Problem 4
Question
Determine whether or not the sum is geometric. Assume \("+\cdots\) indicates that the established pattern continues. If the sum is geometric, identify " \(a\) " and " \(r\) ". $$ \frac{2}{3}+\frac{2}{9}+\frac{2}{27}+\cdots+\frac{2}{6561} $$
Step-by-Step Solution
Verified Answer
The given sequence is a geometric sequence with the first term 'a' being \(\frac{2}{3}\) and the common ratio 'r' being \(\frac{1}{3}\).
1Step 1: Identify The Pattern
Looking at the progression \( \frac{2}{3}, \frac{2}{9}, \frac{2}{27},... \), it can be noted that each term is being divided by 3 to obtain the next term. Hence, the sequence is a geometric progression.
2Step 2: Identify 'a' And 'r'
In a geometric sequence, 'a' represents the first term in the sequence and 'r' the ratio between two successive terms. Here the first term \(a = \frac{2}{3} \) and the ratio \( r = \frac{\frac{2}{9}}{\frac{2}{3}} = \frac{1}{3} \).
Key Concepts
geometric progressioncommon ratiofirst termsum of series
geometric progression
A geometric progression, also known as a geometric sequence, is a sequence of numbers in which each term after the first is found by multiplying the previous term by a constant called the "common ratio". This kind of sequence is distinct from arithmetic sequences, where the difference between terms is constant. In a geometric progression:
- Each successive term is derived from the previous one by multiplication.
- This multiplication factor is consistent and is referred to as the "common ratio".
common ratio
The common ratio, denoted as \( r \), is a crucial part of understanding geometric sequences. It is the constant factor that you multiply by to get from one term to the next in the sequence. You can find the common ratio by dividing any term in the sequence by the preceding term. For example, in the sequence \( \frac{2}{3}, \frac{2}{9}, \frac{2}{27}, \ldots \), the common ratio \( r \) is calculated as follows:- Take any consecutive terms, such as \( \frac{2}{9} \) and \( \frac{2}{3} \).- Divide them: \( \frac{2}{9} \div \frac{2}{3} = \frac{1}{3} \).This demonstrates that \( r = \frac{1}{3} \), and each term is essentially a third of the previous one. Understanding the common ratio helps in predicting the sequence's behavior and in calculating sums efficiently.
first term
The first term of a geometric sequence, often represented by \( a \), serves as the starting point of the sequence. It is the initial value from which all other terms are derived by successive multiplication with the common ratio \( r \).In the context of the example sequence \( \frac{2}{3}, \frac{2}{9}, \frac{2}{27}, \ldots \):- The first term is \( a = \frac{2}{3} \).Identifying the first term is fundamental since it forms the base value upon which the geometric progression is built. And when we add or sum such a sequence, this term directly defines the baseline for calculations using the formulas of the geometric series.
sum of series
The sum of a geometric series refers to adding up all the terms of a geometric sequence. The formula for calculating the sum depends on whether the series is finite or infinite.For a finite geometric series, the sum \( S_n \) of the first \( n \) terms is given by:\[S_n = a \frac{1-r^n}{1-r}\]Here:- \( a \) is the first term,- \( r \) is the common ratio,- \( n \) is the number of terms.For an infinite geometric series, where \( |r| < 1 \), the sum \( S \) can be found using:\[S = \frac{a}{1-r}\]This formula only applies if the common ratio's absolute value is less than 1, ensuring the series converges. Understanding the sum formula allows computation of the total of a series or helps analyze convergence in infinite sequences.
Other exercises in this chapter
Problem 3
For Problems , determine whether the series converges or diverges. Explain your reasoning. $$ \frac{2}{3}+\frac{2}{4}+\frac{2}{5}+\cdots+\frac{2}{n}+\cdots $$
View solution Problem 4
Determine whether the series converges or diverges. If it converges, \(n d\) its sum. $$ \frac{2}{3}+2+6+\cdots+2(3)^{n}+\cdots $$
View solution Problem 4
A ball is thrown from the ground to a height of 16 feet. Each time the ball bounces it rises up to \(60 \%\) of its previous height. What is the total distance
View solution Problem 4
Write the sum using summation notation. (a) \(4 x^{2}+4 x^{3}+4 x^{4}+4 x^{5}+\cdots+\) (b) \(2 x+3 x^{2}+4 x^{3}+5 x^{4}+6 x^{5}+\cdots+\)
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