Problem 39
Question
Solve the rational inequality. $$\frac{x-1}{x+2} \geq 0$$
Step-by-Step Solution
Verified Answer
The solution to the inequality \(\frac{x-1}{x+2} \geq 0\) is \((-∞,-2] \cup [1,∞)\)
1Step 1: Identify and Isolate the Critical Points
Find the critical points by setting the numerator and denominator equal to zero separately. \nFor the numerator x-1 = 0, we get x=1. \nFor the denominator x+2 = 0, we get x=-2. These values are the x-values where the function changes its sign or is undefined.
2Step 2: Construct the Sign Chart
A sign chart is used to determine where a function is positive or negative. To create the sign chart, list the critical points in ascending order on a number line. Divide the number line into intervals using the critical points. These intervals are (-∞,-2], [-2, 1], and [1,∞).
3Step 3: Test each Interval
Select a test point from each interval and substitute these points into the inequality to determine whether the function is positive or negative. \n\nFor the interval (-∞,-2], choose x=-3: \[ \frac{(-3)-1}{(-3)+2}=\frac{-4}{-1}=4>0\], hence this interval is satisfied.\n\nFor the interval [-2, 1], choose x=0: \[ \frac{0-1}{0+2}=-\frac{1}{2}<0\], hence this interval is not satisfied. \n\nFor the interval [1,∞), choose x=2: \[ \frac{2-1}{2+2}=\frac{1}{4}>0], hence this interval is satisfied.
4Step 4: Write the Solution in Interval Notation
The function is greater than or equal to zero when x is either less than or equal to -2, or greater than or equal to 1. Therefore, the solution to this inequality in interval notation should be: \((-∞,-2] \cup [1,∞)\)
Key Concepts
Critical PointsSign ChartInterval Notation
Critical Points
When solving rational inequalities like \( \frac{x-1}{x+2} \geq 0 \), one important concept is identifying the critical points. These are x-values where the function equals zero or becomes undefined. To find them, set both the numerator and denominator equal to zero separately.
- Set the numerator \( x - 1 = 0 \) to find \( x = 1 \).
- Set the denominator \( x + 2 = 0 \) to find \( x = -2 \).
Sign Chart
A sign chart is a useful tool to visually map the positivity and negativity of a function over different intervals segregated by our critical points. For the inequality \( \frac{x-1}{x+2} \geq 0 \), we use the critical points to create distinct regions on a number line.
By constructing and analyzing a sign chart, we gain insights into where the function satisfies the inequality, making it an indispensable tool in solving rational inequalities.
- List the critical points in ascending order: \(-2\) and \(1\).
- Divide the number line into intervals: \((-\infty, -2] \), \([-2, 1] \), and \([1, \infty)\).
By constructing and analyzing a sign chart, we gain insights into where the function satisfies the inequality, making it an indispensable tool in solving rational inequalities.
Interval Notation
Interval notation is a concise way to express the solution to an inequality. For the problem \( \frac{x-1}{x+2} \geq 0 \), we determined through the sign chart that the solution is valid in certain intervals. In interval notation, we include only the intervals where the inequality holds.
This format is efficient and clear. It indicates which values of \( x \) satisfy the inequality without unnecessary detail. Interval notation captures both endpoints where inequality holds inclusive if the inequality is non-strict, indicated by square brackets. An important takeaway is that this notation is useful for presenting solutions succinctly and accurately in mathematical contexts.
- The function is non-negative (satisfies \( \geq 0 \)) in the intervals \((-\infty, -2] \) and \([1, \infty)\).
- Use a union symbol \(\cup\) to join these intervals: \((-\infty, -2] \cup [1, \infty)\).
This format is efficient and clear. It indicates which values of \( x \) satisfy the inequality without unnecessary detail. Interval notation captures both endpoints where inequality holds inclusive if the inequality is non-strict, indicated by square brackets. An important takeaway is that this notation is useful for presenting solutions succinctly and accurately in mathematical contexts.
Other exercises in this chapter
Problem 38
Sketch the polynomial function using transformations. $$h(x)=(x+1)^{4}$$
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Sketch a graph of the rational function. Indicate any vertical and horizontal asymptote(s) and all intercepts. $$g(x)=\frac{3-x}{x+4}$$
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