Problem 39
Question
Prove that \( \displaystyle \lim_{x \to 0}x^4 \cos \frac{2}{x} = 0 \).
Step-by-Step Solution
Verified Answer
The limit is 0 by the Squeeze Theorem.
1Step 1: Understand the Problem Statement
We need to prove the limit \( \lim_{x \to 0} x^4 \cos\left(\frac{2}{x}\right) = 0 \). This means as \( x \) approaches 0, the expression \( x^4 \cos\left(\frac{2}{x}\right) \) should infinitely get closer to 0.
2Step 2: Analyze the Trigonometric Component
The function \( \cos\left(\frac{2}{x}\right) \) oscillates between -1 and 1 for any real number \( x \). Therefore, \( -1 \leq \cos\left(\frac{2}{x}\right) \leq 1 \) for all \( x eq 0 \).
3Step 3: Apply Absolute Value Properties
Given the properties of cosine, the absolute value of the product \( x^4 \cos\left(\frac{2}{x}\right) \) is bounded by the absolute value of \( x^4 \). Therefore, \(-x^4 \leq x^4 \cos\left(\frac{2}{x}\right) \leq x^4 \).
4Step 4: Evaluate the Limit of Boundary Functions
Consider \( \lim_{x \to 0} -x^4 \) and \( \lim_{x \to 0} x^4 \). Since both \( -x^4 \) and \( x^4 \) approach 0 as \( x \to 0 \), by the Squeeze Theorem, we conclude that the limit of any function sandwiched between them will also be 0.
5Step 5: Apply the Squeeze Theorem
Since \(-x^4 \leq x^4 \cos\left(\frac{2}{x}\right) \leq x^4 \) and both bounding functions tend to 0 as \( x \to 0 \), it follows by the Squeeze Theorem that \( \lim_{x \to 0} x^4 \cos\left(\frac{2}{x}\right) = 0 \).
Key Concepts
Squeeze TheoremTrigonometric LimitsCalculus Limit Theorems
Squeeze Theorem
The Squeeze Theorem is a powerful method for proving limits in calculus. It is particularly useful when dealing with functions that oscillate, like the cosine function. The theorem states that if a function is "squeezed" between two other functions that share the same limit at a certain point, the squeezed function must also approach that limit.
Let's break it down into simple terms:
Let's break it down into simple terms:
- You have three functions: \( f(x) \), \( g(x) \), and \( h(x) \).
- For all values near a point \( a \), \( f(x) \leq g(x) \leq h(x) \).
- Both \( f(x) \) and \( h(x) \) have the same limit, \( L \), as \( x \) approaches \( a \).
- Then, \( g(x) \) must also have the limit \( L \) as \( x \to a \).
Trigonometric Limits
Trigonometric limits often require special techniques like the Squeeze Theorem due to their oscillatory nature. Functions such as sine and cosine do not settle on a single value but instead fluctuate indefinitely between -1 and 1.
This behavior can complicate determining limits directly because, unlike polynomial or exponential functions, trigonometric functions do not converge to a particular point.
The key to evaluating these limits lies in understanding the properties of the functions:
This behavior can complicate determining limits directly because, unlike polynomial or exponential functions, trigonometric functions do not converge to a particular point.
The key to evaluating these limits lies in understanding the properties of the functions:
- For \( \cos\left(\frac{2}{x}\right) \), the oscillation between -1 and 1 assures that it does not approach a single number as \( x \) approaches 0.
- Despite this, by multiplying \( \cos\left(\frac{2}{x}\right) \) with \( x^4 \), which does tend to 0, we can conclude using bounds that the overall expression approaches 0 as well.
Calculus Limit Theorems
Calculus limit theorems provide foundational tools for solving problems involving limits. Each theorem gives us insight into how functions behave as they approach certain values:
Each theorem leverages unique properties of functions, offering strategies that cater to their specific challenges. Mastery of these theorems is critical for any calculus student aiming to conquer a wide array of limit problems.
- Squeeze Theorem: Useful for functions caught between two simpler limits.
- Direct Substitution Theorem: Applies when inserting the value directly gives a definitive result.
- Limit Laws: Includes sum, product, and quotient laws for accommodating different function types.
Each theorem leverages unique properties of functions, offering strategies that cater to their specific challenges. Mastery of these theorems is critical for any calculus student aiming to conquer a wide array of limit problems.
Other exercises in this chapter
Problem 39
Show that \( f \) is continuous on \( (-\infty, \infty ) \). \( f(x) = \left\\{ \begin{array}{ll} 1 - x^2 & \mbox{if \) x \le 1 \(}\\\ \ln x & \mbox{if \) x > 1
View solution Problem 39
If the function \( f \) is defined by $$ f(x) = \left\\{ \begin{array}{ll} 0 & \mbox{if \( x \) is rational}\\\ 1 & \mbox{if \( x \) is irrational} \end{array}
View solution Problem 39
Determine the infinite limit. \( \displaystyle \lim_{x \to 2\pi^-}x\csc x \)
View solution Problem 40
Suppose \( N \) is the number of people in the United States who travel by car to another state for a vacation this year when the average price of gasoline is \
View solution