Problem 39
Question
In Exercises 33-40, if possible, find \(AB\) and state the order of the result. \(A=\left[\begin{array}{r} 10 \\ 12 \end{array}\right]\), \(B=\left[\begin{array}{r} 6 & -2 & 1 & 6 \end{array}\right]\)
Step-by-Step Solution
Verified Answer
The product of \(A\) and \(B\) is \(\left[\begin{array}{cccc} 60 & -20 & 10 & 60 \ 72 & -24 & 12 & 72 \end{array}\right]\) which is a 2x4 matrix.
1Step 1: Set Up the Matrices
Matrix \(A\) has two rows and one column, that contains the elements [10, 12]. Matrix \(B\) has one row and four columns, that contains the elements [6, -2, 1, 6].
2Step 2: Multiply the Matrices
The product of \(A\) and \(B\) is calculated by multiplying elements and adding up. First, we multiply the first row of \(A\) by the first column of \(B\), and then add the products. Repeat this for all rows in \(A\) and columns in \(B\).
3Step 3: Calculate the Elements of the New Matrix
The first element is \(10*6=60\), second element is \(10*(-2)=-20\), third element is \(10*1=10\) and forth is \(10*6=60\). Repeat this with the second row of \(A\), so the fifth element is \(12*6=72\), sixth element is \(12*(-2)=-24\), seventh element is \(12*1=12\) and the last element is \(12*6=72\).
Key Concepts
Understanding Matrix OrderMatrix ElementsThe Matrix Product
Understanding Matrix Order
When we talk about matrices, understanding their order is crucial. The order of a matrix is determined by its dimensions, which are specified as "rows by columns." This directly influences how matrix multiplication is performed and whether it is even possible.
- Matrix A is given as \(2 \times 1\), meaning it has 2 rows and 1 column.
- Matrix B is \(1 \times 4\), with 1 row and 4 columns.
- For two matrices to be multiplied, the number of columns in the first matrix must equal the number of rows in the second matrix. Here, since Matrix A has 1 column and Matrix B has 1 row, they satisfy the condition.
Matrix Elements
Matrix elements are the individual numbers within a matrix. Each element is uniquely positioned based on its row and column index, which is crucial when performing operations like matrix multiplication.
- Matrix A consists of elements [10, 12], positioned in two separate rows.
- Matrix B has elements [6, -2, 1, 6], all belonging to a single row.
The Matrix Product
The matrix product is the result of multiplying two matrices. This process might seem complex initially, but it's simplified by following systematic steps.
For matrices \(A\) and \(B\), we:
For matrices \(A\) and \(B\), we:
- Multiply each element of the row in Matrix A with each element of the column in Matrix B.
- Add these products to get a single element in the resulting matrix.
- Repeat this process for each row of A and column of B.
- The first element: \(10 \times 6 = 60\), and similarly, for the column elements, yielding the output row [60, -20, 10, 60].
- Using the second row: \(12 \times 6 = 72\), producing the row [72, -24, 12, 72].
Other exercises in this chapter
Problem 39
In Exercises 39-44, use a determinant to determine whether the points are collinear. \((3, -1)\), \((0, -3)\), \((12, 5)\)
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In Exercises 39-54, find the determinant of the matrix.Expand by cofactors on the row or column that appears to make the computations easiest. \(\left[ \begin{a
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Perform the sequence of row operations on the matrix. What did the operations accomplish? $$\left[\begin{array}{rrr}{1} & {2} & {3} \\ {2} & {-1} & {-4} \\ {3}
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In Exercises 39-54, find the determinant of the matrix.Expand by cofactors on the row or column that appears to make the computations easiest. \(\left[ \begin{a
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