Problem 39
Question
Sketch a graph of the polar equation. $$ r=\theta, \quad \theta \geq 0 \quad(\text { spiral }) $$
Step-by-Step Solution
Verified Answer
The graph is an Archimedean spiral starting at the origin and spiraling outwards.
1Step 1: Understand the Polar Equation
The polar equation given is \( r = \theta \), where \( \theta \geq 0 \). This means that the radius \( r \) is equal to the angle \( \theta \). The point \( (r, \theta) \) in polar coordinates represents the position on the graph.
2Step 2: Plot Basic Points
Start by substituting small, incremental values of \( \theta \) to find corresponding values of \( r \). For example: \( \theta = 0 \) gives \( r = 0 \), \( \theta = \frac{\pi}{4} \) gives \( r = \frac{\pi}{4} \), and so on. Mark these points on a polar grid.
3Step 3: Identify the Pattern
Observe the pattern as \( \theta \) increases and \( r \) also increases. The points plotted will start to spiral outwards from the origin because the distance \( r \) becomes larger as the angle \( \theta \) increases.
4Step 4: Sketch the Graph
Using the points and understanding of the pattern, sketch a smooth curve that spirals outwards from the origin. The curve becomes more spaced out as \( \theta \) increases because \( r = \theta \) means \( r \) must increase linearly as \( \theta \) increases.
5Step 5: Label the Graph
Ensure the graph is labeled properly, indicating that it is a spiral starting from the origin. You can indicate some example points to show the relation \( r = \theta \).
Key Concepts
Polar EquationSpiral GraphGraph Sketching
Polar Equation
Polar coordinates provide a unique way of describing a point's location on a plane using a radius and an angle. In a polar equation, such as \( r = \theta \), \( r \) denotes the radial distance from the origin, while \( \theta \) signifies the angle formed with the positive x-axis. Unlike Cartesian coordinates that use x and y, polar coordinates emphasize radial distance and direction. This makes them particularly useful for equations describing curves like spirals and circles.
To work with a polar equation, you treat \( \theta \) as your variable and calculate \( r \) for varying values of \( \theta \). For example, if \( \theta = 0 \), then \( r = 0 \). As \( \theta \) increases, you'll generate a series of points \((r, \theta)\), defining the curve's outline on a polar grid. This equation simplifies computations for certain types of curves, allowing the demonstration of spirals in a neat and comprehensible way.
To work with a polar equation, you treat \( \theta \) as your variable and calculate \( r \) for varying values of \( \theta \). For example, if \( \theta = 0 \), then \( r = 0 \). As \( \theta \) increases, you'll generate a series of points \((r, \theta)\), defining the curve's outline on a polar grid. This equation simplifies computations for certain types of curves, allowing the demonstration of spirals in a neat and comprehensible way.
Spiral Graph
When plotting a spiral graph, you encounter an enchanting pattern that naturally expands outward. The given polar equation \( r = \theta \) perfectly exemplifies this, forming an Archimedean spiral. The key characteristic of such a spiral is its constant increase in radial distance at a linear rate as the angle increases.
In practice, as \( \theta \) moves from 0 and grows, \( r = \theta \) ensures that each point \((r, \theta)\) is further from the origin than the last, leading to the iconic spiral shape.
In practice, as \( \theta \) moves from 0 and grows, \( r = \theta \) ensures that each point \((r, \theta)\) is further from the origin than the last, leading to the iconic spiral shape.
- The spiral begins at the origin when both \( r \) and \( \theta \) equal zero.
- Moving outward, \( r \) is directly proportional to \( \theta \), creating evenly spaced loops.
- The result is a beautifully expanding curve that elegantly demonstrates the interrelation between radius and angle in polar graphs.
Graph Sketching
Sketching a spiral from the polar equation \( r = \theta \) involves a step-by-step approach relying on plotting key points and intuitively connecting them. Begin by selecting specific values of \( \theta \), such as \( 0, \frac{\pi}{4}, \frac{\pi}{2}, \pi \), and calculating the corresponding \( r \) for each. By marking these points on a polar grid, you form the skeleton of your graph.
Next, identify trends and patterns: here, observe how each new point lies further from the origin than the previous one, confirming the spiral nature. Place more points to get an accurate idea of the curve's path. Using these guideposts, draw a smooth, continuous curve that gracefully extends outward from the origin.
Next, identify trends and patterns: here, observe how each new point lies further from the origin than the previous one, confirming the spiral nature. Place more points to get an accurate idea of the curve's path. Using these guideposts, draw a smooth, continuous curve that gracefully extends outward from the origin.
- Avoid sharp angles; the curve should spiral out smoothly.
- Consistently increment \( \theta \) in small steps to ensure accuracy and a clear pattern.
- Label the graph to clarify it represents a spiral, specifying that \( r \) equates \( \theta \).
Other exercises in this chapter
Problem 38
\(37-40=\) Sketch the curve given by the parametric equations. $$ x=\sin t, \quad y=\sin 2 t $$
View solution Problem 39
Convert the rectangular coordinates to polar coordinates with \(r>0\) and \(0 \leq \theta
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Write the complex number in polar form with argument \(\theta\) between 0 and 2\(\pi\) $$ 4 \sqrt{3}-4 i $$
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\(37-40=\) Sketch the curve given by the parametric equations. $$ X=\frac{3 t}{1+t^{3}}, \quad y=\frac{3 t^{2}}{1+t^{3}} $$
View solution