Problem 399
Question
Sketch the function in one graph and, in a second, sketch several level curves. \(f(x, y)=x+4 y^{2}\)
Step-by-Step Solution
Verified Answer
Graphic of surface: parabolic cylinder; Level curves: parabolas in \(xy\)-plane.
1Step 1: Identify the Components of the Function
Understand that the function given is \[f(x, y) = x + 4y^2\]This is a function of two variables, \(x\) and \(y\). It combines linear and quadratic elements, where \(x\) is linear, and \(4y^2\) is quadratic in nature.
2Step 2: Graph the Function in 3D
Plot the surface \(z = f(x, y) = x + 4y^2\) in three dimensions. This surface is a parabolic cylinder opening along the \(x\) axis, oriented along the \(z\) axis, with its minimum along the \(x\) axis at \(x = 0\) when \(y = 0\). The cross-sections parallel to the \(yz\) plane are parabolas.
3Step 3: Select Level Values
Choose several values for the level \(c\) where the function has a constant value: \(c = 0, 1, 2, -1, -2\). These values will determine the level curves of the function \(x + 4y^2 = c\).
4Step 4: Derive Equations of Level Curves
For each level value \(c\), the equation \(x + 4y^2 = c\) becomes \(x = c - 4y^2\). These are equations of parabolas opening to the left if \(c > 0\) and to the right if \(c < 0\) in the \(xy\)-plane.
5Step 5: Sketch Level Curves in the 2D Plane
For each parabola,- The vertex is at \((c, 0)\).- For \(c = 0\): the line \(x = -4y^2\).- For \(c = 1\): the parabola \(x = 1 - 4y^2\), opening to the left.- For \(c = -1\): the parabola \(x = -1 - 4y^2\), opening to the right.Sketch these curves on the same 2D plot to show several level curves.
Key Concepts
Level Curves3D PlottingParabolic Cylinder
Level Curves
Level curves, also known as contour lines, are essential for understanding the shape of a 3D surface in a 2D plane. They represent the set of points where a function of two variables, in this case \( f(x, y) = x + 4y^2 \), equals the same constant \( c \). By choosing different values of \( c \), we can explore different slices of the surface.
- For the function given, the level curves are defined by the equation \( x + 4y^2 = c \).
- Each level curve corresponds to a specific value of \( c \).
- By rearranging, we have \( x = c - 4y^2 \), which describes a series of parabolas.
- If \( c > 0 \), the parabola opens to the left.
- If \( c < 0 \), it opens to the right.
3D Plotting
Creating a 3D plot for a function like \( f(x, y) = x + 4y^2 \) helps visualize how the surface behaves in space. Such a plot is crucial for understanding the distribution of the function's values over the plane.
- Here, the surface represented is \( z = x + 4y^2 \).
- This highlights how changes in \( x \) and \( y \) impact the value of \( z \).
- The cylinder opens along the \( x \)-axis.
- The surface stretches in the direction of the \( z \)-axis.
- The minimum point, \( x = 0 \) when \( y = 0 \), is crucial for understanding the orientation.
Parabolic Cylinder
The idea of a parabolic cylinder may appear complex, but with a bit of clarity, it becomes easier to understand. In essence, a parabolic cylinder is a 3D shape formed by translating a parabola along an axis.
- For the function \( f(x, y) = x + 4y^2 \), it generates a parabolic cylinder when graphed.
- The cross-sections along planes parallel to the \( yz \)-plane are parabolas.
- Imagine a curved wall shaped like a parabola. This is essentially a parabolic cylinder.
- The curve extends infinitely in one direction (in this case, along the \( x \)-axis).
Other exercises in this chapter
Problem 397
Determine whether the statement is true or false. Justify your answer with a proof . \(\quad\left(\frac{3}{4}, \frac{9}{16}\right) \quad\) is a critical point o
View solution Problem 398
Sketch the function in one graph and, in a second, sketch several level curves. \(f(x, y)=e^{-\left(x^{2}+2 y^{2}\right)}\).
View solution Problem 400
Evaluate the following limits, if they exist. If they do not exist, prove it. \(\lim _{(x, y) \rightarrow(1,1)} \frac{4 x y}{x-2 y^{2}}\)
View solution Problem 401
Evaluate the following limits, if they exist. If they do not exist, prove it. \(\lim _{(x, y) \rightarrow(0,0)} \frac{4 x y}{x-2 y^{2}}\)
View solution