Problem 4
Question
4\. Soil contamination A crop is planted in soil that is contaminated with a pollutant. The pollutant gradually leaches out of the soil but is also absorbed by the growing crop. A simple model of this process is $$\frac{d s}{d t}=-\alpha s-\beta s \quad \frac{d c}{d t}=\beta s$$ where \(s\) and \(c\) are the amounts of pollutant in the soil and crop (in mg), respectively, and \(\alpha\) and \(\beta\) are positive constants. $$\begin{array}{l}{\text { (a) Suppose that } s(0)=s_{0} \text { and } c(0)=0 . \text { What is the solu- }} \\ {\text { tion to the initial-value problem? }} \\ {\text { (b) In the long term (that is, as } t \rightarrow \infty ), \text { what is the amount }} \\ {\text { of pollutant in the crop? }}\end{array}$$
Step-by-Step Solution
VerifiedKey Concepts
Soil Contamination
In the exercise provided, the equations describe how the pollutant leaches out of the soil and is absorbed by the crop. These equations form a differential equation system, where:
- \( \frac{d s}{d t} = -\alpha s - \beta s \) describes how the pollutant amount in the soil decreases over time due to leaching and absorption by the crops.
- \( \frac{d c}{d t} = \beta s \) shows how the concentration in the crop increases as it absorbs the pollutant from the soil.
Biological Modeling
Here, the model uses parameters \( \alpha \) and \( \beta \), which are positive constants representing different aspects of the leaching and absorption processes.
- \( \alpha \) represents the rate at which the soil loses pollutants naturally through processes like leaching.
- \( \beta \) is the rate of absorption by crops, showing how quickly the plants pull the pollutant from the soil.
Initial Value Problem
The step-by-step solution involves solving two differential equations given the initial conditions:
- Solving \( \frac{ds}{dt} = -\alpha s - \beta s \) leads us to the solution \( s(t) = s_0 e^{-(\alpha + \beta)t} \), indicating an exponential decrease in pollutant concentration in the soil over time.
- For the crop, \( \frac{dc}{dt} = \beta s \) is solved resulting in \( c(t) = \frac{\beta s_0}{\alpha + \beta} (1 - e^{-(\alpha + \beta)t}) \), showing the pollutant level in the crop rises over time and approaches a constant value.