Problem 39
Question
In Exercises 39-42, find \(m\) and \(b\) such that \(y=m x+b\) is the equation of the line through the points. $$ (2,-1),(6,1) $$
Step-by-Step Solution
Verified Answer
The equation of the line passing through the given points (2, -1) and (6, 1) is: \(y = \frac{1}{2}x - 2\)
1Step 1: Find the slope of the line (m)
The formula to find the slope (m) is: \[m = \frac{{y_2 - y_1}}{{x_2 - x_1}}\]So, substituting the given points into the formula, we get:\[m = \frac{{1 - (-1)}}{{6 - 2}} = \frac{1}{2}\]
2Step 2: Find the y-intercept (b)
After finding the slope, the next step is to find the y-intercept. The 'y' intercept (b) can be found by substituting the value of m and one of the points into the equation \(y = mx + b\) and solving for 'b'. Let's choose the point (2, -1) for this calculation:\[-1 = \frac{1}{2} \cdot 2 + b \b = -1 - 1 = -2\]
3Step 3: Write the equation of the line
Finally, substitute the values of 'm' and 'b' back into the equation \(y = mx + b\). The equation of the line passing through the points (2, -1) and (6, 1) is: \(y = \frac{1}{2}x - 2\)
Key Concepts
Slope-Intercept FormFinding SlopeY-Intercept
Slope-Intercept Form
Understanding the slope-intercept form of a linear equation is essential in algebra. This form is written as \( y = mx + b \), where \( m \) represents the slope, and \( b \) is the y-intercept of the line. The beauty of this form lies in its simplicity; it allows you to easily visualize the line by knowing just two pieces of information: how steep the line is (slope) and where it crosses the y-axis (y-intercept).
For example, if you have an equation like \( y = 3x + 2 \), you can immediately identify that the slope of the line is 3, meaning for each unit increase in \( x \), \( y \) increases by 3 units. The y-intercept is 2, indicating that the line crosses the y-axis at the point (0, 2). This form is incredibly helpful for graphing linear equations and analyzing linear relationships quickly and effectively.
For example, if you have an equation like \( y = 3x + 2 \), you can immediately identify that the slope of the line is 3, meaning for each unit increase in \( x \), \( y \) increases by 3 units. The y-intercept is 2, indicating that the line crosses the y-axis at the point (0, 2). This form is incredibly helpful for graphing linear equations and analyzing linear relationships quickly and effectively.
Finding Slope
The slope of a line measures its steepness and direction. In other words, it tells us how much \( y \) changes for a change in \( x \). The slope is often denoted as \( m \) and can be found using the formula \( m = \frac{{\text{{rise}}}}{{\text{{run}}} = \frac{{y_2 - y_1}}{{x_2 - x_1}} \), where \( (x_1, y_1) \) and \( (x_2, y_2) \) are two distinct points on the line.
The process is straightforward. Subtract the y-coordinate of the first point from the y-coordinate of the second point, and do the same for the x-coordinates. Then, divide these two numbers to get the slope. For the line through the points \( (2,-1) \) and \( (6,1) \), the slope is calculated as \( m = \frac{1 - (-1)}{6 - 2} = \frac{2}{4} = \frac{1}{2} \). This fraction tells us that for every 2 units we move to the right along the x-axis, we move up 1 unit along the y-axis.
The process is straightforward. Subtract the y-coordinate of the first point from the y-coordinate of the second point, and do the same for the x-coordinates. Then, divide these two numbers to get the slope. For the line through the points \( (2,-1) \) and \( (6,1) \), the slope is calculated as \( m = \frac{1 - (-1)}{6 - 2} = \frac{2}{4} = \frac{1}{2} \). This fraction tells us that for every 2 units we move to the right along the x-axis, we move up 1 unit along the y-axis.
Y-Intercept
The y-intercept of a line is the point where the line crosses the y-axis. It's represented by the letter \( b \) in the slope-intercept equation \( y = mx + b \). Finding this value is a critical step in constructing a line's equation because it anchors the line at a specific location on the graph.
To determine the y-intercept, you can use one of the points on the line and the slope you've already found. Plugging these into the slope-intercept form and solving for \( b \) will yield the y-intercept. Let's take the point \( (2, -1) \) and a slope of \( \frac{1}{2} \) for instance. Plug these into the equation to get \( -1 = \frac{1}{2} \cdot 2 + b \), and solving for \( b \) gives us \( b = -1 - 1 = -2 \). This result tells us that our line's y-intercept is at the point \( (0, -2) \). Therefore, no matter where the line is or how it's slanted, it will always pass through this point on the y-axis.
To determine the y-intercept, you can use one of the points on the line and the slope you've already found. Plugging these into the slope-intercept form and solving for \( b \) will yield the y-intercept. Let's take the point \( (2, -1) \) and a slope of \( \frac{1}{2} \) for instance. Plug these into the equation to get \( -1 = \frac{1}{2} \cdot 2 + b \), and solving for \( b \) gives us \( b = -1 - 1 = -2 \). This result tells us that our line's y-intercept is at the point \( (0, -2) \). Therefore, no matter where the line is or how it's slanted, it will always pass through this point on the y-axis.
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