Problem 39
Question
What is the percent ionic character of each of the following bonds: (a) \(\mathrm{S}-\mathrm{H} ;\) (b) \(\mathrm{O}-\mathrm{Cl} ;\) (c) \(\mathrm{Al}-\mathrm{O}\) (d) As - O?
Step-by-Step Solution
Verified Answer
After doing all of the calculations, the percentage ionic characters for the given bonds (approx) are: (a) S-H: 9.4%, (b) O-Cl: 13%, (c) Al-O: 57%, (d) As-O: 6%.
1Step 1: Determine the Electronegativity Values
Look up the electronegativity values of the atoms in each bond from a trusted source such as a textbook or reliable online resource. For instance, typical values are: S (2.58), H (2.20), O (3.44), Cl (3.16), Al (1.61), and As (2.18).
2Step 2: Calculate the Difference in Electronegativity
For each bond (S-H, O-Cl, Al-O, As-O), calculate the absolute difference in electronegativity values. For example, for the bond S-H, the difference would be |2.58 - 2.20| = 0.38. Repeat this calculation for all bonds.
3Step 3: Calculate the Percent Ionic Character
Using the formula: Percent ionic character = 16(XA - XB) + 3.5(XA - XB)^2 , substitute the calculated electronegativity differences from step 2 into the formula to determine the percent ionic character for each bond. Here, (XA - XB) is the difference in electronegativity. For the S-H bond, the percent ionic character would be \(16 \times 0.38 + 3.5 \times 0.38^2\). Calculate this for all bonds.
Key Concepts
ElectronegativityIonic BondsChemical BondingElectronegativity Difference
Electronegativity
Electronegativity is a key concept in understanding how atoms interact in a molecule. It refers to an atom's ability to attract and hold onto electrons when it is part of a compound.
Different elements have different electronegativity values, which are often published in tables. For example, elements like fluorine have very high electronegativity, while alkali metals like sodium have lower values.
Understanding electronegativity is crucial because it helps predict how atoms will bond with each other.
Different elements have different electronegativity values, which are often published in tables. For example, elements like fluorine have very high electronegativity, while alkali metals like sodium have lower values.
Understanding electronegativity is crucial because it helps predict how atoms will bond with each other.
- If two atoms have similar electronegativities, they'll likely share electrons fairly equally, forming a covalent bond.
- However, if there is a significant difference in electronegativity, the bond may become polar or ionic, with electrons being unequally shared or transferred entirely.
Ionic Bonds
Ionic bonds are formed when there is a complete transfer of electrons from one atom to another. This typically occurs when there's a large difference in electronegativity between two atoms. The atom with the higher electronegativity will attract and gain the electron, becoming a negatively charged ion, or anion.
The atom with lower electronegativity will lose an electron, thus forming a positively charged ion called a cation.
For instance, in table salt (NaCl), sodium (Na) has a much lower electronegativity compared to chlorine (Cl). Sodium donates an electron to chlorine, resulting in a typical ionic bond formation.
The atom with lower electronegativity will lose an electron, thus forming a positively charged ion called a cation.
For instance, in table salt (NaCl), sodium (Na) has a much lower electronegativity compared to chlorine (Cl). Sodium donates an electron to chlorine, resulting in a typical ionic bond formation.
- Ionic bonds are usually strong and lead to the formation of crystalline solids.
- They dissolve in water to produce ions, which are conductive to electricity.
Chemical Bonding
Chemical bonding encompasses all the types of attractions that hold atoms together in compounds. The main types are ionic, covalent, and metallic bonds, with ionic and covalent being most common in chemical compounds.
Covalent bonds involve the sharing of electron pairs between atoms. These can further be categorized into nonpolar (equal sharing) and polar covalent bonds (unequal sharing).
Ionic bonds, as mentioned earlier, involve electron transfer. The type of bond influences a compound's properties significantly.
Covalent bonds involve the sharing of electron pairs between atoms. These can further be categorized into nonpolar (equal sharing) and polar covalent bonds (unequal sharing).
Ionic bonds, as mentioned earlier, involve electron transfer. The type of bond influences a compound's properties significantly.
- Covalently bonded compounds may have low melting and boiling points and might not dissolve easily in water.
- Ionic compounds often have higher melting and boiling points due to strong electrostatic forces and typically dissolve in water to form electrolytes.
Electronegativity Difference
The electronegativity difference between two atoms determines the type of bond they will form. By calculating this difference, we can estimate how ionic or covalent a bond will be.
For example, if two atoms have identical or very similar electronegativity values, they will share electrons pretty evenly, resulting in a nonpolar covalent bond.
On the other hand, a high electronegativity difference, usually above 1.7, indicates that the bond will likely be ionic, with electrons fully transferring to the more electronegative atom.
For example, if two atoms have identical or very similar electronegativity values, they will share electrons pretty evenly, resulting in a nonpolar covalent bond.
On the other hand, a high electronegativity difference, usually above 1.7, indicates that the bond will likely be ionic, with electrons fully transferring to the more electronegative atom.
- For instance, the NaCl bond has a high electronegativity difference, leading to salt's typical ionic nature.
- These differences also contribute to understanding the percent ionic character of a bond, reflecting how "ionic-like" a covalent bond can be.
Other exercises in this chapter
Problem 30
Write a plausible Lewis structure for \(\mathrm{C}_{3} \mathrm{O}_{2},\) a substance known as carbon suboxide.
View solution Problem 38
Which of the following molecules would you expect to have a resultant dipole moment \((\mu) ;\) (a) \(\mathrm{F}_{2}\), (b) \(\mathrm{NO}_{2}\) (c) \(\mathrm{BF
View solution Problem 47
Through appropriate Lewis structures, show that the phenomenon of resonance is involved in the nitrite ion.
View solution Problem 48
Which of the following species requires a resonance hybrid for its Lewis structure: (a) \(\mathrm{CO}_{2},\) (b) \(\mathrm{OCl}^{-}\) (c) \(\mathrm{CO}_{3}^{2-}
View solution