Problem 39
Question
Two different proteins \(X\) and \(Y\) are dissolved in aqueous solution at \(37^{\circ} \mathrm{C}\) . The proteins bind in a \(1 : 1\) ratio to form \(X Y . A\) solution that is initially 1.00 \(\mathrm{mM}\) in each protein is allowed to reach equilibrium. At equilibrium, 0.20 \(\mathrm{mM}\) of free \(\mathrm{X}\) and 0.20 \(\mathrm{mM}\) of free Y remain. What is \(K_{c}\) for the reaction?
Step-by-Step Solution
Verified Answer
The equilibrium constant, \(K_c\), for the reaction \(X + Y \rightleftharpoons XY\) can be determined using the given initial and equilibrium concentrations of X and Y. From the ICE table, we find that the change in concentration (x) is 0.80 mM and the equilibrium concentration of XY is also 0.80 mM. Using the formula \(K_c = \frac{[XY]}{[X][Y]}\) and substituting the equilibrium concentrations, we find that \(K_c = \frac{0.80}{(0.20)(0.20)} = 20\). Therefore, the equilibrium constant for this reaction is 20.
1Step 1: Write the balanced chemical equation
Firstly, we need to write the balanced chemical equation for the reaction. Since the proteins X and Y bind in a 1:1 ratio to form XY, we can write the chemical equation as:
\(X + Y \rightleftharpoons XY\)
2Step 2: Set up the ICE table
To find the equilibrium constant (\(K_c\)), we need to know the equilibrium concentrations of all the species involved in the reaction. We are given the initial and equilibrium concentrations of X and Y. We can set up an Initial, Change, and Equilibrium (ICE) table to represent the changes in concentrations during the reaction.
| | X | Y | XY |
|--------|------|------|------|
| Initial| 1.00 | 1.00 | 0 |
| Change | -x | -x | +x |
| Equilibrium | 0.20 | 0.20 | ? |
3Step 3: Determine the change in concentration
From the ICE table, we can determine the change in concentration (x) for each species using the given equilibrium concentrations of X and Y:
\(x = 1.00 - 0.20 = 0.80\)
4Step 4: Find the equilibrium concentration of XY
Now that we have found the change in concentration (x), we can determine the equilibrium concentration of XY:
Initial concentration of XY + Change in concentration = Equilibrium concentration of XY
\(0 + 0.80 = 0.80\,\text{mM}\)
5Step 5: Calculate the equilibrium constant, \(K_c\)
The equilibrium constant, \(K_c\), can be calculated using the equilibrium concentrations of the species in the chemical equation:
\(K_c = \frac{[XY]}{[X][Y]}\)
Substitute the equilibrium concentrations:
\(K_c = \frac{0.80}{(0.20)(0.20)}\)
Calculate the value of \(K_c\):
\(K_c = \frac{0.80}{0.04} = 20\)
Thus, the equilibrium constant for the reaction is 20.
Key Concepts
Protein BindingChemical EquilibriumICE Table
Protein Binding
In the context of biochemistry and molecular biology, protein binding is a crucial concept. It involves the interaction between two or more proteins or between a protein and other molecules. This is particularly important because it can affect protein function, structure, and overall biological activity. When proteins X and Y bind to form a complex, XY, they are effectively conducting a form of communication necessary for executing biological functions.
Protein interactions like this often occur in a 1:1 ratio, as it happens in our example exercise. In this scenario, equal concentrations of proteins X and Y combine to form a single unit of XY. Understanding these interactions helps scientists learn how proteins regulate processes such as metabolism or signal transduction in cells.
Why is protein binding significant? It influences:
Protein interactions like this often occur in a 1:1 ratio, as it happens in our example exercise. In this scenario, equal concentrations of proteins X and Y combine to form a single unit of XY. Understanding these interactions helps scientists learn how proteins regulate processes such as metabolism or signal transduction in cells.
Why is protein binding significant? It influences:
- Enzyme activity and thus metabolic pathways
- The regulation of biological processes such as gene expression
- Cellular signaling and communication
Chemical Equilibrium
Chemical equilibrium represents a state in which the concentrations of reactants and products remain constant over time because the rate of the forward reaction equals the rate of the backward reaction. In the case of the binding of proteins X and Y, once equilibrium is reached, the amount of free proteins stops changing because the formation and dissociation of XY occur at the same rate.
Reaching chemical equilibrium is essential because it enables biological systems to maintain homeostasis. This is the balance within biological systems that ensures optimal operative conditions.
Several factors can affect chemical equilibrium, including:
Reaching chemical equilibrium is essential because it enables biological systems to maintain homeostasis. This is the balance within biological systems that ensures optimal operative conditions.
Several factors can affect chemical equilibrium, including:
- Temperature: As demonstrated in the exercise, temperature can influence equilibration because molecules have more kinetic energy at higher temperatures, potentially altering reaction rates.
- Concentration: Changes in concentrations of reactants or products can shift the equilibrium, a principle known as Le Chatelier's principle.
ICE Table
An ICE table is a systematic way of tracking the concentrations of reactants and products over the course of a chemical reaction to find equilibrium concentrations. The acronym 'ICE' stands for Initial, Change, and Equilibrium, reflecting three stages of this process.
Let's break down how an ICE table works:
Let's break down how an ICE table works:
- **Initial:** Begin with the initial concentrations or amounts of each reactant and product. In our example, the initial concentrations of proteins X and Y are both 1.00 mM.
- **Change:** As the reaction progresses, the change in concentration (\(x\)) is observed. In this context, if a certain amount is consumed, we denote it with a negative sign, while production is marked as positive.
- **Equilibrium:** Finally, you'll have the equilibrium concentrations, reached after accounting for the changes that have occurred. For the protein binding, the equilibrium concentrations for both X and Y become 0.20 mM, meaning the change (\(x\)) was 0.80 mM.
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