Problem 4
Question
Factor each polynomial. \(x^{3}-27\)
Step-by-Step Solution
Verified Answer
The polynomial \(x^3 - 27\) factors to \((x - 3)(x^2 + 3x + 9)\).
1Step 1: Identify the Form of the Polynomial
The polynomial given is in the form of a difference of cubes, which is expressed as \(a^3 - b^3\). In this problem, \(x^3\) is the cube term and \(27\) can be rewritten as \(3^3\). Hence, the expression \(x^3 - 27\) is a difference of cubes.
2Step 2: Use the Difference of Cubes Formula
The formula for factoring a difference of cubes is: \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\), where \(a = x\) and \(b = 3\) in this case.
3Step 3: Substitute Values into the Formula
Substitute \(a = x\) and \(b = 3\) into the difference of cubes formula:\((x - 3)(x^2 + 3x + 9)\). This completes the factorization of the polynomial.
Key Concepts
Difference of CubesPolynomial ExpressionAlgebraic Formula
Difference of Cubes
The difference of cubes is a special type of polynomial that can be factored using a specific formula. This formula applies when we have an expression like \(a^3 - b^3\), where both \(a\) and \(b\) are perfect cubes. In our problem, the expression \(x^3 - 27\) is recognized as a difference of cubes. Here, \(x^3\) is the cube of \(x\), and \(27\) is the cube of \(3\).
To factor such expressions, we use the formula:
To factor such expressions, we use the formula:
- \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\)
Polynomial Expression
A polynomial expression is a mathematical expression that consists of variables and coefficients. These expressions involve operations like addition, subtraction, multiplication, and non-negative integer exponents of variables. In the case of our example, \(x^3 - 27\) is a polynomial expression consisting of two terms.
Each term in a polynomial is composed of a coefficient (a constant value), a variable (like \(x\)), and an exponent (which shows the power to which the variable is raised). For instance:
Each term in a polynomial is composed of a coefficient (a constant value), a variable (like \(x\)), and an exponent (which shows the power to which the variable is raised). For instance:
- In \(x^3\), the term has a coefficient of 1, a variable \(x\), and an exponent 3.
- In \(27\), the term is a constant, which can also be seen as \(3^3\), a perfect cube.
Algebraic Formula
An algebraic formula is a mathematical equation involving variables and constants. It provides a rule or pattern that helps solve problems or understand relationships between different mathematical elements. For instance, the difference of cubes formula \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\) is an algebraic formula that's invaluable in factoring polynomials.
Using algebraic formulas involves identifying the formula that applies to your specific problem, substituting the appropriate values into the formula, and simplifying the expression as needed. In our exercise, once we identify \(a = x\) and \(b = 3\), we can easily substitute these values into the difference of cubes formula to get
Using algebraic formulas involves identifying the formula that applies to your specific problem, substituting the appropriate values into the formula, and simplifying the expression as needed. In our exercise, once we identify \(a = x\) and \(b = 3\), we can easily substitute these values into the difference of cubes formula to get
- \((x - 3)(x^2 + 3x + 9)\)
Other exercises in this chapter
Problem 4
Solve each equation by using the Square Root Property. \(9 x^{2}-24 x+16=2\)
View solution Problem 4
Simplify. $$ \sqrt{\frac{120}{9}} $$
View solution Problem 4
Solve each equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located. $$ -x^{2}-7 x=0 $$
View solution Problem 4
Complete parts a-c for each quadratic function. a. Find the \(y\) -intercept, the equation of the axis of symmetry, and the \(x\) -coordinate of the vertex. b.
View solution