Problem 39
Question
Use the distributive property to write each expression without parentheses. Then simplify the result. See Example 4 . \(3(6+x)\)
Step-by-Step Solution
Verified Answer
18 + 3x.
1Step 1: Identify the Problem
We are given the expression \(3(6+x)\) and need to apply the distributive property to remove the parentheses, then simplify the expression.
2Step 2: Apply the Distributive Property
The distributive property states that \(a(b+c) = ab + ac\). Here, \(a=3\), \(b=6\), and \(c=x\). We'll distribute 3 to both 6 and \(x\), resulting in \(3 \cdot 6 + 3 \cdot x\).
3Step 3: Perform Multiplication
Calculate \(3 \cdot 6\) and \(3 \cdot x\). We have \(3 \cdot 6 = 18\) and \(3 \cdot x = 3x\).
4Step 4: Write the Expanded Expression
Combine the results from Step 3 into a new expression: \(18 + 3x\).
5Step 5: Simplify the Expression
The expression \(18 + 3x\) is already simplified, so no further steps are needed.
Key Concepts
Algebraic ExpressionsSimplificationMultiplication Distributive Law
Algebraic Expressions
Algebraic expressions are mathematical phrases that can include numbers, symbols, and operations such as addition, subtraction, multiplication, and division. Think of them as sentences that express relationships between quantities. For instance, in the expression \(3(6+x)\), numbers and symbols like 3 and \(x\) are used, along with operations like multiplication and addition. These expressions can be simple or complex.
An expression like \(6 + x\) involves an unknown variable \(x\), which can take different values. By combining numbers (like 6) and variables (like \(x\)), algebraic expressions easily represent a range of possible values. This flexibility is one of the main reasons why algebra is such a powerful tool in mathematics.
An expression like \(6 + x\) involves an unknown variable \(x\), which can take different values. By combining numbers (like 6) and variables (like \(x\)), algebraic expressions easily represent a range of possible values. This flexibility is one of the main reasons why algebra is such a powerful tool in mathematics.
Simplification
Simplification in algebra involves reducing an expression to its simplest form. The goal is to make it as concise and understandable as possible. During simplification, we use mathematical properties to combine like terms and eliminate any unnecessary components. This process often makes expressions easier to work with.
For example, in the expression \(18 + 3x\), there are no like terms to combine since 18 is constant and \(3x\) contains the variable \(x\). Thus, simplification is complete, and the expression is already in its simplest form. Simplifying initially complex expressions helps in solving equations, as it reveals the core relationships between the variables involved.
For example, in the expression \(18 + 3x\), there are no like terms to combine since 18 is constant and \(3x\) contains the variable \(x\). Thus, simplification is complete, and the expression is already in its simplest form. Simplifying initially complex expressions helps in solving equations, as it reveals the core relationships between the variables involved.
Multiplication Distributive Law
The multiplication distributive law is a fundamental property that helps in multiplying a single term across terms within parentheses. It states: \(a(b+c) = ab + ac\). This law is essential for expanding algebraic expressions so that they can be simplified or evaluated further.
In regard to the problem \(3(6+x)\), this law allows us to distribute 3 through the terms inside the parentheses. First, multiply 3 by 6 to get 18. Then, multiply 3 by \(x\) to get \(3x\). Thus, the expression \(3(6+x)\) simplifies to \(18 + 3x\).
In regard to the problem \(3(6+x)\), this law allows us to distribute 3 through the terms inside the parentheses. First, multiply 3 by 6 to get 18. Then, multiply 3 by \(x\) to get \(3x\). Thus, the expression \(3(6+x)\) simplifies to \(18 + 3x\).
- The distributive law is especially useful in algebra and arithmetic because it simplifies complex expressions into manageable parts.
- It is also foundational in advanced mathematics, as it is central to operations involving polynomials and solving equations.
Other exercises in this chapter
Problem 38
Add or subcract as indicared. Write the answer in lower terms. See Erample 5 $$ \frac{18}{35}-\frac{11}{35} $$
View solution Problem 39
Add or subcract as indicared. Write the answer in lower terms. See Erample 5 $$ \frac{23}{105}+\frac{4}{105} $$
View solution Problem 39
Decide whether each statement is true or false. The product of three negative integers is negative.
View solution Problem 39
Add See Examples \(\ell\) through 7 . $$ -\frac{7}{10}+\left(-\frac{3}{5}\right) $$
View solution