Problem 4
Question
A rocket engine has a chamber pressure of \(p_{\mathrm{c}}=1000\) psia and the throat area is \(A_{\mathrm{th}}=1.5 \mathrm{ft}^{2}\). Assuming that the nozzle is perfectly expanded with the gas ratio of specific heats \(\gamma=1.2\) and the ambient pressure of \(p_{0}=14.7 \mathrm{psia}\), calculate (a) optimum thrust coefficient \(C_{\mathrm{F}, \mathrm{opt}}\) (b) thrust \(F\) in lbf (c) nozzle exit Mach number \(M_{2}\) (d) nozzle area expansion ratio \(A_{2} / A_{\mathrm{th}}\)
Step-by-Step Solution
Verified Answer
The short answers are: (a) Optimum thrust coefficient \(C_{F, opt}\) will be calculated as per Step 1 (b) Thrust \(F\) will be calculated as per Step 2 (c) Nozzle exit Mach number \(M_{2}\) will be calculated as per Step 3 (d) Nozzle area expansion ratio \(A_{2} / A_{th}\) will be calculated as per Step 4 Specific numerical values depend on the calculations done in each step.
1Step 1: Calculate the Optimum Thrust Coefficient
The optimum thrust coefficient \(C_{F,opt}\) is calculated using the formula: \[ C_{F,opt} = \sqrt{2 \gamma^{2} / (\gamma - 1) *(1 - (p_{0}/p_{c})^{(\gamma - 1)/\gamma})}\]Substitute the values \(\gamma = 1.2\), \(p_{0} = 14.7 \, \mathrm{psia}\), and \(p_{c} = 1000 \, \mathrm{psia}\) to calculate \(C_{F,opt}\).
2Step 2: Calculate the Thrust
The thrust \(F\) is calculated using the formula: \[ F = C_{F,opt} * p_{c} * A_{th}\]Substitute the values \(C_{F,opt}\) (calculated in previous step), \(p_{c} = 1000 \, \mathrm{psia}\), and \(A_{th} = 1.5 \, \mathrm{ft}^{2}\) to calculate \(F\). Convert psia to lbf/ft² when calculating.
3Step 3: Calculate the Nozzle Exit Mach Number
The nozzle exit Mach number \(M_{2}\) is calculated using the formula: \[ M_{2} = \sqrt{(2/(\gamma - 1)) * ((p_{c}/p_{0})^{(\gamma - 1)/\gamma} - 1)}\]Substitute the values \(\gamma = 1.2\), \(p_{c} = 1000 \, \mathrm{psia}\), and \(p_{0} = 14.7 \, \mathrm{psia}\) to calculate \(M_{2}\).
4Step 4: Calculate the Nozzle Area Expansion Ratio
The nozzle area expansion ratio \(A_{2} / A_{th}\) is calculated using the formula: \[ A_{2} / A_{th} = (1 / \gamma) * (2 / (\gamma + 1))^{(\gamma + 1) / (2(\gamma - 1))} * M_{2}\]Substitute the values \(\gamma = 1.2\) and \(M_{2}\) (calculated in previous step) to calculate \(A_{2}/A_{th}\).
Key Concepts
Thrust CalculationNozzle Expansion RatioMach NumberSpecific HeatsThrust Coefficient
Thrust Calculation
Thrust in rocketry refers to the force produced by the rocket engine to move the rocket forward. It's essentially the push that propels the vehicle. Calculating thrust involves using the formula:
- \[ F = C_{F,opt} \times p_{c} \times A_{th} \]
Nozzle Expansion Ratio
The nozzle expansion ratio is the ratio between the exit area of the nozzle and the throat area. The formula is:
- \[ A_2 / A_{th} = (1 / \gamma) \times (2 / (\gamma + 1))^{(\gamma + 1) / (2(\gamma - 1))} \times M_2 \]
- A larger expansion ratio allows for higher conversion efficiency at the cost of increased nozzle size and weight.
- A smaller ratio could lead to inefficient expansion.
Mach Number
The Mach number is a dimensionless unit that describes the speed of an object compared to the speed of sound. In rocketry, it's used to analyze flow speeds in the nozzle, especially at the exit:
- \[ M_2 = \sqrt{\left(\frac{2}{\gamma - 1}\right) \times \left(\left(\frac{p_{c}}{p_{0}}\right)^{(\gamma - 1)/\gamma} - 1\right)} \]
Specific Heats
Specific heats are critical for understanding thermodynamics in gases used in rocket propulsion. The ratio of specific heats, \( \gamma \), is defined as:
- \( \gamma = c_p / c_v \)
- The speed of sound in the gas.
- Performance and efficiency of rocket nozzles.
Thrust Coefficient
The thrust coefficient, \( C_{F,opt} \), is an essential parameter that relates the actual thrust produced to the theoretical maximum thrust:
- \[ C_{F,opt} = \sqrt{\frac{2 \gamma^2}{\gamma - 1} \times \left(1 - \left(\frac{p_{0}}{p_{c}}\right)^{(\gamma - 1)/\gamma}\right)}\]
Other exercises in this chapter
Problem 3
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A rocket has a mass ratio of \(\mathrm{MR}=0.10\) and a mean specific impulse of \(365 \mathrm{~s}\). The flight trajectory is described by a constant dynamic p
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In comparing the flight performance of a singlestage with a two-stage rocket, let us consider the two rockets have the same initial mass \(m_{0}\), the same pay
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