Problem 39
Question
In Exercises \(39-44,\) (a) find a power function end behavior model for \(f .\) (b) Identify any horizontal asymptotes. $$f(x)=3 x^{2}-2 x+1$$
Step-by-Step Solution
Verified Answer
The power function end behavior model is \(+\infty\) and the function does not have a horizontal asymptote.
1Step 1: Determining the power function end behavior model
Consider the highest power term of the function \(f(x) = 3x^2 - 2x + 1\). That is \(3x^2\). The coefficient is positive and the power of \(x\) is even. So as \(x\) approaches \(+\infty\) and \(-\infty\), \(3x^2\) approaches \(+\infty\). Therefore, the power function end behavior model is \(+\infty\)
2Step 2: Identifying any horizontal asymptotes
As for the horizontal asymptotes, since the highest power of the function is \(2\) which is a finite number, and as \(x\) goes to \(+\infty\) or \(-\infty\), \(3x^2\) tends to \(+\infty\) and doesn't stay close to a constant number. Therefore, the function does not have a horizontal asymptote
Key Concepts
Power FunctionEnd BehaviorHorizontal Asymptotes
Power Function
In calculus, understanding the concept of a power function is crucial. A power function is typically in the form of \( f(x) = ax^n \), where \( a \) is a nonzero constant and \( n \) is a real number. In our given function \( f(x) = 3x^2 - 2x + 1 \), the power function is extracted by identifying the term with the highest power of \( x \), which is \( 3x^2 \). This means that as \( x \) becomes extremely large or very small, \( 3x^2 \) primarily dictates the behavior of the function.
- The presence of lower-degree terms, such as \(-2x + 1\), becomes negligible when compared to the term \(3x^2\) for large values of \(x\).
- This is because they do not grow as fast as the higher power term when \(x\) increases or decreases without bound.
End Behavior
End behavior of a function refers to the direction that the graph of a function heads as \( x \) approaches positive or negative infinity. In this case, we are focusing on the polynomial function \( f(x) = 3x^2 - 2x + 1 \). The most telling part of the end behavior comes from examining the power function, \( 3x^2 \). Since this is a quadratic function (the degree is 2 and is even), it will behave in a characteristic way:
- For positive values of \( x \) (as \( x \to +\infty \)), \( 3x^2 \to +\infty \), indicating that the function's graph opens upwards.
- For negative values of \( x \) (as \( x \to -\infty \)), \( 3x^2 \to +\infty \) as well, indicating the same upward direction.
Horizontal Asymptotes
The concept of horizontal asymptotes involves analyzing the behavior of a function as \( x \) approaches infinity. Specifically, horizontal asymptotes are straight lines that the graph of a function approaches but never touches as \( x \) tends towards \( +\infty \) or \( -\infty \). In considering our function \( f(x) = 3x^2 - 2x + 1 \), we check if there are any horizontal asymptotes by looking at the growth rate of the terms:
- Since the term \( 3x^2 \) grows much faster than \(-2x\) and \(1\) as \( x \) gets large, it dominates the behavior of \( f(x) \).
- A horizontal asymptote exists when the function approaches a constant value at infinity, which does not occur here as \( 3x^2 \to +\infty \).
Other exercises in this chapter
Problem 39
Multiple Choice Find the average rate of change of \(f(x)=x^{2}+x\) over the interval \([1,3] .\) . \(\begin{array}{ll}{\text { (A) } y=-2 x} & {\text { (B) } y
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Group Activity In Exercises \(37-40\) , verify that the function is continuous and state its domain. Indicate which theorems you are using, and which functions
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Multiple Choice Which of the following is an equation of the normal to the graph of \(f(x)=2 / x\) at \(x=1 ? \quad\) $$\begin{array}{ll}{\text { (A) } y=\frac{
View solution Problem 40
Group Activity In Exercises \(37-40\) , verify that the function is continuous and state its domain. Indicate which theorems you are using, and which functions
View solution