Problem 39
Question
The onlystatement among the following that is a tautology is \([ \mathrm{RS}]\) (a) \(A \wedge(A \vee B)\) (b) \(A \vee(A \wedge B)\) (c) \([\mathrm{A} \wedge(\mathrm{A} \rightarrow \mathrm{B})] \rightarrow \mathrm{B} \quad\) (d) \(\mathrm{B} \rightarrow[\mathrm{A} \wedge(\mathrm{A} \rightarrow \mathrm{B})]\)
Step-by-Step Solution
Verified Answer
Option (c) is the tautology: \([A \wedge (A \rightarrow B)] \rightarrow B\).
1Step 1: Analyzing Option (a)
Option (a) is \(A \wedge (A \vee B)\). According to the distributive laws, \(A \wedge (A \vee B)\) simplifies to \(A\). Since \(A\) is not always true for every possible truth value (it depends on the truth value of \(A\)), it cannot be a tautology.
2Step 2: Analyzing Option (b)
Option (b) is \(A \vee (A \wedge B)\). Using the absorption law, \(A \vee (A \wedge B)\) simplifies to \(A\). Similar to option (a), since \(A\) is not always true irrespective of its truth value, this is not a tautology.
3Step 3: Analyzing Option (c)
Option (c) is \([A \wedge (A \rightarrow B)] \rightarrow B\). This can be rewritten using the implication as \([A \wedge (\lnot A \vee B)] \rightarrow B\). It further simplifies to \([A \wedge B] \rightarrow B\), which is always true because if \(A \wedge B\) is true, \(B\) must be true, making the implication valid in all cases. Hence, it is a tautology.
4Step 4: Analyzing Option (d)
Option (d) is \(B \rightarrow [A \wedge (A \rightarrow B)]\). Rewriting using the implication, we have \(B \rightarrow [A \wedge (\lnot A \vee B)]\) which simplifies to \(B \rightarrow (A \wedge B)\). This expression is not necessarily a tautology because when \(B\) is true, \(A\) need not necessarily be true, making \(A \wedge B\) false, which invalidates the implication in some cases.
Key Concepts
Logical ExpressionsTruth TablesLogical Simplification
Logical Expressions
Logical expressions are mathematical expressions used in logic to represent propositions or statements. These expressions consist of variables, logical operators, and constants that collectively describe the logic of particular scenarios. Logical expressions can define a variety of logical relationships and outcomes. In this context, a tautology is a specific type of logical expression that is always true, regardless of the assigned truth values of the variables involved.
For example:
For example:
- The expression \(A \wedge (A \vee B)\) uses logical conjunction \(\wedge\) and disjunction \(\vee\) to combine propositions.
- The expression \(A \vee (A \wedge B)\), which applies the absorption law, simplifies to another logical expression.
Truth Tables
Truth tables are valuable tools used to list all possible truth values of a logical expression. They help in understanding how variables and logical operators combine to produce true or false outcomes. Each row in the table corresponds to a possible configuration of truth values for the involved variables, and the resulting truth value of the expression is computed for each configuration.
Consider the expression \([A \wedge (A \rightarrow B)] \rightarrow B\). To understand its validity as a tautology, a truth table can be constructed where:
Consider the expression \([A \wedge (A \rightarrow B)] \rightarrow B\). To understand its validity as a tautology, a truth table can be constructed where:
- If \(A\) is true and \(B\) is false, \(A \rightarrow B\) is false, making \(A \wedge (A \rightarrow B)\) false, satisfying the implication \([A \wedge (A \rightarrow B)] \rightarrow B\).
- In all other cases, the expression results in true, confirming its status as a tautology.
Logical Simplification
Logical simplification involves reducing complex logical expressions to their simplest form. This process often makes it easier to understand the core logical relationships and evaluate their truth values. Applying laws such as distributive, absorption, or De Morgan's laws can significantly streamline logical expressions.
For instance:
For instance:
- In the expression \(A \wedge (A \vee B)\), using the distributive law results in \(A\).
- Further, the expression \(A \vee (A \wedge B)\) can be simplified to \(A\) using the absorption law.
Other exercises in this chapter
Problem 37
Let \(p\) and \(q\) be two Statements. Amongst the following, the Statement that is equivalent to \(p \rightarrow q\) is |Online May \(\mathbf{1 9 ,} \mathbf{2
View solution Problem 38
The logically equivalent preposition of \(p \Leftrightarrow q\) is (a) \((p \Rightarrow q) \wedge(q \Rightarrow p)\) (b) \(p \wedge q\) (c) \((p \wedge q) \vee(
View solution Problem 40
Statement- \(1: \sim(p \leftrightarrow \sim q)\) is equivalent to \(p \leftrightarrow q\). Statement- \(2: \sim(p \leftrightarrow \sim q)\) is a tantology (a) S
View solution Problem 41
The statement \(p \rightarrow(q \rightarrow p)\) is equivalent to (a) \(p \rightarrow(p \rightarrow q)\) (b) \(p \rightarrow(p \vee q)\) (c) \(p \rightarrow(p \
View solution