Problem 39
Question
Solve each equation for \(0 \leq \theta<2 \pi\) $$ \csc \theta=-1 $$
Step-by-Step Solution
Verified Answer
The solution to the equation \( \csc \theta = -1 \) for \(0 \leq \theta <2 \pi\) is \( \theta = 3\pi/2 \).
1Step 1: Understand the Cosecant Function
The cosecant function is defined as \( \csc \theta = 1/ \sin \theta \). So, when \( \csc \theta = -1 \), it means \( \sin \theta = -1 \).
2Step 2: Determine the Angle
From the unit circle, it is known that \( \sin \theta = -1 \) when \( \theta = 3\pi/2 \).
3Step 3: Check the Range
Since the angle \( \theta = 3\pi/2 \) falls within the range \( 0 \leq \theta < 2\pi \), this is the solution to the given equation.
Key Concepts
Cosecant FunctionUnit CircleTrigonometric Identities
Cosecant Function
The cosecant function, denoted as \( \csc \theta \), is a trigonometric function which is the reciprocal of the sine function. This means that \( \csc \theta = \frac{1}{\sin \theta} \).
When you encounter an equation involving the cosecant function, such as \( \csc \theta = -1 \), it is important to remember that you can rewrite it in terms of the sine function: \( \sin \theta = -1 \).
Transforming the equation like this often makes it easier to solve, especially when you use familiar values from the unit circle.
When you encounter an equation involving the cosecant function, such as \( \csc \theta = -1 \), it is important to remember that you can rewrite it in terms of the sine function: \( \sin \theta = -1 \).
Transforming the equation like this often makes it easier to solve, especially when you use familiar values from the unit circle.
- Keep in mind that the cosecant function is undefined when \( \sin \theta = 0 \) because division by zero is not possible.
- The graph of the cosecant function is closely related to that of the sine function, featuring the same periodicity and zero-crossings where it is undefined.
Unit Circle
The unit circle is a powerful tool for solving trigonometric equations, especially when you are trying to determine angles that satisfy a particular trigonometric function. In the context of the exercise, the unit circle helps us find where \( \sin \theta = -1 \).
The unit circle is a circle with a radius of 1 centered at the origin of the coordinate plane. On this circle, each angle \( \theta \) corresponds to a point, where the x-coordinate is \( \cos \theta \) and the y-coordinate is \( \sin \theta \).
The unit circle is a circle with a radius of 1 centered at the origin of the coordinate plane. On this circle, each angle \( \theta \) corresponds to a point, where the x-coordinate is \( \cos \theta \) and the y-coordinate is \( \sin \theta \).
- The full circle extends from \( 0 \) radians (or degrees) to \( 2\pi \) radians (360 degrees).
- The angle \( \theta = \frac{3\pi}{2} \) is located at the bottom of the unit circle, where the coordinates are (0, -1).
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all values of the variables involved. These identities are essential tools for manipulating and solving trigonometric equations. Some key identities include:
By using these identities, one can consistently solve complex trigonometric problems by transforming them into simpler forms or looking up related values. Building a strong grasp on these identities will make solving trigonometric equations much easier.
- Reciprocal identities, such as \( \csc \theta = \frac{1}{\sin \theta} \)
- Pythagorean identities, such as \( \sin^2 \theta + \cos^2 \theta = 1 \)
- Angle sum and difference identities, like \( \sin(\alpha \pm \beta) = \sin \alpha \cos \beta \pm \cos \alpha \sin \beta \)
By using these identities, one can consistently solve complex trigonometric problems by transforming them into simpler forms or looking up related values. Building a strong grasp on these identities will make solving trigonometric equations much easier.
Other exercises in this chapter
Problem 38
In \(\triangle A B C, m \angle A=40^{\circ}\) and \(m \angle B=30^{\circ} .\) Find each value to the nearest tenth. Find \(A C\) for \(B C=10.5 \mathrm{m}\)
View solution Problem 39
Given \(\cos \theta=\frac{3}{5} \operatorname{and} 270^{\circ}
View solution Problem 39
Verify each identity. $$ \cos (A+B)=\cos A \cos B-\sin A \sin B $$
View solution Problem 39
Express the first trigonometric function in terms of the second. $$ \sin \theta, \cos \theta $$
View solution