Problem 4
Question
Find the domain and range of the function. Then evaluate \(f\) at the given \(x\) -value. \(f(x)=|x-2|, x=2\)
Step-by-Step Solution
Verified Answer
The domain of the function \(f(x) = |x - 2|\) is all real numbers, the range is \(y \geq 0\), and \(f(2) = 0\).
1Step 1: Find the Domain
For any real function, the domain is the set of all real numbers for which the function is defined. Here, the function \(f(x) = |x - 2|\) is defined for all values of \(x\), because the absolute value function \(|x|\) is defined for all \(x\). So, the domain of function \(f\) is all real numbers.
2Step 2: Find the Range
The output of the absolute value function \(|x|\) is always non-negative, because it represents the distance of \(x\) from zero. Similarly, the output of the function \(f(x) = |x - 2|\), which represents the distance of \(x\) from 2, will also be a non-negative real number. So, the range of the function \(f\) is \(y \geq 0\).
3Step 3: Evaluate the function at \(x=2\)
Now we substitute \(x = 2\) into the function to evaluate it. So, \(f(2) = |2 - 2| = |0| = 0\).
Key Concepts
Absolute Value FunctionReal NumbersFunction Evaluation
Absolute Value Function
The absolute value function is a key player in mathematics, as it measures how far a number is from zero on a number line. Think of it like measuring distance without caring about which direction you go. The absolute value of a number, represented as
In the context of the function \(f(x) = |x-2|\), it does not matter if \(x\) is greater than or less than 2; what matters is the distance from 2. This is why the expression inside the absolute value, \(x-2\), changes sign depending on whether \(x\) is smaller or larger than 2, but the absolute value itself remains positive.
Key points to remember about absolute values:
- \(|x|\),
In the context of the function \(f(x) = |x-2|\), it does not matter if \(x\) is greater than or less than 2; what matters is the distance from 2. This is why the expression inside the absolute value, \(x-2\), changes sign depending on whether \(x\) is smaller or larger than 2, but the absolute value itself remains positive.
Key points to remember about absolute values:
- They convert any negative values to positive.
- They help calculate distances or differences without regard to direction.
Real Numbers
Real numbers encompass all the numbers that exist on the number line, which includes both rational numbers (like 1/2, 5, -3) and irrational numbers (like \(\pi\) and \(\sqrt{2}\)).
The domain of a function describes all possible input values, and here, it consists of real numbers. For instance, when dealing with \(f(x) = |x - 2|\), there's no restriction on \(x\), meaning any real number can potentially be plugged into the function.
A few things to keep in mind about real numbers:
The domain of a function describes all possible input values, and here, it consists of real numbers. For instance, when dealing with \(f(x) = |x - 2|\), there's no restriction on \(x\), meaning any real number can potentially be plugged into the function.
A few things to keep in mind about real numbers:
- They can be positive, negative, or zero.
- They can be whole numbers, fractions, or decimals.
- They represent continuous points on the number line without any gaps.
Function Evaluation
Function evaluation is about plugging a specific value of \(x\) into a function and finding the corresponding output. This is like asking, "What happens at this certain point?"
Let's take the function \(f(x) = |x - 2|\) and evaluate it at \(x = 2\). Here’s how it works:
Let's take the function \(f(x) = |x - 2|\) and evaluate it at \(x = 2\). Here’s how it works:
- Replace \(x\) with the specified value: \(f(2) = |2 - 2|\).
- Simplify the expression inside the absolute value: \(f(2) = |0|\).
- Since the absolute value of zero is zero, we find \(f(2) = 0\).
Other exercises in this chapter
Problem 4
Find the inverse function of the function \(f\) given by the set of ordered pairs. \(\\{(6,-2),(5,-3),(4,-4),(3,-5)\\}\)
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Describe the sequence of transformations from \(f(x)=x^{2}\) to \(g\). Then sketch the graph of \(g\) by hand. Verify with a graphing utility. \(g(x)=(x-3)^{2}\
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For urban consumers of educational and communication materials, the Consumer Price Index giving the dollar amount equal to the buying power of \(\$ 100\) in Dec
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(a) plot the points, (b) find the distance between the points, and (c) find the midpoint of the line segment joining the points. \((-7,3),(2,-9)\)
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