Problem 4
Question
Explain why \(15 \mathrm{~g}\) of steam at \(100^{\circ} \mathrm{C}\) melts more ice than \(15 \mathrm{~g}\) of liquid water at \(100^{\circ} \mathrm{C}\).
Step-by-Step Solution
Verified Answer
Steam at 100°C releases more heat (40170 J) than water at 100°C (6270 J), thus melting more ice.
1Step 1: Determine the heat released by steam
First, calculate the heat released when 15 g of steam at 100°C condenses into water at 100°C. The heat of vaporization of water is approximately 2260 J/g. The formula is given by \( Q = mL \), where \( m \) is the mass and \( L \) is the heat of vaporization. \( Q = 15 \text{ g} \times 2260 \text{ J/g} = 33900 \text{ J} \).
2Step 2: Calculate the heat released when steam cools to 0°C
After condensing, the water from steam must cool to 0°C. Using the formula \( Q = mc\Delta T \), where \( c \) is the specific heat capacity of water (4.18 J/g°C) and \( \Delta T = 100°C \), the heat is \( Q = 15 \text{ g} \times 4.18 \text{ J/g°C} \times 100°C = 6270 \text{ J} \).
3Step 3: Total heat released by steam
Add the heat released from condensation and cooling together: \( 33900 \text{ J} + 6270 \text{ J} = 40170 \text{ J} \).
4Step 4: Calculate the heat released by liquid water
Water at 100°C only needs to cool to 0°C, using the same formula as above, \( Q = 15 \text{ g} \times 4.18 \text{ J/g°C} \times 100°C = 6270 \text{ J} \).
5Step 5: Comparison of heat released
The total heat released by steam (40170 J) is much greater than that released by equivalent hot water (6270 J). Therefore, steam melts more ice, due to both the latent heat of vaporization and subsequent cooling.
Key Concepts
Latent Heat of VaporizationSpecific Heat CapacityPhase Change Cooling
Latent Heat of Vaporization
When a substance changes from a liquid to a gas, it requires additional energy known as the latent heat of vaporization. This energy is necessary for overcoming the intermolecular forces in a liquid to transform it into a gaseous state. In our steam example, the latent heat of vaporization for water is approximately 2260 J/g. This means that to convert 1 gram of water at 100°C into steam at the same temperature, 2260 joules of energy are needed.
In practical terms:
In practical terms:
- For 15 grams of steam, the energy associated with this phase change is significant, amounting to 33,900 joules.
- This energy is released when the steam condenses back into liquid water.
Specific Heat Capacity
Specific heat capacity is a property of materials that describes how much heat is required to change the temperature of a certain mass by 1°C. For water, the specific heat capacity is 4.18 J/g°C. This property plays a critical role in the cooling of water.
An example statement:
An example statement:
- When 15 grams of water cools from 100°C to 0°C, it releases energy calculated as: 15 g × 4.18 J/g°C × 100°C = 6,270 joules.
Phase Change Cooling
Phase change cooling refers to the process where a substance releases or absorbs heat during a change in its state (phase) without a temperature change. In the case of steam, two major processes occur:
- Condensation: Steam releases latent heat as it turns into water, delivering significant heat energy.
- Cooling of Condensed Water: Subsequent cooling of this water releases additional energy as it cools from 100°C to 0°C.
Other exercises in this chapter
Problem 2
Describe how you could purify iodine by sublimation.
View solution Problem 3
Describe vapor pressure in molecular terms. What do we mean by saying it involves a dynamic equilibrium?
View solution Problem 5
Why is the heat of fusion of a substance smaller than its heat of vaporization?
View solution Problem 6
Explain why evaporation leads to cooling of the liquid.
View solution