Problem 4
Question
Find all the generators of \(\mathbb{Z}_{10}, \mathbb{Z}_{12},\) and \(\mathbb{Z}_{15}\).
Step-by-Step Solution
Verified Answer
Generators of \(\mathbb{Z}_{10}\) are \(1, 3, 7, 9\); of \(\mathbb{Z}_{12}\) are \(1, 5, 7, 11\); and of \(\mathbb{Z}_{15}\) are \(1, 2, 4, 7, 8, 11, 13, 14\).
1Step 1: Understanding Generators of Cyclic Groups
In a cyclic group \(Z_n\), a generator is an element whose powers produce every element of the group. For \(Z_n\) to have a generator \(g\), \(g\) must be relatively prime to \(n\). This means that the greatest common divisor (GCD) of \(g\) and \(n\) is 1.
2Step 2: Finding Generators of \(\mathbb{Z}_{10}\)
For \(Z_{10}\), the elements are \(\{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 \}\). We need to find the elements that have GCD equal to 1 with 10. These elements are: \(1\), \(3\), \(7\), and \(9\). Hence, these are the generators of \(Z_{10}\).
3Step 3: Finding Generators of \(\mathbb{Z}_{12}\)
For \(Z_{12}\), the elements are \(\{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 \}\). The elements that are relatively prime to 12 are those with GCD equal to 1. These elements are: \(1\), \(5\), \(7\), and \(11\). Therefore, the generators of \(Z_{12}\) are \(1\), \(5\), \(7\), and \(11\).
4Step 4: Finding Generators of \(\mathbb{Z}_{15}\)
For \(Z_{15}\), we consider the elements \(\{ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 \}\). The elements that are coprime to 15 are \(1\), \(2\), \(4\), \(7\), \(8\), \(11\), \(13\), and \(14\). Thus, the generators of \(Z_{15}\) are \(1\), \(2\), \(4\), \(7\), \(8\), \(11\), \(13\), and \(14\).
Key Concepts
GeneratorsGreatest Common Divisor (GCD)Relatively Prime Numbers
Generators
In the realm of cyclic groups, the concept of a "generator" is a cornerstone. A generator of a cyclic group is an element that, through its repeated multiplication, hits every other element within the group. Think of it as the key player who can bring every other member into the spotlight. In mathematical terms, if you have a cyclic group \(\mathbb{Z}_n\), then a generator \(g\) must be an element such that:
- \(g, g^2, g^3, \ldots, g^k\) will produce all elements of the group \(\mathbb{Z}_n\).
Greatest Common Divisor (GCD)
The Greatest Common Divisor (GCD) is a foundational concept in mathematics. It is essential for understanding generators of cyclic groups. The GCD of two numbers is the largest positive integer that divides both numbers without leaving a remainder. Formally, for two integers \(a\) and \(b\), the GCD is denoted as \(\text{GCD}(a, b)\). Consider the numbers 8 and 12. Their common divisors are 1, 2, and 4. Therefore, their GCD is 4 - the greatest among them.
- The GCD is crucial because a generator \(g\) for a cyclic group \(\mathbb{Z}_n\) requires that \(\text{GCD}(g, n) = 1\).
Relatively Prime Numbers
Numbers are considered relatively prime if their greatest common divisor (GCD) is 1. This property is pivotal for identifying generators in cyclic groups. Relatively prime numbers do not have any common factors other than 1, meaning they do not "fit" into each other in a neat multiplication table.
- For instance, 7 and 20 are relatively prime because their GCD is 1.
Other exercises in this chapter
Problem 2
Find the order of the indicated element in the indicated group. $$ 4 \in \mathbb{Z}_{10} $$
View solution Problem 3
Let \(G\) be a group and \(a \in G\) an element of order \(|a|=6\). (a) Write all the elements of \(\langle a\rangle\). (b) Find in \(\langle a\rangle\) the ele
View solution Problem 4
In Exercises 1 through 5 determine which of the indicated functions is a permutation of the indicated set. $$ f: U(5) \rightarrow U(5), \text { where } f(x)=x^{
View solution Problem 4
Show that the indicated set \(G\) with the specified operation forms a group by showing that the four axioms in the definition of a group are satisfied. \(G=C^{
View solution