Problem 39
Question
Which equation models the ratio form of direct variation? $$\begin{array}{llll}\text { (A) } \frac{-4}{3}=\frac{y}{x} & \text { (B) }-3 y=4 x-1 & \text { (C) } \frac{4}{-3}=x+y &\text { (D) } y=-\frac{4}{3} x+6\end{array}$$
Step-by-Step Solution
Verified Answer
The correct answer is Option (A): \(\frac{-4}{3}=\frac{y}{x}\) which can be rewritten as \(y=\frac{-4}{3}x\). This is the only choice that represents the ratio form of direct variation.
1Step 1: Understand Direct Variation Formula
The formula for direct variation is \(y=kx\), where \('k'\) is the constant of variation. Therefore, in this exercise, look for an equation that can be written in the form \(y=kx\).
2Step 2: Explore Option (A)
\(\frac{-4}{3}=\frac{y}{x}\) can be rewritten as \(y=\frac{-4}{3}x\) which is in the form of \(y=kx\), therefore is a ratio of direct variation.
3Step 3: Explore Option (B)
-3y=4x-1 cannot be rewritten as \(y=kx\) because there is a subtraction factor (-1). Therefore, this is not in the ratio form of direct variation.
4Step 4: Explore Option (C)
\(\frac{4}{-3}=x+y\) cannot be rewritten as \(y=-\frac{4}{3}x\) because there is an addition factor (y). Therefore, this is not in the ratio form of direct variation.
5Step 5: Explore Option (D)
y=-\(\frac{4}{3}\)x+6 cannot be rewritten as \(y=kx\) because there is an addition factor (+6). Therefore, this is not in the ratio form of direct variation.
Key Concepts
Constant of VariationDirect Variation FormulaEquation Transformation
Constant of Variation
The constant of variation is a crucial element in direct variation equations. It is usually represented by the letter "\( k \)". In a direct variation relationship, the "\( y \)" values change consistently in proportion to changes in "\( x \)" values, thanks to this constant. It reflects the constant rate at which "\( y \)" changes with "\( x \)".
For example, consider the direct variation equation \( y = kx \). Here, if \( k = \frac{-4}{3} \), it means that for every unit increase in \( x \), \( y \) decreases by \( \frac{4}{3} \). This consistent rate of change is what makes \( k \) so important in understanding how the two variables relate. Knowing \( k \) allows us to quickly calculate one variable when given the other in the context of direct variation.
For example, consider the direct variation equation \( y = kx \). Here, if \( k = \frac{-4}{3} \), it means that for every unit increase in \( x \), \( y \) decreases by \( \frac{4}{3} \). This consistent rate of change is what makes \( k \) so important in understanding how the two variables relate. Knowing \( k \) allows us to quickly calculate one variable when given the other in the context of direct variation.
Direct Variation Formula
Direct variation is described by the simple equation \( y = kx \), where "\( y \)" varies directly with "\( x \)" and \( k \) is known as the constant of variation. This formula is foundational for identifying direct variation relationships.
In practical terms, whenever you see an equation of the form \( y = kx \), you can say "\( y \) varies directly with \( x \)". Direct variation implies a predictable and linear relationship between \( x \) and \( y \).
In practical terms, whenever you see an equation of the form \( y = kx \), you can say "\( y \) varies directly with \( x \)". Direct variation implies a predictable and linear relationship between \( x \) and \( y \).
- "\( k \)" must be a non-zero constant.
- The graph of a direct variation equation is a straight line through the origin (0,0).
Equation Transformation
Understanding how to manipulate equations is vital when identifying direct variation among multiple equation forms. The goal with direct variation equations is to transform them into the \( y = kx \) form, if possible.
For example, consider the equation \( \frac{-4}{3} = \frac{y}{x} \). By multiplying both sides by \( x \), you transform the equation into \( y = \frac{-4}{3}x \). This conversion highlights the constant of variation and aligns with the direct variation formula.
For example, consider the equation \( \frac{-4}{3} = \frac{y}{x} \). By multiplying both sides by \( x \), you transform the equation into \( y = \frac{-4}{3}x \). This conversion highlights the constant of variation and aligns with the direct variation formula.
- Look for opportunities to isolate "\( y \)" and "\( x \)" on opposite sides of the equation.
- Check for additional terms (e.g., constants, other variables) that may prevent the equation from being a direct variation.
Other exercises in this chapter
Problem 39
Use a graphing calculator to find the solution of the equation. Check your solution algebraically. $$-1.6(1.5 x+7.5)=0.6(6 x+30)$$
View solution Problem 39
Graph the function. $$ h(x)=5 $$
View solution Problem 39
Graph the line that has the given intercepts. $$ \begin{array}{l} x \text { -intercept: }-12 \\ y \text { -intercept: }-8 \end{array} $$
View solution Problem 39
Find the value of \(y\) so that the line passing through the two points has the given slope. $$(0,-2),(2, y), m=3$$
View solution