Problem 4
Question
Exer. 1-20: Sketch the graph of the equation, and label the \(x\) - and \(y\)-intercepts. $$ y=-2 x-3 $$
Step-by-Step Solution
Verified Answer
Y-intercept: (0, -3); X-intercept: \(-\frac{3}{2}, 0\).
1Step 1: Understand the Form of the Equation
The given equation is in the form of a linear equation, which is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Here, the equation is \( y = -2x - 3 \).
2Step 2: Identify the Y-intercept
The y-intercept is the value of \( y \) when \( x \) is 0. By setting \( x = 0 \) in the equation, we have \( y = -3 \). Thus, the y-intercept is \( (0, -3) \).
3Step 3: Find the X-intercept
The x-intercept is the value of \( x \) when \( y \) is 0. Set \( y = 0 \) in the equation and solve for \( x \):\[ 0 = -2x - 3 \]Add 3 to both sides:\[ 3 = -2x \]Divide by -2:\[ x = -\frac{3}{2} \]Thus, the x-intercept is \( \left(-\frac{3}{2}, 0\right) \).
4Step 4: Sketch the Graph
Plot the x-intercept \( \left(-\frac{3}{2}, 0\right) \) and the y-intercept \( (0, -3) \) on the coordinate plane. Draw a straight line through these two points since the equation represents a linear function.
5Step 5: Review the Graph
Make sure the line has a downward slope, consistent with the negative slope \( m = -2 \). The line passes through the intercept point \( (0, -3) \) and \( \left(-\frac{3}{2}, 0\right) \), confirming correctness.
Key Concepts
graphing linear equationsx-interceptsy-intercepts
graphing linear equations
Graphing a linear equation involves creating a visual representation of the equation on a coordinate plane. Linear equations are represented by straight lines, and they typically follow the format:
- \( y = mx + b \)
x-intercepts
X-intercepts are where the graph of the equation crosses the x-axis. At these points, the value of \( y \) is zero. To find the x-intercept for \( y = -2x - 3 \), replace \( y \) with 0 and solve for \( x \):
Solve \( 0 = -2x - 3 \), by adding 3 to both sides:\[ 3 = -2x \]Then divide by -2:\[ x = -\frac{3}{2} \]This calculation shows that the x-intercept is \( \left(-\frac{3}{2}, 0\right) \). Knowing how to find the x-intercept is crucial for graphing because it provides a critical point through which the line will pass.
y-intercepts
The y-intercept is the point at which the graph crosses the y-axis. At the y-intercept, the value of \( x \) is zero. To determine the y-intercept of \( y = -2x - 3 \), substitute \( x = 0 \) into the equation:Substitute as follows:\[ y = -2(0) - 3 \]\[ y = -3 \]This tells us that the y-intercept is \( (0, -3) \). Plotting the y-intercept on the graph is a great start to visualizing the linear equation. Like x-intercepts, y-intercepts help define the trajectory of the graphed line and are essential for accurately drawing linear relationships.
Other exercises in this chapter
Problem 4
If \(f(x)=\frac{x}{x-3}\), find \(f(-2), f(0)\), and \(f(3)\)
View solution Problem 4
Exer. 1-6: Sketch the line through \(A\) and \(B\), and find its slope \(m\). $$ A(5,-1), \quad B(5,6) $$
View solution Problem 4
Plot the points \(A(0,0), B(1,-1), C(3,-3), D(-1,1)\), and \(E(-3,3)\). Describe the set of all points of the form \((a,-a)\), where \(a\) is a real number.
View solution Problem 5
Exer. 3-12: Determine whether \(f\) is even, odd, or neither even nor odd. $$ f(x)=3 x^{4}+2 x^{2}-5 $$
View solution