Problem 4
Question
\(a \mid 0\)
Step-by-Step Solution
Verified Answer
Yes, for any integer \(a\), \(a\) divides 0.
1Step 1: Understanding what a divides 0 means
We need to determine what it means when we write \(a \mid 0\). The notation \(a \mid b\) means that \(a\) divides \(b\), which requires there to be an integer \(k\) such that \(b = a \cdot k\). In our case, we want to see if \(a\) divides 0, so we need to find an integer \(k\) such that \(0 = a \cdot k\).
2Step 2: Identifying the value of k
Since the equation is \(0 = a \cdot k\), any integer \(a\) will satisfy this because we can always choose \(k = 0\). Therefore, \(a \cdot 0 = 0\), fulfilling the condition for \(a\) dividing 0. This highlights that the value of \(a\) does not matter; the result \(0 = a \cdot 0\) stands true for any integer \(a\).
3Step 3: Concluding the divisibility statement
We have found that for any integer \(a\), we can choose \(k = 0\) so that \(a \mid 0\). This means that every integer \(a\) divides 0. Therefore, the statement \(a \mid 0\) is true for all integers \(a\).
Key Concepts
IntegersMultiplicationZero Divisibility
Integers
In algebra, integers are the set of whole numbers which include positive numbers, negative numbers, and zero. These numbers don't have any fractional or decimal parts. Understanding integers is essential for working with divisibility because they serve as the base numbers with which divisibility is often tested.
Integers have several key properties:
Integers have several key properties:
- They are evenly spaced with no gaps, and they extend infinitely in both positive and negative directions.
- Zero is a unique integer. It is neither positive nor negative and serves as the additive identity.
- Integers can be represented on the number line, which helps visualize their order and how they interact under various operations.
Multiplication
Multiplication is one of the fundamental operations in algebra and mathematics. It's essentially repeated addition. When considering divisibility, multiplication plays a key role. The product of multiplication affects divisibility directly because if \(a\) divides \(b\), then there exists an integer \(k\) such that \(b = a \cdot k\).
Understanding multiplication:
Understanding multiplication:
- It's commutative, meaning \(a \cdot b = b \cdot a\).
- It's associative, so \((a \cdot b) \cdot c = a \cdot (b \cdot c)\).
- Distributive over addition, i.e., \(a \cdot (b + c) = a \cdot b + a \cdot c\).
Zero Divisibility
Zero is a unique number with special properties, especially when it comes to multiplication and divisibility. Unlike any other number, zero itself can be considered divisible by any integer, regardless of the size or sign of that integer. The statement \(a \mid 0\) becomes meaningful in that zero divided by any integer \(a\) results in zero, satisfying the multiplication condition for divisibility explained earlier.
Some pointers on zero:
Some pointers on zero:
- Zero is the additive identity, meaning adding zero to any number leaves the number unchanged.
- Any integer multiplied by zero results in zero: \(a \cdot 0 = 0\).
- In context of divisibility, because \(0 = a \cdot 0\), the integer \(k\) required to make \(a \mid 0\) true can always be chosen as zero.
Other exercises in this chapter
Problem 4
Suppose that for all integers \(x, x \mid a\) and \(x \mid b\) iff \(x \mid c\). Then \(c=\operatorname{gcd}(a, b)\).
View solution Problem 4
Suppose every common divisor of \(a\) and \(b\) is a common divisor of \(c\) and \(d\), and ce versa. Then \(\operatorname{gcd}(a, b)=\operatorname{gcd}(c, d)\)
View solution Problem 5
\(\operatorname{lcm}(a, a b)=a b\)
View solution Problem 5
Prove by induction: For all \(n>0\), if \(\operatorname{gcd}(a, b)=1\), then \(\operatorname{gcd}\left(a, b^{n}\right)=1\).
View solution