Problem 4
Question
1–6 Evaluate the expression. $$P(10,5)$$
Step-by-Step Solution
Verified Answer
The value of \(P(10, 5)\) is 30,240.
1Step 1: Understand Permutation Notation
The notation \(P(n, r)\) represents a permutation, which is used to determine the number of ways to arrange \(r\) objects out of \(n\) distinct objects. The formula for permutations is given by: \(P(n, r) = \frac{n!}{(n-r)!}\).
2Step 2: Identify the Values of n and r
In the given expression \(P(10, 5)\), the value of \(n\) is 10 and the value of \(r\) is 5. This means we want to find the number of ways to arrange 5 objects out of a total of 10 objects.
3Step 3: Apply the Permutation Formula
Using the formula \(P(n, r)\), calculate \(P(10, 5)\) by substituting \(n = 10\) and \(r = 5\) as follows:\[P(10, 5) = \frac{10!}{(10-5)!} = \frac{10!}{5!}\]
4Step 4: Calculate Factorials
Calculate \(10!\) and \(5!\):- \(10! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1\)- \(5! = 5 \times 4 \times 3 \times 2 \times 1\)
5Step 5: Simplify and Solve
Compute \(P(10, 5)\) by dividing the expanded factorials:\[P(10, 5) = \frac{10 \times 9 \times 8 \times 7 \times 6 \times 5!}{5!}\]The \(5!\) cancels out, so:\[P(10, 5) = 10 \times 9 \times 8 \times 7 \times 6 = 30240\]
6Step 6: Conclusion
The value of the permutation \(P(10, 5)\) is 30,240. There are 30,240 different ways to arrange 5 objects out of 10 distinct objects.
Key Concepts
FactorialsCombinatoricsPermutation Formula
Factorials
Factorials are a fundamental concept in mathematics, particularly useful in permutations and combinations. A factorial, denoted by an exclamation mark (!), represents the product of all positive integers up to a given number.
For example, the factorial of 5 (written as 5!) is calculated as:
Remember, 0! is defined to be 1. This may seem unusual, but it helps in keeping formulas consistent, especially in permutations and combinations.
For example, the factorial of 5 (written as 5!) is calculated as:
- 5! = 5 × 4 × 3 × 2 × 1 = 120
Remember, 0! is defined to be 1. This may seem unusual, but it helps in keeping formulas consistent, especially in permutations and combinations.
Combinatorics
Combinatorics is a branch of mathematics that deals with counting, arranging, and finding patterns in sets. It's often about figuring out how many ways certain selections or arrangements can be made.
For example, in a situation where you have to choose 3 ice cream flavors out of 10 available, combinatorics helps in determining the number of possible combinations.
For example, in a situation where you have to choose 3 ice cream flavors out of 10 available, combinatorics helps in determining the number of possible combinations.
- Permutations: Concerned with the arrangements of objects where order matters.
- Combinations: Deal with the selection of objects where order does not matter.
Permutation Formula
The permutation formula is used to determine the number of ways to arrange a subset of objects from a set, where the order of arrangement is important.
The general permutation formula is given by:
\[ P(n, r) = \frac{n!}{(n-r)!} \]Where:
This formula is particularly useful in situations where order and arrangement are crucial, such as forming passwords, arranging people in lines, or organizing tournament schedules.
The general permutation formula is given by:
\[ P(n, r) = \frac{n!}{(n-r)!} \]Where:
- n is the total number of objects.
- r is the number of objects to be arranged.
- n! represents the factorial of n.
- (n-r)! represents the factorial of the difference between n and r.
This formula is particularly useful in situations where order and arrangement are crucial, such as forming passwords, arranging people in lines, or organizing tournament schedules.
Other exercises in this chapter
Problem 3
A die is rolled. Find the probability of the given event. (a) The number showing is a six. (b) The number showing is an even number. (c) The number showing is g
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A die is rolled. Find the probability of the given event. (a) The number showing is a two or a three. (b) The number showing is an odd number. (c) The number sh
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