Problem 39
Question
If \(A_{1} B_{1} C_{1}, A_{2} B_{2} C_{2}\) and \(A_{3} B_{3} C_{3}\) are three three-digit numbers, each of which is divisible by \(k\), then \(\Delta=\left|\begin{array}{ccc}A_{1} & B_{1} & C_{1} \\ A_{2} & B_{2} & C_{2} \\ A_{3} & B_{3} & C_{3}\end{array}\right|\) is (A) divisible by \(k\) (B) divisible by \(k^{2}\) (C) divisible by \(2 k\) (D) None of these
Step-by-Step Solution
Verified Answer
The determinant \( \Delta \) is divisible by \( k \) (Option A).
1Step 1: Understand Determinant Properties
The determinant \( \Delta \) of a 3x3 matrix is calculated using the rule of Sarrus or expansion by cofactors. Importantly, if all elements of any row (or column) in a matrix are divisible by a number \( k \), then the determinant of the matrix is also divisible by \( k \).
2Step 2: Verify Divisibility Condition
Since each of the numbers \( A_{1} B_{1} C_{1}, A_{2} B_{2} C_{2}, A_{3} B_{3} C_{3} \) is divisible by \( k \), this implies that each row in the matrix has elements divisible by \( k \). Therefore, the determinant \( \Delta \) will be divisible by \( k \).
3Step 3: Extend to Check for \( k^2 \)
For the determinant to be divisible by \( k^2 \), the matrix must have at least two rows or two columns with each element divisible by \( k \). In our case, though all rows are divisible by \( k \), this guarantees only that \( \Delta \) is divisible by \( k \), not \( k^2 \).
4Step 4: Conclusion: Reason Solution
Thus, since each row is divisible by \( k \) but not necessarily forming a condition for \( k^2 \), \( \Delta \) is only divisible by \( k \) and not necessarily by \( k^2 \) or \( 2k \). The correct option is (A): \( \Delta \) is divisible by \( k \).
Key Concepts
Divisibility in MathematicsRule of SarrusDeterminant Expansion by Cofactors
Divisibility in Mathematics
Divisibility is an essential concept in mathematics, referring to how one integer can be evenly divided by another without leaving a remainder. In this context, the notion of divisibility applies to the numbers forming the elements of a matrix, which are stated to be divisible by a common integer, denoted as \( k \).
Understanding divisibility plays a crucial role when working with determinants of matrices. If each element in any row or column of a matrix is divisible by \( k \), the determinant of such a matrix is also divisible by \( k \). This property is powerful because it allows logical deduction about the product and relationships between numbers just by inspecting the divisibility.
Understanding divisibility plays a crucial role when working with determinants of matrices. If each element in any row or column of a matrix is divisible by \( k \), the determinant of such a matrix is also divisible by \( k \). This property is powerful because it allows logical deduction about the product and relationships between numbers just by inspecting the divisibility.
- When a number \( a \) is divisible by another number \( b \), it can be expressed as a product of \( b \) and another integer. This forms the foundational principle behind mathematical operations involving divisibility.
- Knowing how to determine divisibility helps simplify complex mathematical computations and enhances problem-solving strategies.
Rule of Sarrus
The Rule of Sarrus is a simple method used to compute the determinant of a 3x3 matrix. Visualizing or understanding this rule involves writing out the matrix, duplicating the first two columns, and then calculating a series of products.
Specifically, for a 3x3 matrix \(\begin{pmatrix}A_1 & B_1 & C_1 \A_2 & B_2 & C_2 \A_3 & B_3 & C_3\end{pmatrix}\), the calculation step involves expanding the determinant along its diagonals:
The simplicity of the Rule of Sarrus makes it particularly useful in academic settings for quickly verifying or computing determinants in 3x3 matrices.
Specifically, for a 3x3 matrix \(\begin{pmatrix}A_1 & B_1 & C_1 \A_2 & B_2 & C_2 \A_3 & B_3 & C_3\end{pmatrix}\), the calculation step involves expanding the determinant along its diagonals:
- Take the products of the diagonals from top left to bottom right: \( A_1B_2C_3 + A_2B_3C_1 + A_3B_1C_2 \).
- Subtract the products of the diagonals from top right to bottom left: \( C_1B_2A_3 + C_2B_3A_1 + C_3B_1A_2 \).
The simplicity of the Rule of Sarrus makes it particularly useful in academic settings for quickly verifying or computing determinants in 3x3 matrices.
Determinant Expansion by Cofactors
Determinant expansion by cofactors, also known as Laplace expansion, is another method used to evaluate the determinant of matrices. It involves expanding the determinant across a specific row or column by focusing on each element and its corresponding minor.
The minor of an element in a matrix is the determinant of the smaller matrix that remains after removing the element's row and column. For an element \( a_{ij} \), the cofactor is calculated as:
The minor of an element in a matrix is the determinant of the smaller matrix that remains after removing the element's row and column. For an element \( a_{ij} \), the cofactor is calculated as:
- Cofactor = \((-1)^{i+j}\) times the minor of the element.
- The determinant \( \Delta \) is: \(A_1 \cdot \text{det}(\begin{vmatrix}B_2 & C_2 \B_3 & C_3\end{vmatrix}) - B_1 \cdot \text{det}(\begin{vmatrix}A_2 & C_2 \A_3 & C_3\end{vmatrix}) + C_1 \cdot \text{det}(\begin{vmatrix}A_2 & B_2 \A_3 & B_3\end{vmatrix})\)
Other exercises in this chapter
Problem 37
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