Problem 39
Question
Write the standard form of the equation of the circle with the given center and radius. $$ \text { Center }(-4,0), r=10 $$
Step-by-Step Solution
Verified Answer
The standard form of the equation of the circle with the center at (-4,0) and radius 10 is \((x + 4)^2 + y^2 = 100\).
1Step 1: Identify the given parameters
From the problem, we can ascertain that the center of the circle is \((-4, 0)\) and the radius of the circle is \(10\) units. This means that \(h = -4\), \(k = 0\), and \(r = 10\).
2Step 2: Substitute values into the standard equation
Now we need to substitute the values of \(h = -4\), \(k = 0\), and \(r = 10\) into the equation. It then becomes \((x - (-4))^2 + (y - 0)^2 = 10^2\).
3Step 3: Simplify the equation
Simplify the equation to its standard form. The equation then simplifies to \((x + 4)^2 + y^2 = 100\).
Key Concepts
Standard Form of the Circle EquationCenter of the CircleRadius of the Circle
Standard Form of the Circle Equation
The standard form of the equation of a circle is a crucial concept in geometry. It is a way to express a circle algebraically using its center and radius. The general form of a circle's equation in the standard form is: \\[ (x - h)^2 + (y - k)^2 = r^2 \]
where:
where:
- \(h\) and \(k\) are the coordinates of the center of the circle, \((h, k)\).
- \(r\) is the radius of the circle.
Center of the Circle
The center of a circle is a point that is equidistant from all points on the circle. In the standard form of the equation of a circle, the center is represented by the coordinates \((h, k)\). For our problem, the center provided is \((-4, 0)\), which means:
- \(h = -4\)
- \(k = 0\)
Radius of the Circle
The radius of a circle is defined as the constant distance from the center of the circle to any point on its circumference. In the equation \\[ (x - h)^2 + (y - k)^2 = r^2 \]
\(r\) represents the radius.In this specific problem, the radius is given as \(r = 10\). This means every point on the circle is exactly 10 units away from the center \((-4, 0)\). The radius is critical not only for the equation but also for understanding the size and scale of the circle. By squaring the radius, as seen in the equation, it helps plot and confirm the span or reach of the circle on a coordinate plane. Knowing the radius allows us to establish boundaries and dimensions necessary for applications such as circle-sector calculations or solving real-world problems like mapping and design.
\(r\) represents the radius.In this specific problem, the radius is given as \(r = 10\). This means every point on the circle is exactly 10 units away from the center \((-4, 0)\). The radius is critical not only for the equation but also for understanding the size and scale of the circle. By squaring the radius, as seen in the equation, it helps plot and confirm the span or reach of the circle on a coordinate plane. Knowing the radius allows us to establish boundaries and dimensions necessary for applications such as circle-sector calculations or solving real-world problems like mapping and design.
Other exercises in this chapter
Problem 39
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