Problem 4
Question
Evaluate the expression. $$\frac{11 !}{8 !}$$
Step-by-Step Solution
Verified Answer
Question: Evaluate the given expression: $$\frac{11 !}{8 !}$$
Answer: 990
1Step 1: Understanding Factorials
A factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n. For example, 5! = 5 × 4 × 3 × 2 × 1 = 120.
Now we can use this definition to rewrite the given expression.
2Step 2: Rewrite the Expression Using Factorials
Let's rewrite the expression using factorial definition to simplify it:
$$\frac{11 !}{8 !} = \frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}$$
3Step 3: Simplify the Expression Using Factorial Properties
Now we can cancel out terms that are common in both numerator and denominator:
$$\frac{11 \times 10 \times 9 \times \cancel{8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}}{\cancel{8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}} = 11 \times 10 \times 9$$
4Step 4: Calculate the Result
Lastly, we calculate the product:
$$11 \times 10 \times 9 = 990$$
So the evaluated expression is:
$$\frac{11 !}{8 !} = 990$$
Key Concepts
Factorial DefinitionSimplifying Factorial ExpressionsFactorial Properties
Factorial Definition
Factorials are a fundamental concept in mathematics, especially within combinatorics and algebra. Simply put,
This rapid growth makes factorials both interesting objects of study and powerful tools in mathematical operations involving permutations and combinations.
- A factorial, denoted by the symbol "!", is the product of all positive integers up to a specified number.
- For example, the factorial of 4, written as 4!, equals \(4 \times 3 \times 2 \times 1 = 24\).
- By convention, the factorial of zero is defined as 1 (0! = 1).
This rapid growth makes factorials both interesting objects of study and powerful tools in mathematical operations involving permutations and combinations.
Simplifying Factorial Expressions
Simplifying factorial expressions often involves canceling out repeated factors in the numerator and denominator.
This can greatly reduce complexity in a calculation and makes it easier to handle. Here's how it works:
Simplifying in this way not only simplifies calculations but also aids in understanding how factorial operations function at a fundamental level.
This can greatly reduce complexity in a calculation and makes it easier to handle. Here's how it works:
- When dividing one factorial by another, as shown in our example \(\frac{11!}{8!}\), write out each factorial fully.
- The expression \(\frac{11!}{8!}\) becomes \(\frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}\).
Simplifying in this way not only simplifies calculations but also aids in understanding how factorial operations function at a fundamental level.
Factorial Properties
Understanding the properties of factorials can assist in simplifying and solving complex expressions.
Key properties include:
Key properties include:
- Multiplicative Growth: The factorial of a number \(n!\) is \(n\) times the factorial of the previous number, i.e., \(n \times (n-1)!\).
- Division: Dividing factorials often simplifies by canceling out common factors, as demonstrated by \(\frac{11!}{8!}\).
- Factorial of Zero: 0! equals 1. This property is crucial for combinatorial formulas where factorials of zero occur.
Other exercises in this chapter
Problem 4
In Exercises \(1-12\), determine whether the sequence is arithmetic, geometric, or neither. $$-1,-\frac{1}{2}, 0, \frac{1}{2}, \dots$$
View solution Problem 4
Use mathematical induction to prove that each of the given statements is true for every positive integer \(n .\) $$1^{2}+2^{2}+3^{2}+\cdots+n^{2}=\frac{n(n+1)(2
View solution Problem 4
Determine whether the sequence is arithmetic or not. If it is, find the common difference. $$-9,-6,-3,0, \dots$$
View solution Problem 4
Find the first five terms of the sequence \(\left\\{a_{n}\right\\}\). $$a_{n}=\frac{1}{(n+3)(n+1)}$$
View solution