Problem 39
Question
In Problems 39 and 40 , determine which complex number is closer to the origin. $$ 10+8 i, \quad 11-6 i $$
Step-by-Step Solution
Verified Answer
The complex number \( 11 - 6i \) is closer to the origin.
1Step 1: Understand the Concept
To determine which complex number is closer to the origin, we need to calculate the magnitude of each complex number. The one with the smaller magnitude is closer to the origin.
2Step 2: Calculate the Magnitude of the First Complex Number
The magnitude of a complex number \( a + bi \) is calculated using the formula \( \sqrt{a^2 + b^2} \). For the complex number \( 10 + 8i \), the magnitude is \( \sqrt{10^2 + 8^2} \). Calculate this as follows:\[ \sqrt{10^2 + 8^2} = \sqrt{100 + 64} = \sqrt{164} = 12.81 \]
3Step 3: Calculate the Magnitude of the Second Complex Number
Now calculate the magnitude of the complex number \( 11 - 6i \) using the same formula. The magnitude is \( \sqrt{11^2 + (-6)^2} \). Calculate this as follows:\[ \sqrt{11^2 + (-6)^2} = \sqrt{121 + 36} = \sqrt{157} = 12.53 \]
4Step 4: Compare the Magnitudes
Compare the magnitudes of the two complex numbers. The first complex number \( 10 + 8i \) has a magnitude of 12.81, and the second \( 11 - 6i \) has a magnitude of 12.53.
5Step 5: Determine Closer Number to the Origin
Since 12.53 (magnitude of \( 11 - 6i \)) is less than 12.81 (magnitude of \( 10 + 8i \)), the complex number \( 11 -6i \) is closer to the origin.
Key Concepts
Magnitude of Complex NumbersDistance from OriginComplex Number Comparison
Magnitude of Complex Numbers
The magnitude of a complex number is a measure of its distance from the origin in the complex plane. It's similar to finding the length of a vector that originates from the point (0, 0). The formula to calculate the magnitude of a complex number, which is commonly written as \( a + bi \), is \( \sqrt{a^2 + b^2} \). This formula derives from the Pythagorean theorem, making complex numbers easy to visualize as vectors.
- For \( 10 + 8i \), calculate as \( \sqrt{10^2 + 8^2} = \sqrt{164} = 12.81 \).
- For \( 11 - 6i \), calculate as \( \sqrt{11^2 + (-6)^2} = \sqrt{157} = 12.53 \).
Distance from Origin
Distance from the origin to any point in the complex plane can be determined using the magnitude of the corresponding complex number. The term "origin" refers to the point (0, 0), which is where both real and imaginary components are zero in the plane.Using the magnitude:- A smaller magnitude indicates that the complex number is closer to the origin.- For example, the magnitude of \( 11 - 6i \) is less than \( 10 + 8i \), meaning \( 11 - 6i \) is closer to the origin.Understanding these distances allows for appropriate measures and placements of complex numbers on the plane, aiding in visualization and spatial reasoning.
Complex Number Comparison
Comparing complex numbers involves examining their magnitudes rather than their real or imaginary parts individually. The magnitude gives a complete sense of how far each number is from the origin, regardless of direction.Steps to compare:1. **Calculate magnitudes**: Each complex number must first have its magnitude calculated.2. **Compare the values**: A number with a smaller magnitude is closer to the origin.So, when comparing \( 10 + 8i \) and \( 11 - 6i \), we find that \( 11 - 6i \) has a smaller magnitude of 12.53 compared to 12.81 of \( 10 + 8i \). Therefore, \( 11 - 6i \) is closer to the origin. This process simplifies the understanding and comparison of complex numbers without needing their graphical representation.
Other exercises in this chapter
Problem 38
$$ f(z)=\frac{z-4+3 i}{z^{2}-6 z+25} $$
View solution Problem 39
(a) If \(z_{1}=-1\) and \(z_{2}=5 i\), verify that $$ \operatorname{Arg}\left(z_{1} z_{2}\right) \neq \operatorname{Arg}\left(z_{1}\right)+\operatorname{Arg}\le
View solution Problem 39
In Problems 39-42, find all values of the given quantity. \((-i)^{4 i}\)
View solution Problem 39
Show that the function \(f(z)=\bar{z}\) is nowhere differentiable.
View solution