Problem 4
Question
An 18-gauge copper wire (diameter 1.02 mm) carries a current with a current density of \(3.20 \times 10{^6} A/m{^2}\). The density of free electrons for copper is \(8.5 \times 10^{28}\) electrons per cubic meter. Calculate (a) the current in the wire and (b) the drift velocity of electrons in the wire.
Step-by-Step Solution
Verified Answer
The current is approximately 1.31 A, and the drift velocity is about 9.5 \times 10^{-4} m/s.
1Step 1: Determine the cross-sectional area of the wire
To find the current, we first need the cross-sectional area of the wire. Since the wire is round, we use the formula for the area of a circle \(A = \pi r^2\). The radius \(r\) is half of the diameter, so \(r = \frac{1.02 \text{ mm}}{2} = 0.51 \text{ mm} = 0.51 \times 10^{-3} \text{ m}\). Thus, \(A = \pi (0.51 \times 10^{-3})^2\).
2Step 2: Calculate the current using current density
The formula for current \(I\) is given by \(I = J \cdot A\), where \(J\) is the current density. We have \(J = 3.20 \times 10^6 \text{ A/m}^2\) and from Step 1, we found \(A\). Thus, \(I = 3.20 \times 10^6 \times \pi (0.51 \times 10^{-3})^2\).
3Step 3: Calculate the drift velocity of electrons
The drift velocity \(v_d\) is given by \(v_d = \frac{I}{n \cdot A \cdot e}\), where \(n = 8.5 \times 10^{28}\) m^{-3} is the electron density, and \(e = 1.6 \times 10^{-19}\) C is the charge of an electron. Substitute the value of \(I\) from Step 2, and \(A\) from Step 1 into this formula to find \(v_d\).
Key Concepts
Current DensityCopper WireCross-Sectional AreaElectron Drift Velocity
Current Density
Current density (
J
) is a measure of how much current flows through a unit area of a conductor. It's like counting how many electrons pass through a tiny window in the wire per second.
Current density is measured in amperes per square meter (
A/m^2
).
To calculate the current in a wire, knowing the current density is quite essential.
If you think of the wire as a highway, the current density indicates how crowded the highway is with electrons.
To calculate the current in a wire, knowing the current density is quite essential.
If you think of the wire as a highway, the current density indicates how crowded the highway is with electrons.
Knowing Current Density
- It tells us how much electric current flows per unit area.
- Higher current density can lead to increased heat in the wire.
- This is crucial for safety and efficiency when designing electrical circuits.
Copper Wire
Copper wire is popular in electrical applications due to its excellent electrical conductivity.
This makes it very effective in allowing the easy flow of electricity.
In this exercise, the focus is on an 18-gauge copper wire. This refers to the specific size of the wire, and the smaller number in gauge means a larger diameter.
In this exercise, the focus is on an 18-gauge copper wire. This refers to the specific size of the wire, and the smaller number in gauge means a larger diameter.
Why Copper?
- Copper has low resistance, making it ideal for conducting electricity.
- It is durable and can be bent without breaking easily.
- Copper's high electron density makes it an efficient conductor.
Cross-Sectional Area
The cross-sectional area of a wire affects how easily current can flow through it. Basically, it’s the space available for electrons to move.
To find this area in a cylindrical wire, like the one in the exercise, use the formula for the area of a circle: \(A = \pi r^2\).
This helps in calculating the current when you know the current density.
To find this area in a cylindrical wire, like the one in the exercise, use the formula for the area of a circle: \(A = \pi r^2\).
This helps in calculating the current when you know the current density.
Importance of Cross-Sectional Area
- Larger areas allow more current to flow, much like a wide river.
- A smaller area can restrict current flow, similar to a narrow path.
- Influences resistance; smaller areas mean higher resistance.
Electron Drift Velocity
Electron drift velocity (\(v_d\)) is the average velocity of electrons moving through a conductor when subjected to an electric field. It's surprisingly slow compared to the speed of current, which is almost instantaneous.
Appreciating this helps in understanding how electricity behaves in different materials and why the material choice is critical in electrical engineering.
Why Drift Velocity Matters
- Helps in understanding the actual movement of electrons in a conductor.
- Important for calculating conductive properties in materials.
- Low drift velocity means electrons are "bumping" forward in a crowded space.
Appreciating this helps in understanding how electricity behaves in different materials and why the material choice is critical in electrical engineering.
Other exercises in this chapter
Problem 1
During lightning strikes from a cloud to the ground, currents as high as 25,000 A can occur and last for about 40 ms. How much charge is transferred from the cl
View solution Problem 3
A 5.00-A current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has \(8.5 \times 10^{28}\) free electrons per cubic met
View solution Problem 5
Copper has \(8.5 \times 10^{28}\) free electrons per cubic meter. A 71.0-cm length of 12-gauge copper wire that is 2.05 mm in diameter carries 4.85 A of current
View solution Problem 7
The current in a wire varies with time according to the relationship \(I = 55 A\) - \(10.65 A/s{^2}2t{^2}\). (a) How many coulombs of charge pass a cross sectio
View solution