z \) that we calculated, we find the second derivative by further differentiating:
The second derivative is crucial for analyzing the behavior of the function, especially in determining points of inflection and optimizing its behavior.
A positive second derivative indicates that the function is concave up (shaped like a cup), while a negative second derivative indicates concave down (shaped like a cap).
From the first derivative \( w' = 21z^6 - 21z^2 + 42z \) that we calculated, we find the second derivative by further differentiating:
- \( w'' = 126z^5 - 42z + 42 \)
The second derivative is crucial for analyzing the behavior of the function, especially in determining points of inflection and optimizing its behavior.
Other exercises in this chapter
Problem 4
Find \(d y / d x\) $$ y=\sqrt{x} \sec x+3 $$
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derivatives as specified. $$ k(z)=\frac{1-z}{2 z} ; \quad k^{\prime}(-1), k^{\prime}(1), k^{\prime}(\sqrt{2}) $$
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In Exercises \(1-8,\) given \(y=f(u)\) and \(u=g(x),\) find \(d y / d x=\) \(d y / d x=f^{\prime}(g(x)) g^{\prime}(x)\) $$ y=\sqrt{u}, \quad u=\sin x $$
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