Problem 4
Question
Fill in the blanks. The terms \(x(x-1)\) and \(4(x-1)\) have the common __________ factor \(x-1\)
Step-by-Step Solution
Verified Answer
Common factor is \(x-1\).
1Step 1: Understanding the Problem
We need to find the common factor between the terms \(x(x-1)\) and \(4(x-1)\). A common factor means a factor that is present in both terms.
2Step 2: Breaking Down the Terms
Let's look at each term individually. The first term is \(x(x-1)\), which includes the factor \(x-1\). The second term is \(4(x-1)\), which also includes the factor \(x-1\).
3Step 3: Identifying the Common Factor
We notice that both terms \(x(x-1)\) and \(4(x-1)\) have the factor \(x-1\) in common. This makes \(x-1\) the common factor between the two expressions.
Key Concepts
Common factorAlgebraic expressionsPolynomial factorization
Common factor
A common factor is an element that is shared by two or more terms in an algebraic expression. To better understand what a common factor is, let's break down the expressions. Consider the terms \(x(x-1)\) and \(4(x-1)\). In these expressions, the factor \(x-1\) appears in both terms. This means that \(x-1\) is a common factor.
- The common factor is crucial for simplifying expressions.
- It helps in factoring expressions further by identifying shared elements.
- Having a common factor makes it possible to simplify complex expressions into simpler ones.
Algebraic expressions
An algebraic expression is a combination of numbers, variables, and operations. Algebraic expressions can represent real-world quantities in a mathematical form. For example, \(x(x-1)\) and \(4(x-1)\) are algebraic expressions. They contain variables \(x\), constants, and operations like multiplication and subtraction.Some characteristics of algebraic expressions include:
- They can represent both simple and complex mathematical relationships.
- They can be evaluated by substituting values for the variables.
- Expressions can be manipulated using mathematical operations such as addition, subtraction, multiplication, and division.
Polynomial factorization
Polynomial factorization is the process of expressing a polynomial as a product of its factors. Factoring polynomials is crucial because it simplifies expressions and helps solve equations. Consider the polynomial terms \(x(x-1)\) and \(4(x-1)\) from the given problem. They can be factored to reveal the common factor \(x-1\). Key points about polynomial factorization:
- It reduces complex polynomials into simpler ones, making them easier to work with.
- Helps in solving polynomial equations by finding roots.
- It sheds light on the structure of polynomials, showing how they can be broken down into their component parts.
Other exercises in this chapter
Problem 4
Fill in the blanks. Consider \(49 x^{2}-28 x y+4 y^{2}.\) The first term is the square of____. The last term is the square of____. The middle term is the opposi
View solution Problem 4
Fill in the blanks. A trinomial is factored _____ when no factor can be factored further.
View solution Problem 5
For each of the following polynomials, which factoring method would you use first? $$ x^{2}+18 x+81 $$
View solution Problem 5
Fill in the blanks. a. \(x^{2}+2 x y+y^{2}=(\quad+\quad)^{2}\) b. \(x^{2}-2 x y+y^{2}=(x \quad y)^{2}\) \(-\quad)\) c. \(x^{2}-y^{2}=(x \quad y)(\quad-\quad)\)
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