Problem 4
Question
Draw a sketch of the graph of the given equation.\(r=2 \sin \theta\)
Step-by-Step Solution
Verified Answer
The graph of \(r = 2 \sin \theta\) is a circle centered at (0, 1) with a radius of 1.
1Step 1: Understand the given equation
The given equation is in polar coordinates: \[ r = 2 \sin \theta \] Here, \( r \) is the radius (distance from the origin) and \( \theta \) is the angle.
2Step 2: Identify key points
Identify angles \( \theta \) where \( \sin \theta \) has known values: - When \( \theta = 0 \), \( \sin 0 = 0 \ \rightarrow r = 0 \) - When \( \theta = \ \frac{\pi}{2} \), \( \sin \frac{\pi}{2} = 1 \ \rightarrow r = 2 \) - When \( \theta = \pi \), \( \sin \pi = 0 \ \rightarrow r = 0 \) - When \( \theta = \frac{3\pi}{2} \), \( \sin \frac{3\pi}{2} = -1 \ \rightarrow r = -2 \), which means \( r = 2 \) in the opposite direction (\( \theta + \pi \)).
3Step 3: Plot the points
Using the identified points: 1. At \( \theta = 0 \), plot point (0, 0). 2. At \( \theta = \frac{\pi}{2} \), plot point (0, 2). 3. At \( \theta = \pi \), plot point (0, 0). 4. At \( \theta = \frac{3\pi}{2} \), plot point (0, -2), but this translates to the point (0, 2) in the opposite direction.
4Step 4: Connect the points smoothly
The given equation describes a circle. Connect the plotted points smoothly to form the circle. The circle is centered at (0, 1) with a radius of 1 in the Cartesian plane.
Key Concepts
Graphing Polar EquationsSinusoidal FunctionsPlotting Points
Graphing Polar Equations
Polar coordinates are a way to express points on a plane where each point is determined by a distance from the origin (the radius, denoted as \( r \)) and an angle from the positive x-axis (denoted as \( \theta \)). In the given exercise, we have the polar equation \( r = 2 \sin \theta \). When graphing polar equations, follow these steps:
- Identify key angles and calculate corresponding \( r \) values.
- Plot the points on the polar grid.
- Connect the points smoothly to form the graph.
Sinusoidal Functions
Sinusoidal functions, like sine and cosine, are fundamental in understanding polar equations. They describe oscillating patterns and are pivotal in creating smooth curves. For the equation \( r = 2 \sin \theta \), the radius \( r \) varies according to the sine of the angle, \( \theta \).
**Here's a quick overview of the sine function:**
**Here's a quick overview of the sine function:**
- \( \sin 0 = 0 \)
- \( \sin \frac{\pi}{2} = 1 \)
- \( \sin \pi = 0 \)
- \( \sin \frac{3\pi}{2} = -1 \)
Plotting Points
Plotting points correctly in polar coordinates requires understanding both the distance from the origin (\( r \)) and the angle (\( \theta \)). Follow these guidelines for plotting:
- Identify specific angles where the function's values are known.
- Calculate the corresponding radius values.
- Mark the points on the polar grid at the calculated radii and angles.
- Consider the full rotation from 0 to \( 2\pi \) for a complete graph.
Other exercises in this chapter
Problem 4
Find the area of the region enclosed by the graph of the given equation.\(r=4 \sin ^{2} \frac{1}{2} \theta\)
View solution Problem 4
Find the points of intersection of the graphs of the given pair of equations. Draw a sketch of each pair of graphs with the same pole and polar axis.\(\left\\{\
View solution Problem 4
Plot the point having the given set of polar coordinates; then find another set of polar coordinates for the same point for which (a) \(r0\) and \(-2 \pi
View solution Problem 5
Find the area of the region enclosed by the graph of the given equation.\(r^{2}=4 \sin 2 \theta\)
View solution