Problem 4
Question
Express the number in the form \(a / b,\) where \(a\) and \(b\) are integers. $$\frac{2^{0}+0^{2}}{2+0}$$
Step-by-Step Solution
Verified Answer
The number is expressed as \(\frac{1}{2}\).
1Step 1: Simplify the Numerator
The numerator of the given expression is \(2^0 + 0^2\). Since any number raised to the power of zero is 1, \(2^0 = 1\). And any number raised to the power of something, when that number is zero, is also zero, so \(0^2 = 0\). Therefore, the simplified numerator is \(1 + 0 = 1\).
2Step 2: Simplify the Denominator
The denominator of the expression is \(2 + 0\). Adding these numbers gives us \(2\).
3Step 3: Final Fraction
With the simplified numerator and denominator, we can express the number as a fraction. Therefore, the fraction is \(\frac{1}{2}\).
Key Concepts
Expression SimplificationExponentsInteger Arithmetic
Expression Simplification
Expression Simplification involves reducing a complex expression to its simplest form, making it easier to understand and work with. In the given exercise, simplifying the expression \[\frac{2^{0}+0^{2}}{2+0}\]requires breaking it down into smaller parts.
- First, we simplified the numerator \(2^0 + 0^2\).
- Then, we simplified the denominator \(2 + 0\).
- The term \(2^0\) evaluates to 1 because any non-zero base raised to the power of zero equals 1.
- Secondly, \(0^2\) simplifies to 0 because zero raised to any power remains zero.
- Adding these gives a numerator of 1.
- The denominator \(2 + 0\) simplifies directly to 2.
Exponents
Exponents are a shorthand way to represent repeated multiplication of the same factor. They are written as a number (the base) raised to an exponent (or power). For instance, in the expression \(2^0\), 2 is the base and 0 is the exponent.
- An important exponent rule is that any non-zero number raised to the power of zero equals 1. Therefore, \(2^0 = 1\).
- Another rule is that zero raised to any positive power is zero, reflecting that zero multiplied by itself any number of times will always be zero. Consequently, \(0^2 = 0\).
Integer Arithmetic
Integer Arithmetic focuses on performing operations like addition, subtraction, multiplication, and division on integers, which are whole numbers. In the exercise, Integer Arithmetic was used to simplify both the numerator and the denominator.
- The numerator involved the addition of two integer values, \(1 + 0\), which results in an integer, 1.
- The denominator consisted of the addition, \(2 + 0\), leading to the integer 2.
Other exercises in this chapter
Problem 3
Express as a polynomial. $$\frac{8 x^{2} y^{3}-10 x^{3} y}{2 x^{2} y}$$
View solution Problem 3
Write the expression in the form \(a+b i,\) where \(a\) and \(b\) are real numbers. $$(7-6 i)-(-11-3 i)$$
View solution Problem 4
Replace the symbol \square with elther \(,\) or \(=\) to make the resulting statement true. (a) \(-3 \square-5\) (b) \(\frac{\pi}{4} \square 0.8\) (c) \(\sqrt{2
View solution Problem 4
Solve the equation. \((x+5)^{2}+3=(x-2)^{2}\)
View solution