Problem 4
Question
Evaluate the limits. $$ \lim _{x \rightarrow-\infty} \frac{2 x+1}{3-4 x} $$
Step-by-Step Solution
Verified Answer
The limit is \(-\frac{1}{2}\).
1Step 1: Identify the Limit Type
The limit to evaluate is \( \lim _{x \rightarrow -\infty} \frac{2x+1}{3-4x} \). Since \( x \to -\infty \) indicates that \( x \) is approaching negative infinity, we are considering the behavior of a rational function as \( x \) becomes very large in the negative direction.
2Step 2: Analyze Degrees of Polynomials
In the rational function \( \frac{2x+1}{3-4x} \), the numerator has a degree of 1 (\( 2x+1 \)) and the denominator also has a degree of 1 (\( 3-4x \)). Since both the numerator and the denominator have the same degree, the limit as \( x \to -\infty \) will be determined by the leading coefficients.
3Step 3: Determine the Leading Coefficients
The leading coefficient of the numerator \( 2x \) is 2, and the leading coefficient of the denominator \( -4x \) is -4. Since the degrees are the same, the limit will equal the ratio of the leading coefficients. Therefore, the limit is \( \frac{2}{-4} \).
4Step 4: Simplify the Ratio
Simplify the ratio \( \frac{2}{-4} \) to find the limit. The simplification yields \( \frac{2}{-4} = -\frac{1}{2} \).
5Step 5: State the Final Result
The evaluated limit as \( x \to -\infty \) for the given function is \(-\frac{1}{2}\). Therefore, \( \lim _{x \rightarrow -\infty} \frac{2x+1}{3-4x} = -\frac{1}{2} \).
Key Concepts
Rational FunctionLeading CoefficientsPolynomial Degree Analysis
Rational Function
A rational function is a type of fraction where both the numerator and denominator are polynomials. Polynomials are mathematical expressions that involve variables raised to various powers, each multiplied by coefficients. The general form of a rational function is \( \frac{P(x)}{Q(x)} \), where \( P(x) \) and \( Q(x) \) are polynomial functions and \( Q(x) eq 0 \).
Rational functions appear often in mathematics due to their versatile nature. They are predominately used in calculus to explore limits and continuity. In our exercise, the function \( \frac{2x+1}{3-4x} \) is a rational function because it is a ratio of two polynomials: \( 2x+1 \) and \( 3-4x \).
Rational functions have interesting properties, especially regarding limits. As \( x \) approaches infinity or negative infinity, their behavior is largely determined by the degrees and leading coefficients of the numerator and denominator polynomials.
Rational functions appear often in mathematics due to their versatile nature. They are predominately used in calculus to explore limits and continuity. In our exercise, the function \( \frac{2x+1}{3-4x} \) is a rational function because it is a ratio of two polynomials: \( 2x+1 \) and \( 3-4x \).
Rational functions have interesting properties, especially regarding limits. As \( x \) approaches infinity or negative infinity, their behavior is largely determined by the degrees and leading coefficients of the numerator and denominator polynomials.
Leading Coefficients
In a polynomial, the leading coefficient is the number in front of the variable with the highest exponent. This coefficient is crucial for determining the end behavior of a polynomial function and, by extension, a rational function.
For our exercise, the rational function is \( \frac{2x+1}{3-4x} \):
For our exercise, the rational function is \( \frac{2x+1}{3-4x} \):
- The leading coefficient of the numerator \(2x+1\) is 2.
- The leading coefficient of the denominator \(3-4x\) is -4.
Polynomial Degree Analysis
In polynomial degree analysis, the degree of a polynomial is the highest power of the variable present in the polynomial. This concept is essential when dealing with rational functions, especially in the context of limits at infinity.
For the given rational function \( \frac{2x+1}{3-4x} \), we analyze the degrees:
For the given rational function \( \frac{2x+1}{3-4x} \), we analyze the degrees:
- The polynomial \( 2x+1 \) has a degree of 1 because the highest power of \( x \) is 1.
- Similarly, the polynomial \( 3-4x \) also has a degree of 1.
Other exercises in this chapter
Problem 4
Let \(f(x)=\sin x-x, \quad-1 \leq x \leq 1\). (a) Graph \(y=f(x)\) for \(-1 \leq x \leq 1\). (b) Use the Intermediate Value Theorem to conclude that \(\sin x=x\
View solution Problem 4
In Problems \(1-4\), show that each function is continuous at the given value. $$ f(x)=x^{2}+1, c=-1 $$
View solution Problem 4
In Problems 1-32, use a table or a graph to investigate each limit. $$ \lim _{s \rightarrow 0} s\left(s^{2}-4\right) $$
View solution Problem 5
Evaluate the trigonometric limits. $$ \lim _{x \rightarrow 0} \frac{\sin (\pi x)}{x} $$
View solution