Problem 39
Question
In Exercises \(31-40,\) factor the difference of two squares. $$16 x^{4}-81$$
Step-by-Step Solution
Verified Answer
The factored form of \(16 x^{4}-81\) is \((4x^2 + 9)(2x + 3) (2x - 3)\)
1Step 1: Identify terms
First it should be recognized that the equation \(16 x^{4}-81\) is a difference of squares. Notice how each term is a perfect square: \(16x^4\) is \((4x^2)^2\) and \(81\) is \(9^2\)
2Step 2: Apply the formula
Apply the formula for factoring difference of square \(a^2 - b^2 = (a+b)(a-b)\). Here, \(a = 4x^2\) and \(b = 9\). So, the factored form will be \((4x^2 + 9)(4x^2 - 9)\)
3Step 3: Factorise further if possible
Upon examination of the factors, \((4x^2 - 9)\) it can still be factored further. We can apply the formula again to get \( (2x + 3) (2x - 3)\) as the factors of \((4x^2 - 9)\)
4Step 4: Final factored form
The complete factored form of the original equation \(16 x^{4}-81\) will be \((4x^2 + 9)(2x + 3) (2x - 3)\)
Key Concepts
Factoring PolynomialsPerfect SquaresFactoring Techniques
Factoring Polynomials
Understanding how to factor polynomials is a key skill in algebra. Polynomials are expressions made up of terms, each consisting of a variable raised to an exponent, multiplied by a coefficient. Factoring is the process of breaking down a polynomial into simpler terms (or 'factors') that, when multiplied together, give the original polynomial.
To factor a polynomial, you often look for common factors among the terms or identify specific patterns, such as a difference of squares or perfect square trinomials. Once these patterns are recognized, you can apply suitable factoring formulas to simplify the polynomial. These steps make solving higher-level algebra problems more manageable.
To factor a polynomial, you often look for common factors among the terms or identify specific patterns, such as a difference of squares or perfect square trinomials. Once these patterns are recognized, you can apply suitable factoring formulas to simplify the polynomial. These steps make solving higher-level algebra problems more manageable.
Perfect Squares
Perfect squares are numbers or algebraic expressions that can be expressed as the square of an integer or a polynomial. For instance, 81 is a perfect square because it equals 9 squared (
9^2 = 81
). Similarly, in algebra,
16x^4
is a perfect square because it equals (
4x^2
) squared.
Recognizing perfect squares is crucial because they often allow us to simplify complex algebraic expressions. In the difference of squares formula, perfect squares are the backbone. Factoring expressions like
16x^4 - 81
involves identifying these perfect squares as coefficients or terms and transforming them into a product of binomials.
Factoring Techniques
There are various factoring techniques used in algebra to simplify polynomials:
- Greatest Common Factor (GCF): This involves finding the largest factor shared by all terms in the polynomial and factoring it out.
- Difference of Squares: This technique is used when a polynomial can be expressed as a difference between two perfect squares. For example, using the formula (a^2 - b^2 = (a + b)(a - b) ) simplifies the expression.
- Trinomials: Factoring these involves finding two binomials that multiply to form the original trinomial, using techniques such as "trial and error" or "grouping."
Other exercises in this chapter
Problem 39
Find each product. $$\left(1-y^{5}\right)\left(1+y^{5}\right)$$
View solution Problem 39
In Exercises \(39-48\), rationalize the denominator. $$\frac{1}{\sqrt{7}}$$
View solution Problem 39
Add or subtract as indicated. $$ \frac{x^{2}+3 x}{x^{2}+x-12}-\frac{x^{2}-12}{x^{2}+x-12} $$
View solution Problem 40
Simplify each exponential expression $$ \left(6 x^{4}\right)^{2} $$
View solution