Problem 39
Question
$$ \text { . Prove that } \lim _{x \rightarrow c}|x|=|c| \text { . } $$
Step-by-Step Solution
Verified Answer
The limit is \(|c|\), because \(| |x| - |c| |\) is less than any \(\varepsilon\) for \(|x - c| < \varepsilon\).
1Step 1: Understand the Problem Statement
We need to prove that the limit of the absolute value function \(|x|\) as \(x\) approaches \(c\) is equal to the absolute value of \(c\), that is, \( \lim_{x \to c} |x| = |c| \).
2Step 2: Recall the Definition of Absolute Value
The absolute value of a number \(x\), denoted \(|x|\), is \(x\) if \(x \geq 0\) and \(-x\) if \(x < 0\). This function is continuous everywhere.
3Step 3: Definition of a Limit
According to the definition of a limit, \( \lim_{x \to c} f(x) = L \) if for every \(\varepsilon > 0\), there exists a \(\delta > 0\) such that whenever \(0 < |x - c| < \delta\), it follows that \(|f(x) - L| < \varepsilon\).
4Step 4: Apply the Limit Definition to |x|
For \(|x|\), we want \(| |x| - |c| | < \varepsilon \) whenever \(0 < |x - c| < \delta \). Start by observing that \(| |x| - |c| | \leq |x - c| \).
5Step 5: Choose \(\delta\) and Conclude
By our observation, \(| |x| - |c| | \leq |x - c|\). Thus, setting \(\delta = \varepsilon\) ensures that \(| |x| - |c| | < \varepsilon \) whenever \(0 < |x - c| < \delta\), which proves the limit is \(|c|\).
Key Concepts
Definition of LimitAbsolute Value FunctionContinuity of Functions
Definition of Limit
In mathematics, understanding the concept of a limit is crucial when studying how functions behave as they approach a specific point. Specifically, when we say that the limit of a function \( f(x) \) as \( x \) approaches some point \( c \) is \( L \), denoted as \( \lim_{x \to c} f(x) = L \), we mean that \( f(x) \) gets arbitrarily close to \( L \) as \( x \) gets closer and closer to \( c \).
Here's what's happening in simpler terms:
Here's what's happening in simpler terms:
- We look at what happens to \( f(x) \) very near \( x = c \) and make sure \( f(x) \) can get as close as we like to \( L \).
- For every tiny positive distance, let's call it \( \varepsilon \), between \( f(x) \) and \( L \), there should be a range (\( \delta \)) where \( x \) stays close to \( c \) and ensures \( f(x) \) within that distance.
Absolute Value Function
The absolute value function is a simple yet essential concept in mathematics. Denoted by \(|x|\), it measures how far a number is from zero on the number line. Here's how it works:
For example:
- If \( x \) is a positive number or zero, \(|x|\) is simply \( x \).
- If \( x \) is negative, then \(|x|\) is the positive opposite of \( x \), or \(-x\).
For example:
- |3| = 3 (because 3 is positive)
- |-5| = 5 (because -5 is negative, so the positive opposite is 5)
Continuity of Functions
Continuous functions are vital in calculus and analysis because they don't have sudden jumps or interruptions. Importantly, they precisely maintain their values when variables slightly shift, making limits more straightforward to manage.
For a function to be continuous at a point \( c \), it satisfies these criteria:
For a function to be continuous at a point \( c \), it satisfies these criteria:
- The function \( f(x) \) is defined at \( c \), which means \( f(c) \) exists.
- The limit of \( f(x) \) as \( x \) approaches \( c \) exists, denoted as \( \lim_{x \to c} f(x) \).
- The limit \( \lim_{x \to c} f(x) \) equals the function value \( f(c) \).
Other exercises in this chapter
Problem 39
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