Problem 39
Question
Write each equation in standard form, if it is not already so, and graph it. The problems include equations that describe circles, parabolas, and ellipses. \(\frac{x^{2}}{16}+\frac{y^{2}}{1}=1\)
Step-by-Step Solution
Verified Answer
The given equation is already in standard form for an ellipse and can be graphed using its parameters.
1Step 1: Identify the Conic Section
Recognize the form of the given equation: \( \frac{x^{2}}{16} + \frac{y^{2}}{1} = 1 \). This equation is of the form \( \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 \), indicating that it represents an ellipse. Compare it with the standard form to confirm it's already in the correct format.
2Step 2: Rewrite in Standard Form
Because the given equation is already in the standard form for an ellipse (\( \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 \)), there is no need to rewrite it. The standard form provides parameters \( a^{2} = 16 \) and \( b^{2} = 1 \).
3Step 3: Identify Key Parameters
Calculate the key values needed to graph the ellipse. Here, \( a = \sqrt{16} = 4 \) and \( b = \sqrt{1} = 1 \). These values denote the semi-major and semi-minor axes, respectively, with the x-axis being the semi-major axis due to \( a > b \).
4Step 4: Graph the Ellipse
Using the center of the ellipse at the origin (0,0), plot the points at \( (4, 0), (-4, 0), (0, 1), and (0, -1) \). These points correspond to the endpoints of the major and minor axes. Sketch the ellipse by drawing a smooth curve through these points.
Key Concepts
EllipseStandard FormGraphing Conic Sections
Ellipse
An ellipse is a fascinating shape in geometry that resembles an oval. It is essentially a stretched circle. Ellipses are important in both mathematics and the real world, appearing in things like planetary orbits. They are defined by two main parts; the longer axis, called the "major axis," and the shorter one, known as the "minor axis". These axes intersect at a point called the center of the ellipse.
To understand ellipses better, remember:
To understand ellipses better, remember:
- They have two foci or focus points, which are used in their mathematical definition.
- Every point on the ellipse has a consistent total distance to these two foci.
- The semi-major axis is half of the major axis, giving the extent of the ellipse's stretch along its longest part.
- The semi-minor axis is half the minor axis, showing the stretch along its shorter part.
Standard Form
The standard form of an ellipse is a specific mathematical way to express it with precision. When dealing with ellipses, the standard form plays a crucial role. It is given by the equation: \[\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1\] where
- \(a\) is the semi-major axis.
- \(b\) is the semi-minor axis.
Graphing Conic Sections
Graphing conic sections, such as ellipses, involves a systematic method. These shapes, including circles, parabolas, ellipses, and hyperbolas, make up a fundamental family in geometry. When graphing an ellipse in its standard form:
- Start by identifying the center, which is usually at the origin \((0,0)\) unless otherwise specified.
- Next, plot the foci, which for ellipses are points along the major axis.Then, use the semi-major and semi-minor axes to locate the vertex points on the graph. These are \((a, 0), (-a, 0), (0, b), and (0, -b)\) for an ellipse centered at the origin.
- Draw a smooth, oval shape connecting these points.
Other exercises in this chapter
Problem 39
Solve each system. See Using Your Calculator: Solving Systems of Equations. $$ \left\\{\begin{array}{l} x^{2}-6 x-y=-5 \\ x^{2}-6 x+y=-5 \end{array}\right. $$
View solution Problem 39
Write each equation of a parabola in standard form and graph it. Give the coordinates of the vertex. $$ y=2 x^{2}-4 x+5 $$
View solution Problem 40
Solve each system. See Using Your Calculator: Solving Systems of Equations. $$ \left\\{\begin{array}{l} x^{2}-y^{2}=-5 \\ 3 x^{2}+2 y^{2}=30 \end{array}\right.
View solution Problem 40
Use a graphing calculator to graph each equation. See Using Your Calculator: Graphing Hyperbolas. $$\frac{(y+1)^{2}}{9}-\frac{(x-2)^{2}}{4}=1$$
View solution